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poopsiedoodle

  • one year ago

I don't really need help here, I'm just using this as a workspace for my test on quadratic equations. :P

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  1. poopsiedoodle
    • one year ago
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    \[\Large x= \frac {-b \pm sqrt{b^{2}-4ac}{2a}\]

  2. Aeon_Valentine00
    • one year ago
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    HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

  3. poopsiedoodle
    • one year ago
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    stahp it

  4. poopsiedoodle
    • one year ago
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    @saifoo.khan I can't see my equation! D:

  5. saifoo.khan
    • one year ago
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    Wear some glasses maybe?

  6. saifoo.khan
    • one year ago
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    Don't forget to close a curly bracket. \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]

  7. poopsiedoodle
    • one year ago
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    No, like, it's grey, and not loading. I have the thing that says Processing math: 100%

  8. poopsiedoodle
    • one year ago
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    and it WON'T GO AWAY. >:(

  9. poopsiedoodle
    • one year ago
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    Maybe I'm using a bad proxy.

  10. saifoo.khan
    • one year ago
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    Maybe.

  11. poopsiedoodle
    • one year ago
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    \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]

  12. poopsiedoodle
    • one year ago
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    I can see it! It was just a bad proxy :P

  13. poopsiedoodle
    • one year ago
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    \[\Large x=\frac{ -10\pm \sqrt{10^{2-4(-20)}} }{ 2 }\]

  14. poopsiedoodle
    • one year ago
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    \[\Large x=\frac{ -10\pm \sqrt{2} -4(-20) }{ 2 }\]*

  15. poopsiedoodle
    • one year ago
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    GAH

  16. poopsiedoodle
    • one year ago
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    \[\Large x=\frac{ -10\pm \sqrt{2-80} }{ 2 }\]

  17. poopsiedoodle
    • one year ago
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    \[\Large x=\frac{ -10\pm \sqrt{-78} }{ 2 }\]

  18. poopsiedoodle
    • one year ago
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    \[\Large x=-5 \pm \sqrt{-39}\] @hba did I do this step right?

  19. hba
    • one year ago
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    Where are we ?

  20. poopsiedoodle
    • one year ago
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    I think I did this equation completely wrong. That's not one of the answer choices ._.

  21. hba
    • one year ago
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    You always do it wrong,give me a question let me show how it goes.

  22. poopsiedoodle
    • one year ago
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    \[\Huge x ^{2} = 10x -20\]

  23. hba
    • one year ago
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    http://sphotos-b.ak.fbcdn.net/hphotos-ak-ash3/19285_580947011919656_1245239224_n.jpg

  24. poopsiedoodle
    • one year ago
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    Helpful. :P

  25. hba
    • one year ago
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    So, x^2-10x+20=0 Here a=1 b=-10 c=20 in quad formula. @poopsiedoodle Do it for me.

  26. poopsiedoodle
    • one year ago
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    \[\Large x=\frac{ -10\pm \sqrt{10 - (4(20))} }{ 2 }\]

  27. poopsiedoodle
    • one year ago
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    since, a = 1, I just took out a.

  28. hba
    • one year ago
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    @poopsiedoodle Write it again correctly You have done a mistake

  29. poopsiedoodle
    • one year ago
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    oops. 10^2* \[x=\frac{ -10 \pm \sqrt{10^{2}-4(20)} }{ 2 }\]

  30. hba
    • one year ago
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    One more mistake

  31. poopsiedoodle
    • one year ago
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    I'm not seeing it o-o

  32. poopsiedoodle
    • one year ago
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    The only thing I can think of is leaving out the 1, which isn't necessary to include since it doesn't effect the outcome of the problem.

  33. hba
    • one year ago
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    Try seeing it Mistake of sign

  34. poopsiedoodle
    • one year ago
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    OH

  35. poopsiedoodle
    • one year ago
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    \[x=\frac{ 10\sqrt{-10 - 4(20)} }{ 2 }\]

  36. hba
    • one year ago
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    Where is the +- sign ?

  37. hba
    • one year ago
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    Where did the square go

  38. hba
    • one year ago
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    The underroot is on the whole exp.

  39. poopsiedoodle
    • one year ago
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    omg I keep forgetting things

  40. hba
    • one year ago
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    It is 4(a)(b) not only 4(c)

  41. hba
    • one year ago
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    4(a)(c) *

  42. poopsiedoodle
    • one year ago
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    \[\huge x=\frac{ 10\pm \sqrt{-10^{2} - 4(1)(20)} }{ 2(1) }\]

  43. hba
    • one year ago
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    Continue.

