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## onegirl Find the sum 4 sigma notation sign n = 1 (n + 2/n + 3) one year ago one year ago

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1. slaaibak

$\sum_{n=1}^{4} {n+2 \over n+3}$ Like that?

2. onegirl

yes

3. slaaibak

since it's only four terms, just evaluate it at each n: ${1 + 2 \over 1 + 3} + {2 + 2 \over 2 + 3} + {3 + 2 \over 3 + 3} + {4 + 2 \over 4 + 3} = {3 \over 4} + {4 \over 5} + {5 \over 6} + {6 \over 7}$

4. onegirl

umm ok

5. onegirl

so what will it be?

6. slaaibak

Use your calculator.

7. onegirl

i did so i just add them all?

8. slaaibak

yeah

9. onegirl

ok thx