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mo7892

  • 3 years ago

can you prove that (m+n)cotθ=mcotθ-ncotθ

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  1. shubhamsrg
    • 3 years ago
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    Can i ?

  2. klimenkov
    • 3 years ago
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    Obviously, this is not right.

  3. AravindG
    • 3 years ago
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    is that possible?

  4. AravindG
    • 3 years ago
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    it can nevr be true

  5. hartnn
    • 3 years ago
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    only if n=0

  6. mo7892
    • 3 years ago
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    i have a non right angle triangle ABC which the base is length m and n. and its divided into two by two angles beta and alpha

  7. hartnn
    • 3 years ago
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    do you have a figure ?

  8. mo7892
    • 3 years ago
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    let me draw it

  9. mo7892
    • 3 years ago
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    i have drawn it but how do i send it for you

  10. mo7892
    • 3 years ago
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    how do i send the figure

  11. hartnn
    • 3 years ago
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    you can draw the figure using 'Draw' button below, or you can attach the image file using 'Attach File' button...these buttons are on the left of Post button.

  12. klimenkov
    • 3 years ago
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    And don't forget to click the "Post" button.

  13. mo7892
    • 3 years ago
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    let me know if you can see the diagram

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  14. hartnn
    • 3 years ago
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    no, can't see..

  15. mo7892
    • 3 years ago
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    they have said use the trigonometric theorem (M+N)COTθ=MCOTα-NCOTβ

  16. mo7892
    • 3 years ago
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    try no 2 second attachment.

  17. mo7892
    • 3 years ago
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  18. mo7892
    • 3 years ago
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    can you let me know if you can see it

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