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anonymous
 4 years ago
heeelp! in how many ways can 2 elephants, 1 monkey and 3 ants sit in a row if no 2 animals of the same kind are together? assume 2 animals of the same kind are distinguishable. answer is said to be 120. O:
anonymous
 4 years ago
heeelp! in how many ways can 2 elephants, 1 monkey and 3 ants sit in a row if no 2 animals of the same kind are together? assume 2 animals of the same kind are distinguishable. answer is said to be 120. O:

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is a permutations questions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have 6 animals, 2 are the same and 3 are the same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they're considered distinguishableO: so not really the "same"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer would be 720 if that was the case

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer should be 60, your equation should be 6!/(3!)(2!)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it DISTINGUISHABLE, or INdistinguishable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first arrange the elephants and the ants in the way such that the elephants are in betweeb the ants as such A1 E1 A2 E2 A3 which can be done in 3!*2! ways now the monkey can be paired with any of the five animals in 5*2! ways =10 e.g A1 E1M1 A2 E2 A3 & A1 M1E1 A2 E2 A3 (here paired with E1) another one paired with A3 A1 E1 A2 E2 A3 M1 & A1 E1 A2 E2 M1A3 in this way the number of ways is 3!*2!*(10)=120 (as no two animals of same kind are together)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@dydlf is it wrong ...

shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.0possible no. of arrangements of 3 ants is : 1) a_a_a_ > 3! * 3! 2) a__a_a >(3! * 3!)  ( 3! * 2!) 3) a_a__a > (3! * 3!)  (31 * 2!) 4) _a_a_a > 3! *3! so final answer= 36 +24 +36+ 24 = 120
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