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ArkGoLucky

  • one year ago

Drawing attached

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  1. wio
    • one year ago
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    =)

  2. ArkGoLucky
    • one year ago
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    |dw:1358141893836:dw|

  3. ArkGoLucky
    • one year ago
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    find x

  4. wio
    • one year ago
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    Oh wow, looks like a bit of algebra

  5. blahblah_who_cares
    • one year ago
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    Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?

  6. ArkGoLucky
    • one year ago
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    There is a 90 degree angle where the 75 and 50 meet

  7. wio
    • one year ago
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    |dw:1358142178357:dw|

  8. wio
    • one year ago
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    \[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]

  9. wio
    • one year ago
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    Do you see how I got this little nugget?

  10. wio
    • one year ago
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    Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]

  11. wio
    • one year ago
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    Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]

  12. wio
    • one year ago
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    Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]

  13. ArkGoLucky
    • one year ago
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    nevermind I solved it. Thanks for trying

  14. wio
    • one year ago
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    What ever could have inspired you to solve it?

  15. ArkGoLucky
    • one year ago
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    theta. I forgot that you could find an angle with two side lengths

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