jayda
Without graphing, tell how many x-intercepts y= 2x2 + 4x + 2 has.
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abb0t
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one, and they are teh same number.
abb0t
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well, two, but they are the the same number is what I mean.
ParthKohli
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We can let \(y = 0\) and then solve \(2x^2 + 4x + 2 = 0\).
tanvirms
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if you solve the equation, u end up with (x+1)^2, so, the the function will be satisfied by 1, but twice....so it has one x intercept
blurbendy
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Two intercepts. 2x^2 + 4 x + 2. The leading exponential power tells you how many intercepts will be present (in this case, it is 2) For example, if it were 3x^3 it would have 3 x intercepts
tanvirms
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sorry, its -1
abb0t
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@tanvirms how did you get -1?
tanvirms
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2x^2+2x+1+0
or, x^2_2x+1=0
or, (x+1)^2=0
or, X+1=0
or, x= -1
tanvirms
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sorry, 2x^2+4x+2=0 *
jayda
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thanks guys !