poopsiedoodle
  • poopsiedoodle
I don't really need help here, I'm just using this as a workspace for my test on quadratic equations. :P
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
poopsiedoodle
  • poopsiedoodle
\[\Large x= \frac {-b \pm sqrt{b^{2}-4ac}{2a}\]
anonymous
  • anonymous
HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
poopsiedoodle
  • poopsiedoodle
stahp it

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poopsiedoodle
  • poopsiedoodle
@saifoo.khan I can't see my equation! D:
saifoo.khan
  • saifoo.khan
Wear some glasses maybe?
saifoo.khan
  • saifoo.khan
Don't forget to close a curly bracket. \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]
poopsiedoodle
  • poopsiedoodle
No, like, it's grey, and not loading. I have the thing that says Processing math: 100%
poopsiedoodle
  • poopsiedoodle
and it WON'T GO AWAY. >:(
poopsiedoodle
  • poopsiedoodle
Maybe I'm using a bad proxy.
saifoo.khan
  • saifoo.khan
Maybe.
poopsiedoodle
  • poopsiedoodle
\[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]
poopsiedoodle
  • poopsiedoodle
I can see it! It was just a bad proxy :P
poopsiedoodle
  • poopsiedoodle
\[\Large x=\frac{ -10\pm \sqrt{10^{2-4(-20)}} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
\[\Large x=\frac{ -10\pm \sqrt{2} -4(-20) }{ 2 }\]*
poopsiedoodle
  • poopsiedoodle
GAH
poopsiedoodle
  • poopsiedoodle
\[\Large x=\frac{ -10\pm \sqrt{2-80} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
\[\Large x=\frac{ -10\pm \sqrt{-78} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
\[\Large x=-5 \pm \sqrt{-39}\] @hba did I do this step right?
hba
  • hba
Where are we ?
poopsiedoodle
  • poopsiedoodle
I think I did this equation completely wrong. That's not one of the answer choices ._.
hba
  • hba
You always do it wrong,give me a question let me show how it goes.
poopsiedoodle
  • poopsiedoodle
\[\Huge x ^{2} = 10x -20\]
hba
  • hba
http://sphotos-b.ak.fbcdn.net/hphotos-ak-ash3/19285_580947011919656_1245239224_n.jpg
poopsiedoodle
  • poopsiedoodle
Helpful. :P
hba
  • hba
So, x^2-10x+20=0 Here a=1 b=-10 c=20 in quad formula. @poopsiedoodle Do it for me.
poopsiedoodle
  • poopsiedoodle
\[\Large x=\frac{ -10\pm \sqrt{10 - (4(20))} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
since, a = 1, I just took out a.
hba
  • hba
@poopsiedoodle Write it again correctly You have done a mistake
poopsiedoodle
  • poopsiedoodle
oops. 10^2* \[x=\frac{ -10 \pm \sqrt{10^{2}-4(20)} }{ 2 }\]
hba
  • hba
One more mistake
poopsiedoodle
  • poopsiedoodle
I'm not seeing it o-o
poopsiedoodle
  • poopsiedoodle
The only thing I can think of is leaving out the 1, which isn't necessary to include since it doesn't effect the outcome of the problem.
hba
  • hba
Try seeing it Mistake of sign
poopsiedoodle
  • poopsiedoodle
OH
poopsiedoodle
  • poopsiedoodle
\[x=\frac{ 10\sqrt{-10 - 4(20)} }{ 2 }\]
hba
  • hba
Where is the +- sign ?
hba
  • hba
Where did the square go
hba
  • hba
The underroot is on the whole exp.
poopsiedoodle
  • poopsiedoodle
omg I keep forgetting things
hba
  • hba
It is 4(a)(b) not only 4(c)
hba
  • hba
4(a)(c) *
poopsiedoodle
  • poopsiedoodle
\[\huge x=\frac{ 10\pm \sqrt{-10^{2} - 4(1)(20)} }{ 2(1) }\]
hba
  • hba
Continue.
