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Falkqwer

  • 3 years ago

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  1. Falkqwer
    • 3 years ago
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    @hba

  2. hba
    • 3 years ago
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    Um,Multiply and divide by (4-6i)

  3. hba
    • 3 years ago
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    Nice changing your profile picture. Now start working lol :P

  4. hba
    • 3 years ago
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    \[\frac{ 5+6i }{ 4+6i } \times \frac{ 4-6i }{ 4-6i }\] \[\frac{ (5+6i)(4-6i) }{ (4+6i)(4-6i)}\]

  5. Falkqwer
    • 3 years ago
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    ok :) what now

  6. hba
    • 3 years ago
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    Use (a+b)(a-b)=(a^2-b^2) for denominator and remember i^2=-1

  7. Falkqwer
    • 3 years ago
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    idk please do it :'(

  8. hba
    • 3 years ago
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    Not helping :/

  9. hba
    • 3 years ago
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    \[\frac{ (5+6i)(4-6i) }{ ((4)^2-(6i)^2)}\] Now solve

  10. Falkqwer
    • 3 years ago
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    \[\frac{ 56-6i }{ 52 }\]

  11. Falkqwer
    • 3 years ago
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    so its D Thanks you :)

  12. hba
    • 3 years ago
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    Welcome :)

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