Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Consider the curve defied by the equation y+cosy = x +1 for 0< or to equal y < or to equal 2pi

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
hmm
Okay, i considered it, now what?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

a.) Find dy/dx in terms of y. b.) Write an equation for each vertical tangent to the curve c.) Find d^2y/dx^2 in terms of y.
wouldn't be like this? |dw:1358131334593:dw|
sorry about my bad handwriting my hands are cold :P
no it wont be like that cause you with with respect to Y
ok so part a.) is just 1-siny=x'
they are looking for dy/dx or y' derivative wrt x BUT in terms of y
oh derp.... i did it wrong
lol
so was my technique correct? :D
|dw:1358139066897:dw|
k so y did it not show both images.... the 1st part wwas expanded 2nd part is simplified
wait how did u get that?
|dw:1358139147928:dw|
this program some times deletes my images or it doesnt appear for whatever reason
o.o
|dw:1358139329704:dw|
get it now?
how does x cancel from the other side?
|dw:1358139425312:dw|
when/where did i cancel a x?
from the right original side of equation (x+1)
btw here is graph of curve http://www.wolframalpha.com/input/?i=y+%2B+cos%28y%29+%3D+x%2B1+%2C+from+x%3D0+to+2pi%2C+from+y%3D0+to+2pi
oh ok i think i see why u canceled the variables on the right side of the equation :)
so 1/(1-siny) is part a.)?
the x didnt cancel the derivative of x+1 = just 1 since its wrt x
and yes thats your part a
ok how do i do part b.)
hmm
so vertical asymptotes is what makes the bottom of a fraction = 0
|dw:1358140100389:dw|
but we need the vertical asymptote so we needa find the x value so we put the equation in the form of x = #
so now we use the original equation and use that y value to solve for the x
how did u get 1=siny
|dw:1358140410824:dw|
so the vertical graph is x= (pi - 2)/ 2
i got 1=siny because it was 1st 1-siny= 0 i just moved it over
|dw:1358140649853:dw| sorry im bad at spelling
ok so part c is finding the 2nd derivative.... this will be fun
|dw:1358140714426:dw|
so part b.) is (pi -2)/2
|dw:1358140838951:dw|
|dw:1358140982676:dw|
this is basically the quotient rule + implicint differentation + production rule + chain rule THEN use that negative .... you dont have to simplify unless ur told to.. which i dont think u can
so cosy/(1-siny)^2 is the answer? :)
yee
k, ty ^^
can you help me with 1 more pls? :)
sure

Not the answer you are looking for?

Search for more explanations.

Ask your own question