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ValentinaT

Can someone check my work?

  • one year ago
  • one year ago

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  1. hba
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    Sure thing.

    • one year ago
  2. ValentinaT
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    I have to solve systems of equations, and I chose the elimination method, but for some reason the last step isn't working. b) 7x – 3y = 20 5x + 3y = 16 Elimination Method 7x – 3y = 20 5x + 3y = 16 So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16

    • one year ago
  3. hba
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    ^ This

    • one year ago
  4. hba
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    Is actually messed up.

    • one year ago
  5. ValentinaT
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    Could you show me where i went wrong?

    • one year ago
  6. hba
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    I cannot understand how many ques you have posted up there . Can you please post one ques at a time.

    • one year ago
  7. ValentinaT
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    I only posted one question..? I just asked if you could show me where in the problem did I do something wrong.

    • one year ago
  8. hba
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    What are the equations and what is your answer for that.

    • one year ago
  9. hba
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    I am sorry i am having a hard time understanding what you hav done above.@ValentinaT

    • one year ago
  10. ValentinaT
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    Okay. The equation is: 7x – 3y = 20 5x + 3y = 16 I used the elimination method of solving systems to solve it. So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16

    • one year ago
  11. ciara_chap3
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    your answer should be x=3 y=1/3

    • one year ago
  12. ValentinaT
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    A fraction for y?

    • one year ago
  13. hba
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    15+3y=16 1)subract both sides by 15 2)divide both sides by 3

    • one year ago
  14. hba
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    There can be a fraction and you can always check by putting the (x,y) value in your orignal equation and checking If, LHS=RHS then your answer is correct :)

    • one year ago
  15. ValentinaT
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    Thank you.

    • one year ago
  16. hba
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    Welcome :)

    • one year ago
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