anonymous
  • anonymous
find by first principle the derivative of arccos(x) / x Pls help anyone??
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\cos^{-1} (x) / x find the derivative by first principle???\]
Goten77
  • Goten77
|dw:1358241639871:dw|
Goten77
  • Goten77
does this mean we cant use the quotient rule?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it should be done only by first principle method and not using the formula
whpalmer4
  • whpalmer4
\[\frac{dy}{dx}=\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}=\lim_{h \rightarrow 0}\frac{1}{h}(\frac{\cos^{-1}(x+h)}{x+h}-\frac{\cos^{-1}(x)}{x})\] Grind out the work...
anonymous
  • anonymous
after this what next how to resolve the RHS, pls help
whpalmer4
  • whpalmer4
I'd start by making a common denominator for the right hand side...
anonymous
  • anonymous
Pls give me the steps i'm not getting it.
klimenkov
  • klimenkov
Reduce this:\[\frac{\cos^{-1}(x+h)}{x+h}-\frac{\cos^{-1}(x)}{x}\].
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
yes this is correct answer but it should be done with first principle method
anonymous
  • anonymous
the method suggeested by @whpalmer4 is right
anonymous
  • anonymous
yes but how do we go further to get the answer?

Looking for something else?

Not the answer you are looking for? Search for more explanations.