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First, turn it into a matrix!

Umm okay...

Okay.

Here do you understand how I got this?
[1 6 4 2 ]
[4 25 31 7 ]
[2 13 7a^2 -1+a]

Yeah I do.,

Yeah but what about that a?

We're going to work with that later. It shouldn't get in the way because it's in the bottom row.

I have to still manipulate it like normal correct?

Yes. So first try to get 0s in the first column

|dw:1358201674350:dw|

No wait. That's not right.

Nope :P OK I'll give you the first step. Subtract 4 times the first row from the second row.

Sorry about that. This Linear algebra is fun but totally new to me.

If we went 4* Row 1 we get -3 in the 2nd row for the first term.

Wait... Oops.

KK. Let me try myslef again.

I was looking at another Matrix >.< .

Kk. I got what you got. Now I would go and divide Row 3 by 2 right?

Nope you would do Row 3 - 2 times Row 1. You want to get a 0 in the first spot of row 3

Okay, that works too.

For row 3 I got [0 1 5+a^2 -3+a]

Wait, third colums in wrong.

[0 1 -1+a^2 -3+a]

[0 1 -1+a^2 -5+a] . Woudn't it be that actually?

K I got [0 0 -16+a^2 -4+a]

If you've got any questions about my explanation, ask them and I'll answer later.

WHat's a Pivot column?

And thanks for the encouragement :) .