Ammarah
  • Ammarah
how do u know when to use sin and cos?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Ammarah
  • Ammarah
@mathstudent55
IsTim
  • IsTim
sin for opposite over hypotenus cos for adjacent over hypotenus
Ammarah
  • Ammarah
I know but like in a problem...i dont get which one i should use

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Ammarah
  • Ammarah
Use a sine or cosine ration to find the value of each variable. Round decimals to the nearest tenth.
Ammarah
  • Ammarah
|dw:1358230193689:dw|
Ammarah
  • Ammarah
These three please
Ammarah
  • Ammarah
i dont get them
IsTim
  • IsTim
https://www.google.com/webhp?sourceid=chrome-instant&ion=1&ie=UTF-8#hl=en&sugexp=les%3B&gs_rn=1&gs_ri=hp&tok=SDprTiicMZfE6kT1J9oplw&cp=11&gs_id=a&xhr=t&q=trig+ratios&es_nrs=true&pf=p&safe=off&tbo=d&output=search&sclient=psy-ab&oq=trig+ratios&gs_l=&pbx=1&bav=on.2,or.r_gc.r_pw.r_qf.&bvm=bv.41018144,d.b2U&fp=17f68d729ad92053&biw=1344&bih=743&ion=1
IsTim
  • IsTim
use that. sorry. i ahve to go soon.
Ammarah
  • Ammarah
it doesnt help please solve these for me
Callisto
  • Callisto
|dw:1358230939592:dw| Refer to the reference angle. Sin => opposite side (to the reference angle) / hypotenuse In this diagram, can you determine what sine theta is?
Ammarah
  • Ammarah
? no
Callisto
  • Callisto
what is the opposite side to the reference angle theta?
Ammarah
  • Ammarah
x
Callisto
  • Callisto
and what is the hypotenuse?
Ammarah
  • Ammarah
2 btw what is theta?
Callisto
  • Callisto
Sorry :| that was supposed to be z :| If you know x and z, you can find theta. Because sin (theta) = x/z Got it?
anonymous
  • anonymous
Ammara, so in an equation, Callisto is saying is that in the figure above, \[\sin(\theta) = \frac{ x }{ z }\] So, in your figure, the first problem: you know the hypotenuse (18) and the angle opposite x (32 degrees). So you know that, \[\sin(32) = \frac{ x }{ 18 }\] Then solve for x :)
anonymous
  • anonymous
And that's the sine of 32 degrees of course, not radians.
Ammarah
  • Ammarah
what do i do for why then?
Ammarah
  • Ammarah
|dw:1358231828749:dw|
anonymous
  • anonymous
Well, you know that the angle opposite x is 32 degrees, and that the angle opposite the hypotentuse is 90 degrees. You also know the total sum of all interior angles of a triangle - so from that you can figure out the remaining angle you don't know, and do the same thing.
Ammarah
  • Ammarah
i dont get it....how to i solve for y?
Ammarah
  • Ammarah
and does x=9.5?
anonymous
  • anonymous
Or alternatively, use the cosine which is the adjacent angle over the hypotenuse: \[\cos(\theta) = \frac{ y }{ z }\] Substitute for the adjacent angle (32 degrees again) and for the hypotenuse (18), and solve for y the same way you solved for x above.
Ammarah
  • Ammarah
|dw:1358232234127:dw|
anonymous
  • anonymous
Correct.
Ammarah
  • Ammarah
Ok how about the next triangle...
Ammarah
  • Ammarah
|dw:1358232364105:dw|
Ammarah
  • Ammarah
|dw:1358232378783:dw|
Ammarah
  • Ammarah
so in the left triangle were solving for a.
Ammarah
  • Ammarah
how would u solve it? please solve it for me.......
anonymous
  • anonymous
Correct. And you know that the cosine of the angle (48 degrees) is the same as 10 divided by a - careful here, because a is the hypotenuse: \[\cos(\Theta) = \frac{ 10 }{ a }\] So, \[\cos(48) = \frac{ 10 }{ a } \]
Ammarah
  • Ammarah
how would i solve be now...i got 14.9 for a
anonymous
  • anonymous
That's correct. Now solve the last figure?
Ammarah
  • Ammarah
b=11.1?
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
You got it. Can you do the last triangle?

Looking for something else?

Not the answer you are looking for? Search for more explanations.