Kagome_gurl8
In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x8. For what value of x is ABCD a rhombus.



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Kagome_gurl8
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mathstudent55
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In a rhombus, each diagonal bisects a pair of opposite angles.

Kagome_gurl8
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I keep getting 6 at the very end, is that correct?

mathstudent55
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No, x is not 6. How did you set up your equation?

Kagome_gurl8
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I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5

mathstudent55
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Show me the equation you are trying to solve.

Kagome_gurl8
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2x + 4=2 + 5x8=3 then 3+2=5
This is what my teacher taught me but it just doesnt seem right

mathstudent55
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Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means:
2x + 4 = 5x  8
This is the equation you must solve.

Kagome_gurl8
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4

mathstudent55
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Correct

Kagome_gurl8
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You should be a teacher.

mathstudent55
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Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part

micahm
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@jolenewhite.2000