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ArkGoLucky
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358141893836:dw

wio
 one year ago
Best ResponseYou've already chosen the best response.1Oh wow, looks like a bit of algebra

blahblah_who_cares
 one year ago
Best ResponseYou've already chosen the best response.0Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?

ArkGoLucky
 one year ago
Best ResponseYou've already chosen the best response.0There is a 90 degree angle where the 75 and 50 meet

wio
 one year ago
Best ResponseYou've already chosen the best response.1\[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Do you see how I got this little nugget?

wio
 one year ago
Best ResponseYou've already chosen the best response.1Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]

ArkGoLucky
 one year ago
Best ResponseYou've already chosen the best response.0nevermind I solved it. Thanks for trying

wio
 one year ago
Best ResponseYou've already chosen the best response.1What ever could have inspired you to solve it?

ArkGoLucky
 one year ago
Best ResponseYou've already chosen the best response.0theta. I forgot that you could find an angle with two side lengths
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