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I don't really need help here, I'm just using this as a workspace for my test on quadratic equations. :P

Mathematics
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\[\Large x= \frac {-b \pm sqrt{b^{2}-4ac}{2a}\]
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stahp it

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Other answers:

@saifoo.khan I can't see my equation! D:
Wear some glasses maybe?
Don't forget to close a curly bracket. \[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]
No, like, it's grey, and not loading. I have the thing that says Processing math: 100%
and it WON'T GO AWAY. >:(
Maybe I'm using a bad proxy.
Maybe.
\[\Large x= \frac {-b \pm \sqrt{b^{2}-4ac}}{2a}\]
I can see it! It was just a bad proxy :P
\[\Large x=\frac{ -10\pm \sqrt{10^{2-4(-20)}} }{ 2 }\]
\[\Large x=\frac{ -10\pm \sqrt{2} -4(-20) }{ 2 }\]*
GAH
\[\Large x=\frac{ -10\pm \sqrt{2-80} }{ 2 }\]
\[\Large x=\frac{ -10\pm \sqrt{-78} }{ 2 }\]
\[\Large x=-5 \pm \sqrt{-39}\] @hba did I do this step right?
  • hba
Where are we ?
I think I did this equation completely wrong. That's not one of the answer choices ._.
  • hba
You always do it wrong,give me a question let me show how it goes.
\[\Huge x ^{2} = 10x -20\]
  • hba
http://sphotos-b.ak.fbcdn.net/hphotos-ak-ash3/19285_580947011919656_1245239224_n.jpg
Helpful. :P
  • hba
So, x^2-10x+20=0 Here a=1 b=-10 c=20 in quad formula. @poopsiedoodle Do it for me.
\[\Large x=\frac{ -10\pm \sqrt{10 - (4(20))} }{ 2 }\]
since, a = 1, I just took out a.
  • hba
@poopsiedoodle Write it again correctly You have done a mistake
oops. 10^2* \[x=\frac{ -10 \pm \sqrt{10^{2}-4(20)} }{ 2 }\]
  • hba
One more mistake
I'm not seeing it o-o
The only thing I can think of is leaving out the 1, which isn't necessary to include since it doesn't effect the outcome of the problem.
  • hba
Try seeing it Mistake of sign
OH
\[x=\frac{ 10\sqrt{-10 - 4(20)} }{ 2 }\]
  • hba
Where is the +- sign ?
  • hba
Where did the square go
  • hba
The underroot is on the whole exp.
omg I keep forgetting things
  • hba
It is 4(a)(b) not only 4(c)
  • hba
4(a)(c) *
\[\huge x=\frac{ 10\pm \sqrt{-10^{2} - 4(1)(20)} }{ 2(1) }\]
  • hba
Continue.
  • hba
\[\huge x=\frac{ 10\pm \sqrt{100 - 4(20)} }{ 2 }\]
\[\huge x=\frac{ 10\pm \sqrt{100 - 80} }{ 2 }\]
\[\huge x=\frac{ 10\pm \sqrt{20} }{ 2 }\]
  • hba
Yes :)
\[\huge x=\frac{ 10\pm 4\sqrt{5} }{ 2 }\]
  • hba
^ this is wrong.
\[\huge x={ 5\pm \sqrt{4*5} }\] *
  • hba
When you take sqrt{20}=sqrt{5*4]=2sqrt{5} \[\huge x=\frac{ 10\pm 2\sqrt{5} }{ 2 }\] Now continue....
\[\Huge x=10\pm \sqrt{5}\]
I'd nominate you for helper of the month, if that was a thing.
now time for another one! :D
\[\Huge 0 = -3x ^{2} 33x+24\]
  • hba
No YOU ARE WRONG!! We are taking 2 common through out.
wat
  • hba
\[\huge x=\frac{ 2(5\pm \sqrt{5}) }{ 2 }\]
so yeah, \[\Huge x= 5 \pm \sqrt{5}\]
  • hba
hmm
Now then, on to \[\Huge 0 = -3x^{2} + 33x +24
oops
\[\Huge 0 = -3x^{2} + 33x +24\]
  • hba
Here a=-3 b=33 c=24 in quad formula
\[\huge x = \frac{ 3\pm \sqrt{-3^{2} - 4(-3)(24)} }{ 2(-3) }\]
  • hba
b=33 not 3
erpsh.
\[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 4(-3)(24)} }{ 2(-3) }\]
  • hba
Sign error
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} - 4(-3)(24)} }{ 2(-3) }\]
  • hba
Continue.
\[\Huge x = \frac{ 33\pm \sqrt{-33^{2} - 288} }{ 2(-3) }\]
  • hba
The sign :/
+288?
I was kinda confused on that part.
  • hba
What about -33 also
  • hba
Yes +288 because (-) (-)=+
oops.
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ 2(-3) }\]
  • hba
YEs continue
\[\Huge x = \frac{ -33\pm \sqrt{33^{2} + 288} }{ -6 }\]
\[\Huge x = \frac{ -33\pm \sqrt{1089 + 288} }{ -6 }\]
das a big ol' numba doe.
  • hba
Continue.
\[\Huge x = \frac{ -33\pm \sqrt{1377} }{ -6 }\]
I think the 1377 breaks down into 17 and 81 here.
\[\Huge x = \frac{ -33\pm \sqrt{17*81} }{ -6 }\]
\[\Huge x = \frac{ -33\pm 9\sqrt{17} }{ -6 }\]
well, I gotta go home now. I may or may not be back soon.
  • hba
Now take 3 common
\[\Huge x = \frac{ -11\pm 3\sqrt{17} }{ -2 }\]
  • hba
Yeah right :) You can also take -1 common throughout. But,this answer is also correct

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