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anonymous
 4 years ago
In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x8. For what value of x is ABCD a rhombus.
anonymous
 4 years ago
In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x8. For what value of x is ABCD a rhombus.

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mathstudent55
 4 years ago
Best ResponseYou've already chosen the best response.1In a rhombus, each diagonal bisects a pair of opposite angles.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I keep getting 6 at the very end, is that correct?

mathstudent55
 4 years ago
Best ResponseYou've already chosen the best response.1No, x is not 6. How did you set up your equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5

mathstudent55
 4 years ago
Best ResponseYou've already chosen the best response.1Show me the equation you are trying to solve.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x + 4=2 + 5x8=3 then 3+2=5 This is what my teacher taught me but it just doesnt seem right

mathstudent55
 4 years ago
Best ResponseYou've already chosen the best response.1Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means: 2x + 4 = 5x  8 This is the equation you must solve.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You should be a teacher.

mathstudent55
 4 years ago
Best ResponseYou've already chosen the best response.1Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part
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