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anonymous
 4 years ago
find the radius of the largest circle that can be inscribed in a triangle with sides 5 cm, 7 cm, 10 cm respectively
anonymous
 4 years ago
find the radius of the largest circle that can be inscribed in a triangle with sides 5 cm, 7 cm, 10 cm respectively

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let r be the radius of the largerst circle that can be drawn inside traingle then area of the triangle is given by the sum of the three triangles thus formed by joining the incentre with the respective vertices

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thus r = area of triangle /(semiperimeter of the triangle)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0area of triangle= sqrt(11*1*6*4)=sqrt (264) =16.248 semiperimetr= (5+7+10)=22/2=11 thus r =16.248/11 =1.477

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont get it? i also solved it but in a different solution but i wasn't sure of my answer so i asked the question but our solutions and answers did not match so will you explain to me your solution ? pleeaase?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0see first of all roughly draw the incircle touching all the sides of the triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now take any one side and see it forms a triangle with the incentre as one of the vertex and the side of the triangle as the base

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358145014344:dw is the drawing supposed to be like this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if i assume the lengths of the sides to be a,b,c (and say a=5,b=7,c=10) and r be the incenter of the triangle ,. then area of triangle is given by area =sqrt(s*sa)*(sb)*(sc)) also when the triangle is subdivided into three tr

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358145137085:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A = sqrt(11(115)(117)(1110) right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also if r is the incentre then area=1/2 *r *5 + 1/2 *r *7 + 1/2 *r *10 =r *(5+7+10) /2 =r*22/2=11 *r hence 11r =sqrt(11(115)(117)(1110) or r = (sqrt(11(115)(117)(1110))/11

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0u can correct or check the calcualtion
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