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anonymous
 4 years ago
Find the sum 4 sigma notation sign n = 1 (n + 2/n + 3)
anonymous
 4 years ago
Find the sum 4 sigma notation sign n = 1 (n + 2/n + 3)

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slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sum_{n=1}^{4} {n+2 \over n+3}\] Like that?

slaaibak
 4 years ago
Best ResponseYou've already chosen the best response.1since it's only four terms, just evaluate it at each n: \[{1 + 2 \over 1 + 3} + {2 + 2 \over 2 + 3} + {3 + 2 \over 3 + 3} + {4 + 2 \over 4 + 3} = {3 \over 4} + {4 \over 5} + {5 \over 6} + {6 \over 7}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did so i just add them all?
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