Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
geerky42
Group Title
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]
 one year ago
 one year ago
geerky42 Group Title
Find the value of x and y:\[ (2x)^{\ln 2} = (3y)^{\ln 3} \]\[ 3^{\ln x} = 2^{\ln y}\]
 one year ago
 one year ago

This Question is Closed

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
dw:1358145356088:dw
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
Is this a system of equations?
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
dw:1358145846151:dw
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
dw:1358147158729:dw
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
.... @Goten77 hard to read it... what are you doing?
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
dw:1358147202405:dw
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
think bout it..... not that hard to read..... but it wont ever end....
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
\[ \large \begin{array}{rcl} (2x)^{\ln2}&=&(3y)^{\ln3} \\ \ln(2x)\ln(2)&=&\ln(3y)\ln(3) \\ \ln(2)\ln(2) +\ln(2) \ln(x) &=&\ln(3)\ln(y)+\ln(3)\ln(3) \\ \ln(2) \ln(x)  \ln(3)\ln(y) &=&\ln(3)\ln(3)\ln(2)\ln(2) \end{array} \] \[ \large \begin{array}{rcl} 3^{\ln x}&=&2^{\ln y} \\ \ln(3)\ln (x)&=&\ln(2)\ln (y) \\ \ln(3)\ln (x)  \ln(2)\ln (y) &=& 0 \end{array} \] \[ \begin{bmatrix} \ln(2)&\ln(3) \\ \ln(3)& \ln(2) \end{bmatrix} \begin{bmatrix} \ln(x) \\ \ln(y) \end{bmatrix} = \begin{bmatrix} \ln(3)\ln(3)\ln(2)\ln(2) \\ 0 \end{bmatrix} \]
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
If you put it into a matrix, it's not as big a mess.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.2
then at the very end raise it to the power of \(e\). It could be a singular matrix though?
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
strange its basically a property..... memorable
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.