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hmm

Okay, i considered it, now what?

wouldn't be like this? |dw:1358131334593:dw|

sorry about my bad handwriting my hands are cold :P

no it wont be like that cause you with with respect to Y

ok so part a.) is just 1-siny=x'

they are looking for dy/dx or y'
derivative wrt x BUT in terms of y

oh derp.... i did it wrong

lol

so was my technique correct? :D

|dw:1358139066897:dw|

k so y did it not show both images.... the 1st part wwas expanded 2nd part is simplified

wait how did u get that?

|dw:1358139147928:dw|

this program some times deletes my images or it doesnt appear for whatever reason

o.o

|dw:1358139329704:dw|

get it now?

how does x cancel from the other side?

|dw:1358139425312:dw|

when/where did i cancel a x?

from the right original side of equation (x+1)

oh ok i think i see why u canceled the variables on the right side of the equation :)

so 1/(1-siny) is part a.)?

the x didnt cancel
the derivative of x+1 = just 1 since its wrt x

and yes thats your part a

ok how do i do part b.)

hmm

so vertical asymptotes is what makes the bottom of a fraction = 0

|dw:1358140100389:dw|

so now we use the original equation and use that y value to solve for the x

how did u get 1=siny

|dw:1358140410824:dw|

so the vertical graph is
x= (pi - 2)/ 2

i got 1=siny because it was 1st
1-siny= 0
i just moved it over

|dw:1358140649853:dw| sorry im bad at spelling

ok so part c is finding the 2nd derivative.... this will be fun

|dw:1358140714426:dw|

so part b.) is (pi -2)/2

|dw:1358140838951:dw|

|dw:1358140982676:dw|

so cosy/(1-siny)^2 is the answer? :)

yee

k, ty ^^

can you help me with 1 more pls? :)

sure