A community for students.
Here's the question you clicked on:
 0 viewing
geerky42
 3 years ago
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]
geerky42
 3 years ago
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is this a system of equations?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0.... @Goten77 hard to read it... what are you doing?

Goten77
 3 years ago
Best ResponseYou've already chosen the best response.0think bout it..... not that hard to read..... but it wont ever end....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \large \begin{array}{rcl} (2x)^{\ln2}&=&(3y)^{\ln3} \\ \ln(2x)\ln(2)&=&\ln(3y)\ln(3) \\ \ln(2)\ln(2) +\ln(2) \ln(x) &=&\ln(3)\ln(y)+\ln(3)\ln(3) \\ \ln(2) \ln(x)  \ln(3)\ln(y) &=&\ln(3)\ln(3)\ln(2)\ln(2) \end{array} \] \[ \large \begin{array}{rcl} 3^{\ln x}&=&2^{\ln y} \\ \ln(3)\ln (x)&=&\ln(2)\ln (y) \\ \ln(3)\ln (x)  \ln(2)\ln (y) &=& 0 \end{array} \] \[ \begin{bmatrix} \ln(2)&\ln(3) \\ \ln(3)& \ln(2) \end{bmatrix} \begin{bmatrix} \ln(x) \\ \ln(y) \end{bmatrix} = \begin{bmatrix} \ln(3)\ln(3)\ln(2)\ln(2) \\ 0 \end{bmatrix} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you put it into a matrix, it's not as big a mess.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then at the very end raise it to the power of \(e\). It could be a singular matrix though?

Goten77
 3 years ago
Best ResponseYou've already chosen the best response.0strange its basically a property..... memorable
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.