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sammii2u
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{6} \frac{ x2 }{ x^25x14 }\]

slaaibak
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{6} {x2 \over (x+2)(x 7)} dx\] now do the whole partial fractions thing

sammii2u
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ A }{ x7 } + \frac{ B }{ x+2 }\] then getting everything with the same denominator I get.. \[x2 = A(x+2) + B (x7)\] then plugging in the different zeros, x=7 and x=2 I solve for A and B. \[ A = \frac{ 5 }{ 9 }\] \[ B = \frac{ 4}{ 9 }\] Now the overall equation looks like: \[= \frac{ 5 }{ 9 } \int\limits_{}^{} \frac{ 1 }{ x7 } dx + \frac{ 4 }{ 9 } \int\limits_{}^{} \frac{ 1 }{ x+2 } dx\] now what..? am I even doing this right?

Goten77
 one year ago
Best ResponseYou've already chosen the best response.1yes... but in this form now its put into the ln form....

Goten77
 one year ago
Best ResponseYou've already chosen the best response.1you got it into the like ... i cant think of the name but its a form name.... but you did it right

sammii2u
 one year ago
Best ResponseYou've already chosen the best response.0right. so it would be \[= \left[ \frac{ 5\ln x7 }{ 9 } + \frac{ 4\ln x+2 }{ 9 } \right] _{1} ^{6}\] and then I evaluate it at x=6 and then subtract x=1 ?
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