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Rosy95Best ResponseYou've already chosen the best response.0
Find an expression equivalent to... dw:1358280084977:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
any expression? or is this something needing to involve a certain method? There's a number of ways to find an equivalent.
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
I am not sure. The answer choice are... A. sec^2 theta B. cot theta C. tan^2 theta D. cos^2 theta
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358280261643:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358280353086:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
Oh, my pictures got cut off, but the math is easy to see if you know definitions of trig functions and basic algebra skills.
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
Yes I can see. Thanks for writing out the equations. So the answer would be A. sec^2 theta?
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358280516292:dw
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
So can you help with another one?
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
YEs. Post a new question
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
Simplifydw:1358281039137:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
Tan^2theta + 1 = sec^2theta This is very useful to remember.
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
And can you check a question? The question is Which expression is equivalent to cos(pitheta)? I got cos theta. Is that right?
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
I'll answer that one quickly before I finish your first problem.
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358281166638:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
Another good rule to remember. So, yes your answer is correct.
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
Thanks and for my second question, I am still confused. Can you explain more? It was the simplify one
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358281344118:dw
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
dw:1358281440642:dw
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
Oh ok. So since cos^2 theta can be crossed out, you move the 1st numerator over the 2nd denominator. That makes more sense. Thanks!
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
Well, it's not being crossed out. It's cos^2 theta divided by itself which is one. And then as fractions go, numerator times numerator and denominator times denominator.
 one year ago

Rosy95Best ResponseYou've already chosen the best response.0
Oh ok, Do you know how to do this one.... Solve \[4\sin ^{2}x+4\sqrt{2}cosx6=0\]
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.1
Post this one as a new question up top and close this question.
 one year ago
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