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joules are kg m^2/s^2
\[J/s= \frac{{kg}*m^2}{s^2}*\frac{1}{s}=\frac{{kg}*m^2}{s^3}\]
Right?

I think this is extremely over-complicating the original intent of this thread...but...yes?

Simply asking how to cancel out "s" in this situation.

Where are you canceling the s? Maybe with more context I can give you a better answer.

In J/S

They don't cancel out. J/s = watts, and watts are kg m^2 / s^3, just like I showed above.

Remember, dividing by s is equivalent to multiplying by 1/s.

well, you know, the same well you can "remove" distance (m) in speed (m/s) to get time (t) by

t=v/d?
t=d/v?

Man, can not realize I forgot this so fast.

d = vt
m = (m/s)*(s)
m = m
But there's no cancellation in J/s...