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lilfayfay

  • 2 years ago

Consider the curve defied by the equation y+cosy = x +1 for 0< or to equal y < or to equal 2pi

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  1. lilfayfay
    • 2 years ago
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    @Goten77

  2. Goten77
    • 2 years ago
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    hmm

  3. Umangiasd
    • 2 years ago
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    Okay, i considered it, now what?

  4. lilfayfay
    • 2 years ago
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    a.) Find dy/dx in terms of y. b.) Write an equation for each vertical tangent to the curve c.) Find d^2y/dx^2 in terms of y.

  5. lilfayfay
    • 2 years ago
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    wouldn't be like this? |dw:1358131334593:dw|

  6. lilfayfay
    • 2 years ago
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    sorry about my bad handwriting my hands are cold :P

  7. Goten77
    • 2 years ago
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    no it wont be like that cause you with with respect to Y

  8. lilfayfay
    • 2 years ago
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    ok so part a.) is just 1-siny=x'

  9. dumbcow
    • 2 years ago
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    they are looking for dy/dx or y' derivative wrt x BUT in terms of y

  10. Goten77
    • 2 years ago
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    oh derp.... i did it wrong

  11. lilfayfay
    • 2 years ago
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    lol

  12. lilfayfay
    • 2 years ago
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    so was my technique correct? :D

  13. Goten77
    • 2 years ago
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    |dw:1358139066897:dw|

  14. Goten77
    • 2 years ago
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    k so y did it not show both images.... the 1st part wwas expanded 2nd part is simplified

  15. lilfayfay
    • 2 years ago
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    wait how did u get that?

  16. Goten77
    • 2 years ago
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    |dw:1358139147928:dw|

  17. Goten77
    • 2 years ago
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    this program some times deletes my images or it doesnt appear for whatever reason

  18. lilfayfay
    • 2 years ago
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    o.o

  19. Goten77
    • 2 years ago
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    |dw:1358139329704:dw|

  20. Goten77
    • 2 years ago
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    get it now?

  21. lilfayfay
    • 2 years ago
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    how does x cancel from the other side?

  22. Goten77
    • 2 years ago
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    |dw:1358139425312:dw|

  23. Goten77
    • 2 years ago
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    when/where did i cancel a x?

  24. lilfayfay
    • 2 years ago
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    from the right original side of equation (x+1)

  25. dumbcow
    • 2 years ago
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    btw here is graph of curve http://www.wolframalpha.com/input/?i=y+%2B+cos%28y%29+%3D+x%2B1+%2C+from+x%3D0+to+2pi%2C+from+y%3D0+to+2pi

  26. lilfayfay
    • 2 years ago
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    oh ok i think i see why u canceled the variables on the right side of the equation :)

  27. lilfayfay
    • 2 years ago
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    so 1/(1-siny) is part a.)?

  28. Goten77
    • 2 years ago
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    the x didnt cancel the derivative of x+1 = just 1 since its wrt x

  29. Goten77
    • 2 years ago
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    and yes thats your part a

  30. lilfayfay
    • 2 years ago
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    ok how do i do part b.)

  31. Goten77
    • 2 years ago
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    hmm

  32. Goten77
    • 2 years ago
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    so vertical asymptotes is what makes the bottom of a fraction = 0

  33. Goten77
    • 2 years ago
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    |dw:1358140100389:dw|

  34. Goten77
    • 2 years ago
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    but we need the vertical asymptote so we needa find the x value so we put the equation in the form of x = #

  35. Goten77
    • 2 years ago
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    so now we use the original equation and use that y value to solve for the x

  36. lilfayfay
    • 2 years ago
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    how did u get 1=siny

  37. Goten77
    • 2 years ago
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    |dw:1358140410824:dw|

  38. Goten77
    • 2 years ago
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    so the vertical graph is x= (pi - 2)/ 2

  39. Goten77
    • 2 years ago
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    i got 1=siny because it was 1st 1-siny= 0 i just moved it over

  40. Goten77
    • 2 years ago
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    |dw:1358140649853:dw| sorry im bad at spelling

  41. Goten77
    • 2 years ago
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    ok so part c is finding the 2nd derivative.... this will be fun

  42. Goten77
    • 2 years ago
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    |dw:1358140714426:dw|

  43. lilfayfay
    • 2 years ago
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    so part b.) is (pi -2)/2

  44. Goten77
    • 2 years ago
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    |dw:1358140838951:dw|

  45. Goten77
    • 2 years ago
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    |dw:1358140982676:dw|

  46. Goten77
    • 2 years ago
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    this is basically the quotient rule + implicint differentation + production rule + chain rule THEN use that negative .... you dont have to simplify unless ur told to.. which i dont think u can

  47. lilfayfay
    • 2 years ago
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    so cosy/(1-siny)^2 is the answer? :)

  48. Goten77
    • 2 years ago
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    yee

  49. lilfayfay
    • 2 years ago
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    k, ty ^^

  50. lilfayfay
    • 2 years ago
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    can you help me with 1 more pls? :)

  51. Goten77
    • 2 years ago
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    sure

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