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mo7892 Group Title

can you prove that (m+n)cotθ=mcotθ-ncotθ

  • one year ago
  • one year ago

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  1. shubhamsrg Group Title
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    Can i ?

    • one year ago
  2. klimenkov Group Title
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    Obviously, this is not right.

    • one year ago
  3. AravindG Group Title
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    is that possible?

    • one year ago
  4. AravindG Group Title
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    it can nevr be true

    • one year ago
  5. hartnn Group Title
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    only if n=0

    • one year ago
  6. mo7892 Group Title
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    i have a non right angle triangle ABC which the base is length m and n. and its divided into two by two angles beta and alpha

    • one year ago
  7. hartnn Group Title
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    do you have a figure ?

    • one year ago
  8. mo7892 Group Title
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    let me draw it

    • one year ago
  9. mo7892 Group Title
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    i have drawn it but how do i send it for you

    • one year ago
  10. mo7892 Group Title
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    how do i send the figure

    • one year ago
  11. hartnn Group Title
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    you can draw the figure using 'Draw' button below, or you can attach the image file using 'Attach File' button...these buttons are on the left of Post button.

    • one year ago
  12. klimenkov Group Title
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    And don't forget to click the "Post" button.

    • one year ago
  13. mo7892 Group Title
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    let me know if you can see the diagram

    • one year ago
    1 Attachment
  14. hartnn Group Title
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    no, can't see..

    • one year ago
  15. mo7892 Group Title
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    they have said use the trigonometric theorem (M+N)COTθ=MCOTα-NCOTβ

    • one year ago
  16. mo7892 Group Title
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    try no 2 second attachment.

    • one year ago
  17. mo7892 Group Title
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    • one year ago
  18. mo7892 Group Title
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    can you let me know if you can see it

    • one year ago
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