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geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I solved #10 and the answer is 109.217 m/s if this help you all.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I'm not sure exactly what #11 mean; I don't see how this system lost energy during collision.

wio
 one year ago
Best ResponseYou've already chosen the best response.2By the way, how did you find the velocity?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Are you telling me that the block lost energy to the spring?

VeritasVosLiberabit
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ 2 }m _{b}v _{b1}^{2}=\frac{ 1 }{ 2 }m _{b}v _{b2}^{2}+\frac{ 1 }{ 2 }kx\] was the formula I got for 10. \[\sqrt{2[\frac{ 1 }{ 2 }(.003kg)(500\frac{ m }{ s })^{2}\frac{ 1 }{ 2 }(859\frac{ N }{ m })(.02m)]/.003kg}=v _{b2}\]

VeritasVosLiberabit
 one year ago
Best ResponseYou've already chosen the best response.0my final answer for #10 was 494.24 m/s which makes more sense to me than 109.217 m/s

VeritasVosLiberabit
 one year ago
Best ResponseYou've already chosen the best response.0but I'm not sure. are you sure your answer for #10 is correct?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Well, I submitted my answer on online homework and it said it's correct.

VeritasVosLiberabit
 one year ago
Best ResponseYou've already chosen the best response.0ok, I'm going to retry it then.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Any idea for #11, @wio ?

wio
 one year ago
Best ResponseYou've already chosen the best response.2So you figured out how much energy was transferred to the block, and the remaining energy was used to calculate velocity, right?

wio
 one year ago
Best ResponseYou've already chosen the best response.2Did you try putting the elastic energy as energy lost?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I did and the answer is incorrect...

wio
 one year ago
Best ResponseYou've already chosen the best response.2What about the conservation of momentum?

wio
 one year ago
Best ResponseYou've already chosen the best response.2Was momentum give to the block on the spring?

wio
 one year ago
Best ResponseYou've already chosen the best response.2Figure out the momentum before hand and figure out the momentum later. That would tell you how much momentum the block received. Compare that to the elastic energy.

wio
 one year ago
Best ResponseYou've already chosen the best response.2I mean, use the momentum of the block to find its velocity and figure out the kinetic energy of the block. Then compare that to the elastic energy.

wio
 one year ago
Best ResponseYou've already chosen the best response.2That might be what they're asking. It's true that I find it hard to tell. Obviously this is a closed system an no energy is being lost. So maybe what they mean is how much kinetic energy do we expect the block to have, which it won't have.

wio
 one year ago
Best ResponseYou've already chosen the best response.2If that doesn't work then I'm really stumped here.

wio
 one year ago
Best ResponseYou've already chosen the best response.2It's a really unfair question in my opinion.

wio
 one year ago
Best ResponseYou've already chosen the best response.2@geerky42 Have you been looking at the momentum?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1None, It doesn't work... I guess I need to ask my physics teacher a question. Thanks.

wio
 one year ago
Best ResponseYou've already chosen the best response.2@geerky42 I'm not getting your 109 velocity through energy methods alone

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Sorry I just use conservation of energy to find the speed of block after collision, I then plug the speed of block into conservation of momentum to find the speed of bullet after collision. My brain is dead, sorry about that.

wio
 one year ago
Best ResponseYou've already chosen the best response.2How did you find the speed of the block then?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1"Sorry I just use conservation of energy to find the speed of block"

wio
 one year ago
Best ResponseYou've already chosen the best response.2Yeah well the block started with no energy right?

wio
 one year ago
Best ResponseYou've already chosen the best response.2you converted that into kinetic energy?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Well, it moves so it should have kinetic energy.

wio
 one year ago
Best ResponseYou've already chosen the best response.2How did you find out how much bullet energy went into kinetic energy then?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I don't find it from bullet, I did work "backward." We know that the spring has been compressed by 2 cm and from that we can find elastic energy and then from that, we can convert it into kinetic energy. That's how I find the speed of block.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Kinetic energy instantly after collision.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I don't see how system lost the energy, spring absorb energy from block that has been hit by bullet.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1The surface is frictionless. I don't know what else cause it to lost energy...

wio
 one year ago
Best ResponseYou've already chosen the best response.2Oh, did you try entering the change in kinetic energy of the bullet?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1No, how can this help me?

wio
 one year ago
Best ResponseYou've already chosen the best response.2Because it would be the amount of energy the bullet lost

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1None, still don't work...

wio
 one year ago
Best ResponseYou've already chosen the best response.2What are you getting for it though?

wio
 one year ago
Best ResponseYou've already chosen the best response.2No, that's the new KE of the bullet. I said the change.

wio
 one year ago
Best ResponseYou've already chosen the best response.2Meaning the first KE minus the new KE

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I did this, I got this answer.

wio
 one year ago
Best ResponseYou've already chosen the best response.2your original KE wasn't 375?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Forgot to square one of the velocity, I got 357.107 J

wio
 one year ago
Best ResponseYou've already chosen the best response.2Yes, that's what I'm getting as the change in bullet eneryg.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Submitted this answer; it's still wrong...

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1I guess I have to see my teacher and talk about it.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Thanks for your time and patience, though.
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