\[\frac{ 2 }{ 9 } \]
of the people on a restaurant are adults. if there are 95 more children than adults, how many children are there in the restaurant
95 more children, so 7/9 of the people the children portion is 95.
Knowing that:
(7/9 - 2/9)*x = 95
5/9 * x = 95
So the total people would be:
95 * 9/5 = 171
Next we do:
2/9 *171 = 38
To get the adult count.
And this for the children count:
7/9 *171 = 133
\[9/9\]would be everyone in the restaurant.
Given to us is 2/9 is adults.
So that leaves? 9 - 2 = 7
7/9 Must be children.
Do you understand so far before I continue?
For each "9" people there are 5 more then adults.
So:
Let's use a variable now which will be "P" for people.
5/9 * P = 95
Now let's flip over 95 to the other side.
95 * 9/5 (it becomes 9/5 due to a rule) = P
95 * 9/5 = 171
Correct?
Now we know the total amount of people. Do you understand?
Okay.
So:
Since we now know the total:
Next we do:
2/9(Adults) *171 = 38 Adults
And this for the children count:
7/9(Children) *171 = 133 Children
So there for 133 Children are in the restaurant.
Haha :) I'm happy you didn't die.
There is another method you could do:
Take 95 / 5(Since we know there is 5 more children then adults.) And you get 19.
So you need 19 sets of 2 adults and 7 children to equal the total.
19 x 2 = 38 Adults
19 x 7 = 133 Children
Check your work:
133 - 38 = 95
See?