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Mathematics
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=)
|dw:1358141893836:dw|
find x

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Other answers:

Oh wow, looks like a bit of algebra
Nah. Pretty sure its geometry. ArkGoLucky are u sure u arent missing anything in the problem such as a 90 degrees angle?
There is a 90 degree angle where the 75 and 50 meet
|dw:1358142178357:dw|
\[ \sqrt{70^2+50^2}\cos(\theta) = 75 \]
Do you see how I got this little nugget?
Actually, even better would be: \[ \tan(\theta) = \frac{50}{57} \]
Then there is \[ \tan(\theta + 10.5^\circ) = \frac{50+x}{75} \]
Okay all together, without errors \[ \begin{array}{rcl} \tan(\theta) &=& \frac{50}{75} \\ \tan(\theta + 10.5^\circ) &=& \frac{50+x}{75} \end{array} \]
nevermind I solved it. Thanks for trying
What ever could have inspired you to solve it?
theta. I forgot that you could find an angle with two side lengths

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