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geerky42
 4 years ago
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]
geerky42
 4 years ago
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this a system of equations?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0.... @Goten77 hard to read it... what are you doing?

Goten77
 4 years ago
Best ResponseYou've already chosen the best response.0think bout it..... not that hard to read..... but it wont ever end....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \large \begin{array}{rcl} (2x)^{\ln2}&=&(3y)^{\ln3} \\ \ln(2x)\ln(2)&=&\ln(3y)\ln(3) \\ \ln(2)\ln(2) +\ln(2) \ln(x) &=&\ln(3)\ln(y)+\ln(3)\ln(3) \\ \ln(2) \ln(x)  \ln(3)\ln(y) &=&\ln(3)\ln(3)\ln(2)\ln(2) \end{array} \] \[ \large \begin{array}{rcl} 3^{\ln x}&=&2^{\ln y} \\ \ln(3)\ln (x)&=&\ln(2)\ln (y) \\ \ln(3)\ln (x)  \ln(2)\ln (y) &=& 0 \end{array} \] \[ \begin{bmatrix} \ln(2)&\ln(3) \\ \ln(3)& \ln(2) \end{bmatrix} \begin{bmatrix} \ln(x) \\ \ln(y) \end{bmatrix} = \begin{bmatrix} \ln(3)\ln(3)\ln(2)\ln(2) \\ 0 \end{bmatrix} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you put it into a matrix, it's not as big a mess.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then at the very end raise it to the power of \(e\). It could be a singular matrix though?

Goten77
 4 years ago
Best ResponseYou've already chosen the best response.0strange its basically a property..... memorable
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