## kandsbbf 2 years ago Find the real solutions of the equation by graphing. –8x3 – 17x2 + 7x = 0

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1. kandsbbf

@zepdrix

2. kandsbbf

0, –2.48, 0.35 –2.48 –2.48, 0.35 0, 2.48, –0.35

3. kandsbbf

@zepdrix

4. zepdrix

lol once is enough ^^ sorry I'm also helping someone else so it's hard to get away XD

5. kandsbbf

i didn't mean too lol my cp is slow.. thought u didn't get it

6. zepdrix

$\large -8x^3-17x^2+7x=0$See how EVERY term has an X in it? Let's start by factoring an X out of each term.$\large x(-8x^2-17x+7)=0$

7. zepdrix

I know they said to solve by GRAPHING, but I'm not exactly sure how you would go about doing that. Do they mean by using a calculator?

8. zepdrix

Graphing Calculator*?

9. zepdrix

Anyway doing it this way, if we apply the Zero Factor Property, we'll set each factor equal to 0 giving us,$\large x=0 \qquad \text{and}\qquad -8x^2-17x+7=0$

10. kandsbbf

maybe but i don't have one and their are actual graphs as the answersbut i just gave u the points.....

11. kandsbbf

okayy

12. zepdrix

From here, we can immediately cancel out two of the options, because it has to be one of the choices with x=0.

13. zepdrix

To find the other two roots, we can throw the quadratic part into the Quadratic Formula.$\large ax^2+bx+c=0 \qquad \rightarrow \qquad x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

14. zepdrix

$\large -8x^2-17x+7=0 \qquad \rightarrow \qquad x=\frac{17 \pm \sqrt{17^2-4(-8)(7)}}{2(-8)}$

15. zepdrix

Hopefully I plugged that in correctly. You can punch that into your calculator and hopefully get something that's listed :O