anonymous
  • anonymous
Consider the curve defied by the equation y+cosy = x +1 for 0< or to equal y < or to equal 2pi
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@Goten77
Goten77
  • Goten77
hmm
anonymous
  • anonymous
Okay, i considered it, now what?

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anonymous
  • anonymous
a.) Find dy/dx in terms of y. b.) Write an equation for each vertical tangent to the curve c.) Find d^2y/dx^2 in terms of y.
anonymous
  • anonymous
wouldn't be like this? |dw:1358131334593:dw|
anonymous
  • anonymous
sorry about my bad handwriting my hands are cold :P
Goten77
  • Goten77
no it wont be like that cause you with with respect to Y
anonymous
  • anonymous
ok so part a.) is just 1-siny=x'
dumbcow
  • dumbcow
they are looking for dy/dx or y' derivative wrt x BUT in terms of y
Goten77
  • Goten77
oh derp.... i did it wrong
anonymous
  • anonymous
lol
anonymous
  • anonymous
so was my technique correct? :D
Goten77
  • Goten77
|dw:1358139066897:dw|
Goten77
  • Goten77
k so y did it not show both images.... the 1st part wwas expanded 2nd part is simplified
anonymous
  • anonymous
wait how did u get that?
Goten77
  • Goten77
|dw:1358139147928:dw|
Goten77
  • Goten77
this program some times deletes my images or it doesnt appear for whatever reason
anonymous
  • anonymous
o.o
Goten77
  • Goten77
|dw:1358139329704:dw|
Goten77
  • Goten77
get it now?
anonymous
  • anonymous
how does x cancel from the other side?
Goten77
  • Goten77
|dw:1358139425312:dw|
Goten77
  • Goten77
when/where did i cancel a x?
anonymous
  • anonymous
from the right original side of equation (x+1)
dumbcow
  • dumbcow
btw here is graph of curve http://www.wolframalpha.com/input/?i=y+%2B+cos%28y%29+%3D+x%2B1+%2C+from+x%3D0+to+2pi%2C+from+y%3D0+to+2pi
anonymous
  • anonymous
oh ok i think i see why u canceled the variables on the right side of the equation :)
anonymous
  • anonymous
so 1/(1-siny) is part a.)?
Goten77
  • Goten77
the x didnt cancel the derivative of x+1 = just 1 since its wrt x
Goten77
  • Goten77
and yes thats your part a
anonymous
  • anonymous
ok how do i do part b.)
Goten77
  • Goten77
hmm
Goten77
  • Goten77
so vertical asymptotes is what makes the bottom of a fraction = 0
Goten77
  • Goten77
|dw:1358140100389:dw|
Goten77
  • Goten77
but we need the vertical asymptote so we needa find the x value so we put the equation in the form of x = #
Goten77
  • Goten77
so now we use the original equation and use that y value to solve for the x
anonymous
  • anonymous
how did u get 1=siny
Goten77
  • Goten77
|dw:1358140410824:dw|
Goten77
  • Goten77
so the vertical graph is x= (pi - 2)/ 2
Goten77
  • Goten77
i got 1=siny because it was 1st 1-siny= 0 i just moved it over
Goten77
  • Goten77
|dw:1358140649853:dw| sorry im bad at spelling
Goten77
  • Goten77
ok so part c is finding the 2nd derivative.... this will be fun
Goten77
  • Goten77
|dw:1358140714426:dw|
anonymous
  • anonymous
so part b.) is (pi -2)/2
Goten77
  • Goten77
|dw:1358140838951:dw|
Goten77
  • Goten77
|dw:1358140982676:dw|
Goten77
  • Goten77
this is basically the quotient rule + implicint differentation + production rule + chain rule THEN use that negative .... you dont have to simplify unless ur told to.. which i dont think u can
anonymous
  • anonymous
so cosy/(1-siny)^2 is the answer? :)
Goten77
  • Goten77
yee
anonymous
  • anonymous
k, ty ^^
anonymous
  • anonymous
can you help me with 1 more pls? :)
Goten77
  • Goten77
sure

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