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ArkGoLucky
 3 years ago
Drawing attached
ArkGoLucky
 3 years ago
Drawing attached

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ArkGoLucky
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1358141893836:dw

wio
 3 years ago
Best ResponseYou've already chosen the best response.1Oh wow, looks like a bit of algebra

blahblah_who_cares
 3 years ago
Best ResponseYou've already chosen the best response.0Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?

ArkGoLucky
 3 years ago
Best ResponseYou've already chosen the best response.0There is a 90 degree angle where the 75 and 50 meet

wio
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]

wio
 3 years ago
Best ResponseYou've already chosen the best response.1Do you see how I got this little nugget?

wio
 3 years ago
Best ResponseYou've already chosen the best response.1Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]

wio
 3 years ago
Best ResponseYou've already chosen the best response.1Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]

wio
 3 years ago
Best ResponseYou've already chosen the best response.1Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]

ArkGoLucky
 3 years ago
Best ResponseYou've already chosen the best response.0nevermind I solved it. Thanks for trying

wio
 3 years ago
Best ResponseYou've already chosen the best response.1What ever could have inspired you to solve it?

ArkGoLucky
 3 years ago
Best ResponseYou've already chosen the best response.0theta. I forgot that you could find an angle with two side lengths
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