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there are a lot....theorems related to circle and their chords, tangents, angles etc....what do u wanna know?
if i was to type a question without the picture would you understand a answer?
i can try...go ahead. btw u can draw a picture with the 'draw' tool.
ouu YAYA ! . okay one sec
|dw:1358257312264:dw| " in the figure, given that point P= point Q . AB=CD , AB=24, and PX=p . what is the length of the given radius Q?
sorry Q is where P is at on the first circle . you see how i put d twice ? well Q is where P is . get it ?
hmm thought so....so u need to find out the radius QY?
it just said of Q , but i guess ?
can u check the question again? i didnt exactly get what u meant by point P = point Q....how can two points be equal?
okay how about i just give you the answer ? , so you can understand how to get it ? ... its 15
that'd be only possible if any of the following angles are given. |dw:1358258436102:dw|
ready for another?
sure...but dont u think we should finish solving it first?
|dw:1358258923677:dw| if point m=point N , AB-CD . QD=24 and ND=26 what is the length of LM?
and yes to your last picture
what was the given length of the segment that i showed in my last picture??
ab=24 and px=9
lol and u said PX=p :P :P ok here's the basic theorem, lets say you draw a line from the center of a circle to any chord of the circle, and the angle formed becomes 90 degree |dw:1358259896480:dw| in that case, the point where the line touches the chord will bisect it, so in ur first picture, since AB=24,
yay and yes . ready for the next one?
okay the next one is the picture i sunt you
ok let me explain the second one. as you can see, ND=MB=26 is the radius for both the circles. QD is already given (you dont need to halve the chord like u did before, QD is already half), also. QD=LB now use pythagorean theorem to find out LM |dw:1358260511366:dw|