## Kagome_gurl8 2 years ago In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x-8. For what value of x is ABCD a rhombus.

1. Kagome_gurl8

2. mathstudent55

In a rhombus, each diagonal bisects a pair of opposite angles.

3. Kagome_gurl8

I keep getting 6 at the very end, is that correct?

4. mathstudent55

No, x is not 6. How did you set up your equation?

5. Kagome_gurl8

I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5

6. mathstudent55

Show me the equation you are trying to solve.

7. Kagome_gurl8

2x + 4=2 + 5x-8=3 then 3+2=5 This is what my teacher taught me but it just doesnt seem right

8. mathstudent55

Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means: 2x + 4 = 5x - 8 This is the equation you must solve.

9. Kagome_gurl8

4

10. mathstudent55

Correct

11. Kagome_gurl8

You should be a teacher.

12. mathstudent55

Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part

13. micahm

@jolenewhite.2000

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