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onegirl

  • 2 years ago

Find the sum 4 sigma notation sign n = 1 (n + 2/n + 3)

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  1. slaaibak
    • 2 years ago
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    \[\sum_{n=1}^{4} {n+2 \over n+3}\] Like that?

  2. onegirl
    • 2 years ago
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    yes

  3. slaaibak
    • 2 years ago
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    since it's only four terms, just evaluate it at each n: \[{1 + 2 \over 1 + 3} + {2 + 2 \over 2 + 3} + {3 + 2 \over 3 + 3} + {4 + 2 \over 4 + 3} = {3 \over 4} + {4 \over 5} + {5 \over 6} + {6 \over 7}\]

  4. onegirl
    • 2 years ago
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    umm ok

  5. onegirl
    • 2 years ago
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    so what will it be?

  6. slaaibak
    • 2 years ago
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    Use your calculator.

  7. onegirl
    • 2 years ago
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    i did so i just add them all?

  8. slaaibak
    • 2 years ago
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    yeah

  9. onegirl
    • 2 years ago
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    ok thx

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