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abb0tBest ResponseYou've already chosen the best response.0
one, and they are teh same number.
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
well, two, but they are the the same number is what I mean.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
We can let \(y = 0\) and then solve \(2x^2 + 4x + 2 = 0\).
 one year ago

tanvirmsBest ResponseYou've already chosen the best response.0
if you solve the equation, u end up with (x+1)^2, so, the the function will be satisfied by 1, but twice....so it has one x intercept
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Two intercepts. 2x^2 + 4 x + 2. The leading exponential power tells you how many intercepts will be present (in this case, it is 2) For example, if it were 3x^3 it would have 3 x intercepts
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
@tanvirms how did you get 1?
 one year ago

tanvirmsBest ResponseYou've already chosen the best response.0
2x^2+2x+1+0 or, x^2_2x+1=0 or, (x+1)^2=0 or, X+1=0 or, x= 1
 one year ago
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