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ArkGoLucky

Drawing attached

  • one year ago
  • one year ago

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  1. wio
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    =)

    • one year ago
  2. ArkGoLucky
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    |dw:1358141893836:dw|

    • one year ago
  3. ArkGoLucky
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    find x

    • one year ago
  4. wio
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    Oh wow, looks like a bit of algebra

    • one year ago
  5. blahblah_who_cares
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    Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?

    • one year ago
  6. ArkGoLucky
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    There is a 90 degree angle where the 75 and 50 meet

    • one year ago
  7. wio
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    |dw:1358142178357:dw|

    • one year ago
  8. wio
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    \[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]

    • one year ago
  9. wio
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    Do you see how I got this little nugget?

    • one year ago
  10. wio
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    Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]

    • one year ago
  11. wio
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    Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]

    • one year ago
  12. wio
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    Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]

    • one year ago
  13. ArkGoLucky
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    nevermind I solved it. Thanks for trying

    • one year ago
  14. wio
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    What ever could have inspired you to solve it?

    • one year ago
  15. ArkGoLucky
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    theta. I forgot that you could find an angle with two side lengths

    • one year ago
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