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sammii2u
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{6} \frac{ x2 }{ x^25x14 }\]

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{6} {x2 \over (x+2)(x 7)} dx\] now do the whole partial fractions thing

sammii2u
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ A }{ x7 } + \frac{ B }{ x+2 }\] then getting everything with the same denominator I get.. \[x2 = A(x+2) + B (x7)\] then plugging in the different zeros, x=7 and x=2 I solve for A and B. \[ A = \frac{ 5 }{ 9 }\] \[ B = \frac{ 4}{ 9 }\] Now the overall equation looks like: \[= \frac{ 5 }{ 9 } \int\limits_{}^{} \frac{ 1 }{ x7 } dx + \frac{ 4 }{ 9 } \int\limits_{}^{} \frac{ 1 }{ x+2 } dx\] now what..? am I even doing this right?

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1yes... but in this form now its put into the ln form....

Goten77
 2 years ago
Best ResponseYou've already chosen the best response.1you got it into the like ... i cant think of the name but its a form name.... but you did it right

sammii2u
 2 years ago
Best ResponseYou've already chosen the best response.0right. so it would be \[= \left[ \frac{ 5\ln x7 }{ 9 } + \frac{ 4\ln x+2 }{ 9 } \right] _{1} ^{6}\] and then I evaluate it at x=6 and then subtract x=1 ?
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