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anonymous
 3 years ago
What is the most misleading aspect of this graph that might lead one to the wrong conclusion?
connecting the data points with a line
scale of the yaxis
scale of the xaxis
spacing of the grid
(graph attached)
anonymous
 3 years ago
What is the most misleading aspect of this graph that might lead one to the wrong conclusion? connecting the data points with a line scale of the yaxis scale of the xaxis spacing of the grid (graph attached)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what it means by "scale of the yaxis," but it's a little confusing that it starts off at .45 seconds instead of zero. So in that, I would select spacing of the grid. Don't take my word for it; it is between B and D.

blues
 3 years ago
Best ResponseYou've already chosen the best response.1It is quite confusing that the Y axis starts at some number other than zero. Without a couple dashes in it drawing attention to the discontinuity.

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4I personally would go with "connecting the data points with a line" and I'll explain why: Four discrete points are plotted which implies that measurements were only taken at those points. Adding lines to this graph implies that many more measurements were taken which contradicts the fact that only 4 measurements were taken.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much :) can you help me with one more i'm posting now?

blues
 3 years ago
Best ResponseYou've already chosen the best response.1I am not in love with connecting the data points either  but I thought they might be OK in this case because measurements are on the same spring. Presumably the spring stretches through all the intermediate points (i.e., the ones on the line) to reach the conformations it's in when it's measured.

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4I guess that could be true but the restoring force of a string is not linear:\[F=kx^2\]

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4Ooops...that should have been: \[F=\frac{1}{2}kx^2\] :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so is that answer correct?

blues
 3 years ago
Best ResponseYou've already chosen the best response.1**Agrees** No professional person in their right mind would draw lines through those data points. But the labeling on the Y axis is also lousy. I guess the bottom line is there is much wrong with this picture and it's a subjective decision what's worst.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you :) i see now

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4One sec...let me explain that a bit better. dw:1358133711277:dw Drawing the lines in the first graph implies that if you take any point on the line that's where the displacement will be given a pendulum with that period. Now look at the second graph...which could just as easily be the true graph of some spring. Clearly using the graph with the lines is going to be misleading.

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4That's what I was trying to say :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks so much, the graph was much easier to see it. i understand it much better now :)

Shane_B
 3 years ago
Best ResponseYou've already chosen the best response.4At any rate erin, the lines are the problem
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