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In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x8. For what value of x is ABCD a rhombus.
 one year ago
 one year ago
In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x8. For what value of x is ABCD a rhombus.
 one year ago
 one year ago

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mathstudent55Best ResponseYou've already chosen the best response.1
In a rhombus, each diagonal bisects a pair of opposite angles.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
I keep getting 6 at the very end, is that correct?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
No, x is not 6. How did you set up your equation?
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
Show me the equation you are trying to solve.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
2x + 4=2 + 5x8=3 then 3+2=5 This is what my teacher taught me but it just doesnt seem right
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means: 2x + 4 = 5x  8 This is the equation you must solve.
 one year ago

Kagome_gurl8Best ResponseYou've already chosen the best response.0
You should be a teacher.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part
 one year ago
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