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 one year ago
Would someone please explain how to find the inflection point, y"=0, of the equation y"= 2[4x^315x^2+12x5]/(1x^2)^3 without a graphing calculator, please?
 one year ago
Would someone please explain how to find the inflection point, y"=0, of the equation y"= 2[4x^315x^2+12x5]/(1x^2)^3 without a graphing calculator, please?

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Shini
 one year ago
Best ResponseYou've already chosen the best response.0You already have the second derivative of the function so all you have to do is set the equation equal to 0 and then solve it. This will give you possible points of inflexion. Then you check the concavity of the point found by substituting the xvalues one higher then the xvalue you found and one lower. If you get a positive on one side and a negative on the other (doesn't matter which) you have found a point of inflexion.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0so is it like this? \[0=\frac{ 2\left[ 4\chi ^{3}15\chi ^{2}+12\chi 5 \right] }{ \left( 1\chi ^{2} \right)^{3} }\] But how do you start to solve it?

Shini
 one year ago
Best ResponseYou've already chosen the best response.0\[2[4x^3 15x^2 + 12x  5] = 0\] \[4x^3  15x^2 + 12x 5 = 0\] Then solve it from there

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0okay so I got: \[\chi \left( 4\chi ^{2}15\chi +12 \right)=5\] then I used the \[\frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\] and got 2.593070331 and 1.156929669. So do I put those numbers in the equation and test if they equal to 0?

Shini
 one year ago
Best ResponseYou've already chosen the best response.0There is also the value of x = 5. When you used the quadratic formulas to find the xvalues did you first separate the equation you got into: \[x = 5, 4x^2  15x + 12 = 5\] If not, try that. Were you given the original equation? If you were you substitute the values you got into that to get the possible points. If not don't worry. After that i usually check if the concavity changes by drawing: dw:1358129096454:dw and then repeat that for the rest of the x values you got. Sorry im not being a great deal of help anymore, if anything im confusing you more.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0the original equation was \[y =\frac{ 2\chi ^{2}4\chi +3 }{ 1\chi^{2} }\] and I got, When X=4 Y=0.21007 When X=6 Y= 0.05133

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0I still can't find the inflection point...

wio
 one year ago
Best ResponseYou've already chosen the best response.1Since you have an equation of degree 3, you need to find one of the roots first without the help of the quadratic equation.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0The there is another way to find it?

wio
 one year ago
Best ResponseYou've already chosen the best response.1Well you sort of have to guess.

wio
 one year ago
Best ResponseYou've already chosen the best response.1What is the equation we want to find the roots of exactly?

wio
 one year ago
Best ResponseYou've already chosen the best response.1Which function exactly is \(y''\). I see a lot of functions here.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0sorry about that... the first one equation in the question is y". I need to find the inflection point for y"=0

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0\[y"=\frac{ 2\left[ 4\chi ^{3}15\chi ^{2}+12\chi 5 \right] }{ \left( 1\chi ^{2} \right)^{3} }\] to be exact

wio
 one year ago
Best ResponseYou've already chosen the best response.1First thing to notice is that it's undefined at 1 and 1. Next thing to notice is that if the numerator (part on top) is 0, then the whole thing is 0. So we can ignore the denominator as long as we keep the first thing in mind.

wio
 one year ago
Best ResponseYou've already chosen the best response.1I'd start by just distributing that \(2\). There's not reason to have that factored out.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0oh okay... so it's only the \[2\left[ 4\chi ^{3}15\chi ^{2}+12\chi 5 \right]\] part I work with right?

wio
 one year ago
Best ResponseYou've already chosen the best response.1Yes. Ultimately we could multiply both sides by the denominator, and since the other size is 0, it would remain 0.

wio
 one year ago
Best ResponseYou've already chosen the best response.1I suppose you could get rid of that \(2\) with the same logic.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0\[4\chi^{3}15\chi ^{2}+12\chi 5\] is not factorable right?

wio
 one year ago
Best ResponseYou've already chosen the best response.1why is there a negative in front of the 4?

wio
 one year ago
Best ResponseYou've already chosen the best response.1yeah apparently it has a really nasty real root, and two imaginary roots.

wio
 one year ago
Best ResponseYou've already chosen the best response.1Did they give you y'' or y originally?

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0they gave me y originally and I was suppose to sketch the graph and find the inflection points without a graphing calculator

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0\[y=\frac{ 2\chi ^{2}4\chi +3 }{1\chi ^{2} }\]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Why were you opposed to just graphing it?

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0\[y'=\frac{ 4\chi ^{2}+10\chi 4 }{ \left( 1\chi ^{2} \right)^{2} }\]

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0you mean graph it with a calculator or by hand?

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0I have to label the inflection points and I can't find the y"=0 one

wio
 one year ago
Best ResponseYou've already chosen the best response.1The only way to really find it is to use the very erudite formula for 3rd degree polynomials, or use some other root finding method.... like Newton's method.

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0I don't know the other methods....

wio
 one year ago
Best ResponseYou've already chosen the best response.1http://en.wikipedia.org/wiki/Cubic_function#General_formula_of_roots The formula is HUGE

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure if i can memorize that....

wio
 one year ago
Best ResponseYou've already chosen the best response.1Seems like the only thing you could really do is to

wio
 one year ago
Best ResponseYou've already chosen the best response.1graph it and then plug in points really close to the inflection point

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0oh okay... so I can just guess the inflection point then, right?

wio
 one year ago
Best ResponseYou've already chosen the best response.1yeah. The problem seems kinda messed up.

wio
 one year ago
Best ResponseYou've already chosen the best response.1You can sort of see how the tangent line would intersect between 2 and 3

bluebird
 one year ago
Best ResponseYou've already chosen the best response.0Okay, thank you so much for your help!
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