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dydlf
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heeelp! in how many ways can 2 elephants, 1 monkey and 3 ants sit in a row if no 2 animals of the same kind are together? assume 2 animals of the same kind are distinguishable. answer is said to be 120. O:
 one year ago
 one year ago
dydlf Group Title
heeelp! in how many ways can 2 elephants, 1 monkey and 3 ants sit in a row if no 2 animals of the same kind are together? assume 2 animals of the same kind are distinguishable. answer is said to be 120. O:
 one year ago
 one year ago

This Question is Closed

cammyabbo Group TitleBest ResponseYou've already chosen the best response.0
this is a permutations questions
 one year ago

cammyabbo Group TitleBest ResponseYou've already chosen the best response.0
you have 6 animals, 2 are the same and 3 are the same
 one year ago

dydlf Group TitleBest ResponseYou've already chosen the best response.0
they're considered distinguishableO: so not really the "same"
 one year ago

cammyabbo Group TitleBest ResponseYou've already chosen the best response.0
the answer would be 720 if that was the case
 one year ago

cammyabbo Group TitleBest ResponseYou've already chosen the best response.0
the answer should be 60, your equation should be 6!/(3!)(2!)
 one year ago

dydlf Group TitleBest ResponseYou've already chosen the best response.0
the book says 120 :(
 one year ago

cammyabbo Group TitleBest ResponseYou've already chosen the best response.0
is it DISTINGUISHABLE, or INdistinguishable
 one year ago

dydlf Group TitleBest ResponseYou've already chosen the best response.0
distinguishiable O:
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.1
first arrange the elephants and the ants in the way such that the elephants are in betweeb the ants as such A1 E1 A2 E2 A3 which can be done in 3!*2! ways now the monkey can be paired with any of the five animals in 5*2! ways =10 e.g A1 E1M1 A2 E2 A3 & A1 M1E1 A2 E2 A3 (here paired with E1) another one paired with A3 A1 E1 A2 E2 A3 M1 & A1 E1 A2 E2 M1A3 in this way the number of ways is 3!*2!*(10)=120 (as no two animals of same kind are together)
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.1
@dydlf is it wrong ...
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.0
possible no. of arrangements of 3 ants is : 1) a_a_a_ > 3! * 3! 2) a__a_a >(3! * 3!)  ( 3! * 2!) 3) a_a__a > (3! * 3!)  (31 * 2!) 4) _a_a_a > 3! *3! so final answer= 36 +24 +36+ 24 = 120
 one year ago
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