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poopsiedoodle

I don't really need help here, I'm just using this as a workspace for my test on quadratic equations. :P

  • one year ago
  • one year ago

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  1. poopsiedoodle
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    \[\Large x= \frac {-b \pm sqrt{b^{2}-4ac}{2a}\]

    • one year ago
  2. Aeon_Valentine00
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    HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

    • one year ago
  3. poopsiedoodle
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    stahp it

    • one year ago
  4. poopsiedoodle
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    @saifoo.khan I can't see my equation! D:

    • one year ago
  5. saifoo.khan
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    Wear some glasses maybe?

    • one year ago
  6. saifoo.khan
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    Don't forget to close a curly bracket. \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]

    • one year ago
  7. poopsiedoodle
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    No, like, it's grey, and not loading. I have the thing that says Processing math: 100%

    • one year ago
  8. poopsiedoodle
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    and it WON'T GO AWAY. >:(

    • one year ago
  9. poopsiedoodle
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    Maybe I'm using a bad proxy.

    • one year ago
  10. saifoo.khan
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    Maybe.

    • one year ago
  11. poopsiedoodle
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    \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]

    • one year ago
  12. poopsiedoodle
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    I can see it! It was just a bad proxy :P

    • one year ago
  13. poopsiedoodle
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    \[\Large x=\frac{ -10\pm \sqrt{10^{2-4(-20)}} }{ 2 }\]

    • one year ago
  14. poopsiedoodle
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    \[\Large x=\frac{ -10\pm \sqrt{2} -4(-20) }{ 2 }\]*

    • one year ago
  15. poopsiedoodle
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    GAH

    • one year ago
  16. poopsiedoodle
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    \[\Large x=\frac{ -10\pm \sqrt{2-80} }{ 2 }\]

    • one year ago
  17. poopsiedoodle
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    \[\Large x=\frac{ -10\pm \sqrt{-78} }{ 2 }\]

    • one year ago
  18. poopsiedoodle
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    \[\Large x=-5 \pm \sqrt{-39}\] @hba did I do this step right?

    • one year ago
  19. hba
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    Where are we ?

    • one year ago
  20. poopsiedoodle
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    I think I did this equation completely wrong. That's not one of the answer choices ._.

    • one year ago
  21. hba
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    You always do it wrong,give me a question let me show how it goes.

    • one year ago
  22. poopsiedoodle
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    \[\Huge x ^{2} = 10x -20\]

    • one year ago
  23. hba
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    http://sphotos-b.ak.fbcdn.net/hphotos-ak-ash3/19285_580947011919656_1245239224_n.jpg

    • one year ago
  24. poopsiedoodle
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    Helpful. :P

    • one year ago
  25. hba
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    So, x^2-10x+20=0 Here a=1 b=-10 c=20 in quad formula. @poopsiedoodle Do it for me.

    • one year ago
  26. poopsiedoodle
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    \[\Large x=\frac{ -10\pm \sqrt{10 - (4(20))} }{ 2 }\]

    • one year ago
  27. poopsiedoodle
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    since, a = 1, I just took out a.

    • one year ago
  28. hba
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    @poopsiedoodle Write it again correctly You have done a mistake

    • one year ago
  29. poopsiedoodle
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    oops. 10^2* \[x=\frac{ -10 \pm \sqrt{10^{2}-4(20)} }{ 2 }\]

    • one year ago
  30. hba
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    One more mistake

    • one year ago
  31. poopsiedoodle
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    I'm not seeing it o-o

    • one year ago
  32. poopsiedoodle
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    The only thing I can think of is leaving out the 1, which isn't necessary to include since it doesn't effect the outcome of the problem.

    • one year ago
  33. hba
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    Try seeing it Mistake of sign

    • one year ago
  34. poopsiedoodle
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    OH

    • one year ago
  35. poopsiedoodle
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    \[x=\frac{ 10\sqrt{-10 - 4(20)} }{ 2 }\]

    • one year ago
  36. hba
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    Where is the +- sign ?

    • one year ago
  37. hba
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    Where did the square go

    • one year ago
  38. hba
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    The underroot is on the whole exp.

    • one year ago
  39. poopsiedoodle
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    omg I keep forgetting things

    • one year ago
  40. hba
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    It is 4(a)(b) not only 4(c)

    • one year ago
  41. hba
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    4(a)(c) *

    • one year ago
  42. poopsiedoodle
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    \[\huge x=\frac{ 10\pm \sqrt{-10^{2} - 4(1)(20)} }{ 2(1) }\]

    • one year ago
  43. hba
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    Continue.

