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anonymous
 4 years ago
Drawing attached
anonymous
 4 years ago
Drawing attached

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358141893836:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh wow, looks like a bit of algebra

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is a 90 degree angle where the 75 and 50 meet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358142178357:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you see how I got this little nugget?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nevermind I solved it. Thanks for trying

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What ever could have inspired you to solve it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0theta. I forgot that you could find an angle with two side lengths
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