hba
  • hba
@poopsiedoodle
poopsiedoodle
  • poopsiedoodle
\[\huge x=\frac{ 10\pm \sqrt{100 - 4(20)} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
\[\huge x=\frac{ 10\pm \sqrt{100 - 80} }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
\[\huge x=\frac{ 10\pm \sqrt{20} }{ 2 }\]
hba
  • hba
Yes :)
poopsiedoodle
  • poopsiedoodle
\[\huge x=\frac{ 10\pm 4\sqrt{5} }{ 2 }\]
hba
  • hba
^ this is wrong.
poopsiedoodle
  • poopsiedoodle
\[\huge x={ 5\pm \sqrt{4*5} }\] *
hba
  • hba
When you take sqrt{20}=sqrt{5*4]=2sqrt{5} \[\huge x=\frac{ 10\pm 2\sqrt{5} }{ 2 }\] Now continue....
poopsiedoodle
  • poopsiedoodle
\[\Huge x=10\pm \sqrt{5}\]
poopsiedoodle
  • poopsiedoodle
I'd nominate you for helper of the month, if that was a thing.
poopsiedoodle
  • poopsiedoodle
now time for another one! :D
poopsiedoodle
  • poopsiedoodle
\[\Huge 0 = -3x ^{2} 33x+24\]
hba
  • hba
No YOU ARE WRONG!! We are taking 2 common through out.
poopsiedoodle
  • poopsiedoodle
wat
hba
  • hba
\[\huge x=\frac{ 2(5\pm \sqrt{5}) }{ 2 }\]
poopsiedoodle
  • poopsiedoodle
so yeah, \[\Huge x= 5 \pm \sqrt{5}\]
hba
  • hba
hmm
poopsiedoodle
  • poopsiedoodle
Now then, on to \[\Huge 0 = -3x^{2} + 33x +24
poopsiedoodle
  • poopsiedoodle
oops
poopsiedoodle
  • poopsiedoodle
\[\Huge 0 = -3x^{2} + 33x +24\]
hba
  • hba
Here a=-3 b=33 c=24 in quad formula
poopsiedoodle
  • poopsiedoodle
\[\huge x = \frac{ 3\pm \sqrt{-3^{2} - 4(-3)(24)} }{ 2(-3) }\]
hba
  • hba
b=33 not 3
poopsiedoodle
  • poopsiedoodle
erpsh.
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 4(-3)(24)} }{ 2(-3) }\]
hba
  • hba
Sign error
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} - 4(-3)(24)} }{ 2(-3) }\]
hba
  • hba
Continue.
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 288} }{ 2(-3) }\]
hba
  • hba
The sign :/
poopsiedoodle
  • poopsiedoodle
+288?
poopsiedoodle
  • poopsiedoodle
I was kinda confused on that part.
hba
  • hba
What about -33 also
hba
  • hba
Yes +288 because (-) (-)=+
poopsiedoodle
  • poopsiedoodle
oops.
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ 2(-3) }\]
hba
  • hba
YEs continue
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ -6 }\]
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{1089 + 288} }{ -6 }\]
poopsiedoodle
  • poopsiedoodle
das a big ol' numba doe.
hba
  • hba
Continue.
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{1377} }{ -6 }\]
poopsiedoodle
  • poopsiedoodle
I think the 1377 breaks down into 17 and 81 here.
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm \sqrt{17*81} }{ -6 }\]
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -33\pm 9\sqrt{17} }{ -6 }\]
poopsiedoodle
  • poopsiedoodle
well, I gotta go home now. I may or may not be back soon.
hba
  • hba
Now take 3 common
poopsiedoodle
  • poopsiedoodle
\[\Huge x = \frac{ -11\pm 3\sqrt{17} }{ -2 }\]
hba
  • hba
Yeah right :) You can also take -1 common throughout. But,this answer is also correct

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