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ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
I have to solve systems of equations, and I chose the elimination method, but for some reason the last step isn't working. b) 7x – 3y = 20 5x + 3y = 16 Elimination Method 7x – 3y = 20 5x + 3y = 16 So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Is actually messed up.
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Could you show me where i went wrong?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I cannot understand how many ques you have posted up there . Can you please post one ques at a time.
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
I only posted one question..? I just asked if you could show me where in the problem did I do something wrong.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
What are the equations and what is your answer for that.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I am sorry i am having a hard time understanding what you hav done above.@ValentinaT
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Okay. The equation is: 7x – 3y = 20 5x + 3y = 16 I used the elimination method of solving systems to solve it. So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16
 one year ago

ciara_chap3 Group TitleBest ResponseYou've already chosen the best response.1
your answer should be x=3 y=1/3
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
A fraction for y?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
15+3y=16 1)subract both sides by 15 2)divide both sides by 3
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
There can be a fraction and you can always check by putting the (x,y) value in your orignal equation and checking If, LHS=RHS then your answer is correct :)
 one year ago

ValentinaT Group TitleBest ResponseYou've already chosen the best response.0
Thank you.
 one year ago
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