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abb0t
 one year ago
Best ResponseYou've already chosen the best response.0one, and they are teh same number.

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0well, two, but they are the the same number is what I mean.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0We can let \(y = 0\) and then solve \(2x^2 + 4x + 2 = 0\).

tanvirms
 one year ago
Best ResponseYou've already chosen the best response.0if you solve the equation, u end up with (x+1)^2, so, the the function will be satisfied by 1, but twice....so it has one x intercept

blurbendy
 one year ago
Best ResponseYou've already chosen the best response.0Two intercepts. 2x^2 + 4 x + 2. The leading exponential power tells you how many intercepts will be present (in this case, it is 2) For example, if it were 3x^3 it would have 3 x intercepts

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0@tanvirms how did you get 1?

tanvirms
 one year ago
Best ResponseYou've already chosen the best response.02x^2+2x+1+0 or, x^2_2x+1=0 or, (x+1)^2=0 or, X+1=0 or, x= 1
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