A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Can someone check my work?
anonymous
 3 years ago
Can someone check my work?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have to solve systems of equations, and I chose the elimination method, but for some reason the last step isn't working. b) 7x – 3y = 20 5x + 3y = 16 Elimination Method 7x – 3y = 20 5x + 3y = 16 So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Could you show me where i went wrong?

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I cannot understand how many ques you have posted up there . Can you please post one ques at a time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I only posted one question..? I just asked if you could show me where in the problem did I do something wrong.

hba
 3 years ago
Best ResponseYou've already chosen the best response.0What are the equations and what is your answer for that.

hba
 3 years ago
Best ResponseYou've already chosen the best response.0I am sorry i am having a hard time understanding what you hav done above.@ValentinaT

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. The equation is: 7x – 3y = 20 5x + 3y = 16 I used the elimination method of solving systems to solve it. So with the elimination method you want to manipulate one equation so that when you add the two equations together one will cancel out. You have: 7x – 3y = 20 5x + 3y = 16 Eliminate one variable. Since the sum of the coefficients of y is 0, add the equations to eliminate y. 7x – 3y = 20 5x + 3y = 16 12x = 36 Now we can find: x = 3 In order to solve for y, take the value for x and substitute it back into either one of the original equations. 5(3) + 3y = 16 15 + 3y = 16

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your answer should be x=3 y=1/3

hba
 3 years ago
Best ResponseYou've already chosen the best response.015+3y=16 1)subract both sides by 15 2)divide both sides by 3

hba
 3 years ago
Best ResponseYou've already chosen the best response.0There can be a fraction and you can always check by putting the (x,y) value in your orignal equation and checking If, LHS=RHS then your answer is correct :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.