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Ammarah Group TitleBest ResponseYou've already chosen the best response.0
@mathstudent55
 one year ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
sin for opposite over hypotenus cos for adjacent over hypotenus
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
I know but like in a problem...i dont get which one i should use
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
Use a sine or cosine ration to find the value of each variable. Round decimals to the nearest tenth.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
dw:1358230193689:dw
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
These three please
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
i dont get them
 one year ago

IsTim Group TitleBest ResponseYou've already chosen the best response.0
use that. sorry. i ahve to go soon.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
it doesnt help please solve these for me
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
dw:1358230939592:dw Refer to the reference angle. Sin => opposite side (to the reference angle) / hypotenuse In this diagram, can you determine what sine theta is?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
what is the opposite side to the reference angle theta?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
and what is the hypotenuse?
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
2 btw what is theta?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Sorry : that was supposed to be z : If you know x and z, you can find theta. Because sin (theta) = x/z Got it?
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
Ammara, so in an equation, Callisto is saying is that in the figure above, \[\sin(\theta) = \frac{ x }{ z }\] So, in your figure, the first problem: you know the hypotenuse (18) and the angle opposite x (32 degrees). So you know that, \[\sin(32) = \frac{ x }{ 18 }\] Then solve for x :)
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
And that's the sine of 32 degrees of course, not radians.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
what do i do for why then?
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
dw:1358231828749:dw
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
Well, you know that the angle opposite x is 32 degrees, and that the angle opposite the hypotentuse is 90 degrees. You also know the total sum of all interior angles of a triangle  so from that you can figure out the remaining angle you don't know, and do the same thing.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
i dont get it....how to i solve for y?
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
and does x=9.5?
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
Or alternatively, use the cosine which is the adjacent angle over the hypotenuse: \[\cos(\theta) = \frac{ y }{ z }\] Substitute for the adjacent angle (32 degrees again) and for the hypotenuse (18), and solve for y the same way you solved for x above.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
dw:1358232234127:dw
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
Ok how about the next triangle...
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
dw:1358232364105:dw
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
dw:1358232378783:dw
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
so in the left triangle were solving for a.
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
how would u solve it? please solve it for me.......
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
Correct. And you know that the cosine of the angle (48 degrees) is the same as 10 divided by a  careful here, because a is the hypotenuse: \[\cos(\Theta) = \frac{ 10 }{ a }\] So, \[\cos(48) = \frac{ 10 }{ a } \]
 one year ago

Ammarah Group TitleBest ResponseYou've already chosen the best response.0
how would i solve be now...i got 14.9 for a
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
That's correct. Now solve the last figure?
 one year ago

opiesche Group TitleBest ResponseYou've already chosen the best response.1
You got it. Can you do the last triangle?
 one year ago
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