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Kagome_gurl8

  • 2 years ago

In quadrilateral ABCD, m∠ACD = 2x + 4 and m∠ACB = 5x-8. For what value of x is ABCD a rhombus.

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  1. Kagome_gurl8
    • 2 years ago
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  2. mathstudent55
    • 2 years ago
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    In a rhombus, each diagonal bisects a pair of opposite angles.

  3. Kagome_gurl8
    • 2 years ago
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    I keep getting 6 at the very end, is that correct?

  4. mathstudent55
    • 2 years ago
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    No, x is not 6. How did you set up your equation?

  5. Kagome_gurl8
    • 2 years ago
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    I'm doing what my teacher says, solve both equations for x then adding them together. I did just redo it the way he told me to and i got 5

  6. mathstudent55
    • 2 years ago
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    Show me the equation you are trying to solve.

  7. Kagome_gurl8
    • 2 years ago
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    2x + 4=2 + 5x-8=3 then 3+2=5 This is what my teacher taught me but it just doesnt seem right

  8. mathstudent55
    • 2 years ago
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    Since the diagonal bisects the opposite angles, that means m<ACD = m<ACB, which means: 2x + 4 = 5x - 8 This is the equation you must solve.

  9. Kagome_gurl8
    • 2 years ago
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    4

  10. mathstudent55
    • 2 years ago
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    Correct

  11. Kagome_gurl8
    • 2 years ago
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    You should be a teacher.

  12. mathstudent55
    • 2 years ago
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    Thanks. I hope you understood the problem. You need to take the understanding of the geometry part to then handle the algebra part

  13. micahm
    • 5 months ago
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    @jolenewhite.2000

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