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What is the most misleading aspect of this graph that might lead one to the wrong conclusion?
connecting the data points with a line
scale of the yaxis
scale of the xaxis
spacing of the grid
(graph attached)
 one year ago
 one year ago
What is the most misleading aspect of this graph that might lead one to the wrong conclusion? connecting the data points with a line scale of the yaxis scale of the xaxis spacing of the grid (graph attached)
 one year ago
 one year ago

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JocelynCBest ResponseYou've already chosen the best response.0
I'm not sure what it means by "scale of the yaxis," but it's a little confusing that it starts off at .45 seconds instead of zero. So in that, I would select spacing of the grid. Don't take my word for it; it is between B and D.
 one year ago

bluesBest ResponseYou've already chosen the best response.1
It is quite confusing that the Y axis starts at some number other than zero. Without a couple dashes in it drawing attention to the discontinuity.
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
I personally would go with "connecting the data points with a line" and I'll explain why: Four discrete points are plotted which implies that measurements were only taken at those points. Adding lines to this graph implies that many more measurements were taken which contradicts the fact that only 4 measurements were taken.
 one year ago

erin512Best ResponseYou've already chosen the best response.0
thank you so much :) can you help me with one more i'm posting now?
 one year ago

bluesBest ResponseYou've already chosen the best response.1
I am not in love with connecting the data points either  but I thought they might be OK in this case because measurements are on the same spring. Presumably the spring stretches through all the intermediate points (i.e., the ones on the line) to reach the conformations it's in when it's measured.
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
I guess that could be true but the restoring force of a string is not linear:\[F=kx^2\]
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
Ooops...that should have been: \[F=\frac{1}{2}kx^2\] :)
 one year ago

erin512Best ResponseYou've already chosen the best response.0
so is that answer correct?
 one year ago

bluesBest ResponseYou've already chosen the best response.1
**Agrees** No professional person in their right mind would draw lines through those data points. But the labeling on the Y axis is also lousy. I guess the bottom line is there is much wrong with this picture and it's a subjective decision what's worst.
 one year ago

erin512Best ResponseYou've already chosen the best response.0
thank you :) i see now
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
One sec...let me explain that a bit better. dw:1358133711277:dw Drawing the lines in the first graph implies that if you take any point on the line that's where the displacement will be given a pendulum with that period. Now look at the second graph...which could just as easily be the true graph of some spring. Clearly using the graph with the lines is going to be misleading.
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
That's what I was trying to say :)
 one year ago

erin512Best ResponseYou've already chosen the best response.0
thanks so much, the graph was much easier to see it. i understand it much better now :)
 one year ago

Shane_BBest ResponseYou've already chosen the best response.2
At any rate erin, the lines are the problem
 one year ago
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