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Falkqwer

  • 2 years ago

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  1. phi
    • 2 years ago
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    I just noticed the last line: If you must order at least one of each type of table, because without that line I was not getting any of your choices. Can you try to sketch the relations? Let x be the number of type A and y be the number of type B You can order no more than 190 tables this month. that means the sum of x and y must be less than or equal to 190 x+y≤ 190 put this into slope-intercept form: y ≤ -x + 190 plot the line y= -x + 190 shade the area under this line (this is where y is less than the line) can you do that?

  2. Falkqwer
    • 2 years ago
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    I'll try :) one sec

  3. phi
    • 2 years ago
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    It only shows a bit of the graph. By hand: |dw:1358269570252:dw|

  4. Falkqwer
    • 2 years ago
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    OK so what does this tell me now? sorry I'm dumb :(

  5. phi
    • 2 years ago
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    We don't go below x=0 (we can't order less than 0) same for y that triangle represents all (x,y) pairs of orders where x+y ≤ 190 (and x+y≥0 we can't order less than 0) if you go outside the triangle you will order too many or a negative number. Neither is allowed.

  6. phi
    • 2 years ago
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    you need to make at least $4,610 profit on them It would be good if you could write down the relation (mathematical expression) for this. Hero posted it, but you should try. The profit will be the number of type A's times the profit per type A plus # of B's times profit of a B this sum must be ≥ 4610 Can you write down the expression?

  7. Falkqwer
    • 2 years ago
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    29a + 19b >_ 4610

  8. phi
    • 2 years ago
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    ok, but use x and y, because we have to plot this...

  9. Falkqwer
    • 2 years ago
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    ok :) 29x + 19y >_4610

  10. phi
    • 2 years ago
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    can you put it into slope-intercept form?

  11. Falkqwer
    • 2 years ago
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    IDK sorry

  12. phi
    • 2 years ago
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    slope intercept form is y ≥ mx + b in other words, y is by itself on the left. First step is add -29x to both sides. Just write -29x on both sides what do you get?

  13. Falkqwer
    • 2 years ago
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    y=x+19>_4610 IDk

  14. phi
    • 2 years ago
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    don't make things up. start with 29x + 19y >= 4610 write -29x on both sides: -29x + 29x + 19y >= -29x + 4610 on the left side you have 29x and -29x (think: 29 x's take away 29 x's. I get no x's) 19y ≥ -29x +4610 now divide both sides by 19. That means divide each term on both sides by 19 what do you get?

  15. Falkqwer
    • 2 years ago
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    y≥ -29/12x + 4610/19

  16. phi
    • 2 years ago
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    I assume that 12 is a typo?

  17. Falkqwer
    • 2 years ago
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    ohh I mean 19

  18. phi
    • 2 years ago
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    now, let's change into decimals (only a few digits). Roughly we get y ≥ -1.53 x + 242.6 now plot this line. Y ≥ means shade all the Y above the line. Can you plot this line?

  19. Falkqwer
    • 2 years ago
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    I have no idea:(

  20. phi
    • 2 years ago
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    for y ≥ -1.53 x + 242.6 we first plot y = -1.53x +242.6 if we set x to 0, what is y ?

  21. Falkqwer
    • 2 years ago
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    y ≥ 242.6

  22. phi
    • 2 years ago
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    Ok, x=0, y = 242.6 (0,242.6) is one point on the line can you plot this point ?

  23. Falkqwer
    • 2 years ago
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    idk how

  24. Falkqwer
    • 2 years ago
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    |dw:1358271480089:dw|

  25. phi
    • 2 years ago
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    yes, that looks good See http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/coordinate-plane/v/plot-ordered-pairs if you need a refresher. now lets find y when x = 100 y = -1.53x +242.6 replace x with 100 y = -1.53*100 + 242.6 what do you get ?

  26. phi
    • 2 years ago
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    I picked x=100 because it is easy to multiply by 100. we could pick any x, but x near or inside our triangle makes sense.

  27. Falkqwer
    • 2 years ago
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    y= 395.6

  28. phi
    • 2 years ago
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    -1.53*100 is a negative number. try again

  29. Falkqwer
    • 2 years ago
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    89.6

  30. phi
    • 2 years ago
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    that means (100,89.6) is on the line. can you plot this point ? go to x=100 and move up about 90.

  31. Falkqwer
    • 2 years ago
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    |dw:1358272059574:dw|

  32. phi
    • 2 years ago
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    now connect the dots (or x's in this case) |dw:1358272145701:dw|

  33. Falkqwer
    • 2 years ago
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    d.)100 of type A; 90 of type B

  34. phi
    • 2 years ago
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    I shaded the area above the line, because that is where y ≥ to the line The black shaded area is everywhere where you get the needed profit (remember profit must be ≥ 4610) We also must be below the red line. To meet both requirements, we must be in the lower triangle.

  35. Falkqwer
    • 2 years ago
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    ahhhh ok I'm confused now...what is the answer?

  36. phi
    • 2 years ago
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    Once you get the "feasible" region, you check the "corners" for the (x,y) pair that matches your requirement. In this case, the bottom two spots have y=0 and the statement If you must order at least one of each type of table means we can rule out those points we have to find the intersection of the two lines. but we see by eyeball it is 100, 90

  37. Falkqwer
    • 2 years ago
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    so its AorD :D

  38. phi
    • 2 years ago
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    A is x in our graph. and B is y Here is how to find where the lines cross: you start with y= -x + 190 y = -1.53x +242.6 when they meet they have the same y values. we set -x + 190 = -1.53x +242.6 add 1.53x to both sides (you should learn how to do this, btw) 1.53x - 1x + 190= -1.53x + 1.53x +242.6 on the left we get 0.53x+190 and on the right 242.6: 0.53x +190 = 242.6 add -190 to both sides 0.53x +190-190= 242.6-190 0.53x = 52.6 divide both sides by 0.53, and x = 99.2 looking at our graph, we want x bigger than this (we have to buy a whole table) x=100 and x+y =190 replace x with 100: 100+y=190 add -100 to both sides: 100-100+y= 190-100 y=90 In a harder problem, we would use these x,y numbers in the cost equation, and find the (x,y) pair (of the three corners) that gives the lowest cost. here, we just need to find the top "corner" because the bottom 2 are ruled out by the question (we must buy some of both types, so 0 is not allowed)

  39. Falkqwer
    • 2 years ago
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    So the answer is A :) thank you so much for spending the time on teaching me :p I really appreciated

  40. phi
    • 2 years ago
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    I think you can do this stuff, but you have skimped so much in learning all the details that it is difficult to do a problem like this where you have to remember how to do lots of things: plot, solve equations, etc.

  41. phi
    • 2 years ago
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    Personally, I would pick just one area (example: putting equations into slope-intercept form), and watch a video at Khan

  42. Falkqwer
    • 2 years ago
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    ok I'll try that thanx again :)

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