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anonymous
 4 years ago
y=b+a(t1)/(t+1);solve for t
anonymous
 4 years ago
y=b+a(t1)/(t+1);solve for t

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0subtract b from both sides\[yb=a\frac{t1}{t+1}\]divide both sides by a\[\frac{yb}{a}=\frac{t1}{t+1}\]multiply by t+1\[(\frac{yb}{a})(1+t)=t1\]use Distributive Property for left side\[(\frac{yb}{a})+(\frac{yb}{a})t=t1\]isolate the terms including t\[(\frac{yb}{a})tt=1(\frac{yb}{a})\]factor out t from left side\[t((\frac{yb}{a})1)=1(\frac{yb}{a})\]finally u have\[t=\frac{1(\frac{yb}{a})}{(\frac{yb}{a})1}\]
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