  44. hba
    • one year ago
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    @poopsiedoodle

  45. poopsiedoodle
    • one year ago
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    \[\huge x=\frac{ 10\pm \sqrt{100 - 4(20)} }{ 2 }\]

  46. poopsiedoodle
    • one year ago
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    \[\huge x=\frac{ 10\pm \sqrt{100 - 80} }{ 2 }\]

  47. poopsiedoodle
    • one year ago
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    \[\huge x=\frac{ 10\pm \sqrt{20} }{ 2 }\]

  48. hba
    • one year ago
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    Yes :)

  49. poopsiedoodle
    • one year ago
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    \[\huge x=\frac{ 10\pm 4\sqrt{5} }{ 2 }\]

  50. hba
    • one year ago
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    ^ this is wrong.

  51. poopsiedoodle
    • one year ago
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    \[\huge x={ 5\pm \sqrt{4*5} }\] *

  52. hba
    • one year ago
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    When you take sqrt{20}=sqrt{5*4]=2sqrt{5} \[\huge x=\frac{ 10\pm 2\sqrt{5} }{ 2 }\] Now continue....

  53. poopsiedoodle
    • one year ago
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    \[\Huge x=10\pm \sqrt{5}\]

  54. poopsiedoodle
    • one year ago
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    I'd nominate you for helper of the month, if that was a thing.

  55. poopsiedoodle
    • one year ago
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    now time for another one! :D

  56. poopsiedoodle
    • one year ago
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    \[\Huge 0 = -3x ^{2} 33x+24\]

  57. hba
    • one year ago
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    No YOU ARE WRONG!! We are taking 2 common through out.

  58. poopsiedoodle
    • one year ago
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    wat

  59. hba
    • one year ago
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    \[\huge x=\frac{ 2(5\pm \sqrt{5}) }{ 2 }\]

  60. poopsiedoodle
    • one year ago
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    so yeah, \[\Huge x= 5 \pm \sqrt{5}\]

  61. hba
    • one year ago
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    hmm

  62. poopsiedoodle
    • one year ago
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    Now then, on to \[\Huge 0 = -3x^{2} + 33x +24

  63. poopsiedoodle
    • one year ago
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    oops

  64. poopsiedoodle
    • one year ago
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    \[\Huge 0 = -3x^{2} + 33x +24\]

  65. hba
    • one year ago
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    Here a=-3 b=33 c=24 in quad formula

  66. poopsiedoodle
    • one year ago
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    \[\huge x = \frac{ 3\pm \sqrt{-3^{2} - 4(-3)(24)} }{ 2(-3) }\]

  67. hba
    • one year ago
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    b=33 not 3

  68. poopsiedoodle
    • one year ago
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    erpsh.

  69. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 4(-3)(24)} }{ 2(-3) }\]

  70. hba
    • one year ago
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    Sign error

  71. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} - 4(-3)(24)} }{ 2(-3) }\]

  72. hba
    • one year ago
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    Continue.

  73. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 288} }{ 2(-3) }\]

  74. hba
    • one year ago
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    The sign :/

  75. poopsiedoodle
    • one year ago
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    +288?

  76. poopsiedoodle
    • one year ago
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    I was kinda confused on that part.

  77. hba
    • one year ago
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    What about -33 also

  78. hba
    • one year ago
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    Yes +288 because (-) (-)=+

  79. poopsiedoodle
    • one year ago
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    oops.

  80. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ 2(-3) }\]

  81. hba
    • one year ago
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    YEs continue

  82. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ -6 }\]

  83. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{1089 + 288} }{ -6 }\]

  84. poopsiedoodle
    • one year ago
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    das a big ol' numba doe.

  85. hba
    • one year ago
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    Continue.

  86. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{1377} }{ -6 }\]

  87. poopsiedoodle
    • one year ago
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    I think the 1377 breaks down into 17 and 81 here.

  88. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm \sqrt{17*81} }{ -6 }\]

  89. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -33\pm 9\sqrt{17} }{ -6 }\]

  90. poopsiedoodle
    • one year ago
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    well, I gotta go home now. I may or may not be back soon.

  91. hba
    • one year ago
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    Now take 3 common

  92. poopsiedoodle
    • one year ago
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    \[\Huge x = \frac{ -11\pm 3\sqrt{17} }{ -2 }\]

  93. hba
    • one year ago
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    Yeah right :) You can also take -1 common throughout. But,this answer is also correct

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