    • one year ago
  44. hba
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    @poopsiedoodle

    • one year ago
  45. poopsiedoodle
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    \[\huge x=\frac{ 10\pm \sqrt{100 - 4(20)} }{ 2 }\]

    • one year ago
  46. poopsiedoodle
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    \[\huge x=\frac{ 10\pm \sqrt{100 - 80} }{ 2 }\]

    • one year ago
  47. poopsiedoodle
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    \[\huge x=\frac{ 10\pm \sqrt{20} }{ 2 }\]

    • one year ago
  48. hba
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    Yes :)

    • one year ago
  49. poopsiedoodle
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    \[\huge x=\frac{ 10\pm 4\sqrt{5} }{ 2 }\]

    • one year ago
  50. hba
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    ^ this is wrong.

    • one year ago
  51. poopsiedoodle
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    \[\huge x={ 5\pm \sqrt{4*5} }\] *

    • one year ago
  52. hba
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    When you take sqrt{20}=sqrt{5*4]=2sqrt{5} \[\huge x=\frac{ 10\pm 2\sqrt{5} }{ 2 }\] Now continue....

    • one year ago
  53. poopsiedoodle
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    \[\Huge x=10\pm \sqrt{5}\]

    • one year ago
  54. poopsiedoodle
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    I'd nominate you for helper of the month, if that was a thing.

    • one year ago
  55. poopsiedoodle
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    now time for another one! :D

    • one year ago
  56. poopsiedoodle
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    \[\Huge 0 = -3x ^{2} 33x+24\]

    • one year ago
  57. hba
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    No YOU ARE WRONG!! We are taking 2 common through out.

    • one year ago
  58. poopsiedoodle
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    wat

    • one year ago
  59. hba
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    \[\huge x=\frac{ 2(5\pm \sqrt{5}) }{ 2 }\]

    • one year ago
  60. poopsiedoodle
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    so yeah, \[\Huge x= 5 \pm \sqrt{5}\]

    • one year ago
  61. hba
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    hmm

    • one year ago
  62. poopsiedoodle
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    Now then, on to \[\Huge 0 = -3x^{2} + 33x +24

    • one year ago
  63. poopsiedoodle
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    oops

    • one year ago
  64. poopsiedoodle
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    \[\Huge 0 = -3x^{2} + 33x +24\]

    • one year ago
  65. hba
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    Here a=-3 b=33 c=24 in quad formula

    • one year ago
  66. poopsiedoodle
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    \[\huge x = \frac{ 3\pm \sqrt{-3^{2} - 4(-3)(24)} }{ 2(-3) }\]

    • one year ago
  67. hba
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    b=33 not 3

    • one year ago
  68. poopsiedoodle
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    erpsh.

    • one year ago
  69. poopsiedoodle
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    \[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 4(-3)(24)} }{ 2(-3) }\]

    • one year ago
  70. hba
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    Sign error

    • one year ago
  71. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} - 4(-3)(24)} }{ 2(-3) }\]

    • one year ago
  72. hba
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    Continue.

    • one year ago
  73. poopsiedoodle
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    \[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 288} }{ 2(-3) }\]

    • one year ago
  74. hba
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    The sign :/

    • one year ago
  75. poopsiedoodle
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    +288?

    • one year ago
  76. poopsiedoodle
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    I was kinda confused on that part.

    • one year ago
  77. hba
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    What about -33 also

    • one year ago
  78. hba
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    Yes +288 because (-) (-)=+

    • one year ago
  79. poopsiedoodle
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    oops.

    • one year ago
  80. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ 2(-3) }\]

    • one year ago
  81. hba
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    YEs continue

    • one year ago
  82. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ -6 }\]

    • one year ago
  83. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{1089 + 288} }{ -6 }\]

    • one year ago
  84. poopsiedoodle
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    das a big ol' numba doe.

    • one year ago
  85. hba
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    Continue.

    • one year ago
  86. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{1377} }{ -6 }\]

    • one year ago
  87. poopsiedoodle
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    I think the 1377 breaks down into 17 and 81 here.

    • one year ago
  88. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm \sqrt{17*81} }{ -6 }\]

    • one year ago
  89. poopsiedoodle
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    \[\Huge x = \frac{ -33\pm 9\sqrt{17} }{ -6 }\]

    • one year ago
  90. poopsiedoodle
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    well, I gotta go home now. I may or may not be back soon.

    • one year ago
  91. hba
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    Now take 3 common

    • one year ago
  92. poopsiedoodle
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    \[\Huge x = \frac{ -11\pm 3\sqrt{17} }{ -2 }\]

    • one year ago
  93. hba
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    Yeah right :) You can also take -1 common throughout. But,this answer is also correct

    • one year ago
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