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Find the real solutions of the equation by graphing.
–8x3 – 17x2 + 7x = 0
 one year ago
 one year ago
Find the real solutions of the equation by graphing. –8x3 – 17x2 + 7x = 0
 one year ago
 one year ago

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kandsbbfBest ResponseYou've already chosen the best response.0
0, –2.48, 0.35 –2.48 –2.48, 0.35 0, 2.48, –0.35
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
lol once is enough ^^ sorry I'm also helping someone else so it's hard to get away XD
 one year ago

kandsbbfBest ResponseYou've already chosen the best response.0
i didn't mean too lol my cp is slow.. thought u didn't get it
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large 8x^317x^2+7x=0\]See how EVERY term has an X in it? Let's start by factoring an X out of each term.\[\large x(8x^217x+7)=0\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
I know they said to solve by GRAPHING, but I'm not exactly sure how you would go about doing that. Do they mean by using a calculator?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Anyway doing it this way, if we apply the Zero Factor Property, we'll set each factor equal to 0 giving us,\[\large x=0 \qquad \text{and}\qquad 8x^217x+7=0\]
 one year ago

kandsbbfBest ResponseYou've already chosen the best response.0
maybe but i don't have one and their are actual graphs as the answersbut i just gave u the points.....
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
From here, we can immediately cancel out two of the options, because it has to be one of the choices with x=0.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
To find the other two roots, we can throw the quadratic part into the Quadratic Formula.\[\large ax^2+bx+c=0 \qquad \rightarrow \qquad x=\frac{b \pm \sqrt{b^24ac}}{2a}\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large 8x^217x+7=0 \qquad \rightarrow \qquad x=\frac{17 \pm \sqrt{17^24(8)(7)}}{2(8)}\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Hopefully I plugged that in correctly. You can punch that into your calculator and hopefully get something that's listed :O
 one year ago
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