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how do u know when to use sin and cos?

Mathematics
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sin for opposite over hypotenus cos for adjacent over hypotenus
I know but like in a problem...i dont get which one i should use

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Other answers:

Use a sine or cosine ration to find the value of each variable. Round decimals to the nearest tenth.
|dw:1358230193689:dw|
These three please
i dont get them
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use that. sorry. i ahve to go soon.
it doesnt help please solve these for me
|dw:1358230939592:dw| Refer to the reference angle. Sin => opposite side (to the reference angle) / hypotenuse In this diagram, can you determine what sine theta is?
? no
what is the opposite side to the reference angle theta?
x
and what is the hypotenuse?
2 btw what is theta?
Sorry :| that was supposed to be z :| If you know x and z, you can find theta. Because sin (theta) = x/z Got it?
Ammara, so in an equation, Callisto is saying is that in the figure above, \[\sin(\theta) = \frac{ x }{ z }\] So, in your figure, the first problem: you know the hypotenuse (18) and the angle opposite x (32 degrees). So you know that, \[\sin(32) = \frac{ x }{ 18 }\] Then solve for x :)
And that's the sine of 32 degrees of course, not radians.
what do i do for why then?
|dw:1358231828749:dw|
Well, you know that the angle opposite x is 32 degrees, and that the angle opposite the hypotentuse is 90 degrees. You also know the total sum of all interior angles of a triangle - so from that you can figure out the remaining angle you don't know, and do the same thing.
i dont get it....how to i solve for y?
and does x=9.5?
Or alternatively, use the cosine which is the adjacent angle over the hypotenuse: \[\cos(\theta) = \frac{ y }{ z }\] Substitute for the adjacent angle (32 degrees again) and for the hypotenuse (18), and solve for y the same way you solved for x above.
|dw:1358232234127:dw|
Correct.
Ok how about the next triangle...
|dw:1358232364105:dw|
|dw:1358232378783:dw|
so in the left triangle were solving for a.
how would u solve it? please solve it for me.......
Correct. And you know that the cosine of the angle (48 degrees) is the same as 10 divided by a - careful here, because a is the hypotenuse: \[\cos(\Theta) = \frac{ 10 }{ a }\] So, \[\cos(48) = \frac{ 10 }{ a } \]
how would i solve be now...i got 14.9 for a
That's correct. Now solve the last figure?
b=11.1?
Yes!
You got it. Can you do the last triangle?

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