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ArkGoLuckyBest ResponseYou've already chosen the best response.0
dw:1358141893836:dw
 one year ago

wioBest ResponseYou've already chosen the best response.1
Oh wow, looks like a bit of algebra
 one year ago

blahblah_who_caresBest ResponseYou've already chosen the best response.0
Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?
 one year ago

ArkGoLuckyBest ResponseYou've already chosen the best response.0
There is a 90 degree angle where the 75 and 50 meet
 one year ago

wioBest ResponseYou've already chosen the best response.1
\[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]
 one year ago

wioBest ResponseYou've already chosen the best response.1
Do you see how I got this little nugget?
 one year ago

wioBest ResponseYou've already chosen the best response.1
Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]
 one year ago

wioBest ResponseYou've already chosen the best response.1
Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]
 one year ago

wioBest ResponseYou've already chosen the best response.1
Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]
 one year ago

ArkGoLuckyBest ResponseYou've already chosen the best response.0
nevermind I solved it. Thanks for trying
 one year ago

wioBest ResponseYou've already chosen the best response.1
What ever could have inspired you to solve it?
 one year ago

ArkGoLuckyBest ResponseYou've already chosen the best response.0
theta. I forgot that you could find an angle with two side lengths
 one year ago
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