Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
jayda
Group Title
Without graphing, tell how many xintercepts y= 2x2 + 4x + 2 has.
 one year ago
 one year ago
jayda Group Title
Without graphing, tell how many xintercepts y= 2x2 + 4x + 2 has.
 one year ago
 one year ago

This Question is Closed

abb0t Group TitleBest ResponseYou've already chosen the best response.0
one, and they are teh same number.
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.0
well, two, but they are the the same number is what I mean.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
We can let \(y = 0\) and then solve \(2x^2 + 4x + 2 = 0\).
 one year ago

tanvirms Group TitleBest ResponseYou've already chosen the best response.0
if you solve the equation, u end up with (x+1)^2, so, the the function will be satisfied by 1, but twice....so it has one x intercept
 one year ago

blurbendy Group TitleBest ResponseYou've already chosen the best response.0
Two intercepts. 2x^2 + 4 x + 2. The leading exponential power tells you how many intercepts will be present (in this case, it is 2) For example, if it were 3x^3 it would have 3 x intercepts
 one year ago

tanvirms Group TitleBest ResponseYou've already chosen the best response.0
sorry, its 1
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.0
@tanvirms how did you get 1?
 one year ago

tanvirms Group TitleBest ResponseYou've already chosen the best response.0
2x^2+2x+1+0 or, x^2_2x+1=0 or, (x+1)^2=0 or, X+1=0 or, x= 1
 one year ago

tanvirms Group TitleBest ResponseYou've already chosen the best response.0
sorry, 2x^2+4x+2=0 *
 one year ago

jayda Group TitleBest ResponseYou've already chosen the best response.0
thanks guys !
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.