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Rosy95

  • 3 years ago

Please help on PreCal

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  1. cgreenwade2000
    • 3 years ago
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    Ok go

  2. Rosy95
    • 3 years ago
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    Find an expression equivalent to... |dw:1358280084977:dw|

  3. cgreenwade2000
    • 3 years ago
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    any expression? or is this something needing to involve a certain method? There's a number of ways to find an equivalent.

  4. Rosy95
    • 3 years ago
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    I am not sure. The answer choice are... A. sec^2 theta B. cot theta C. tan^2 theta D. cos^2 theta

  5. cgreenwade2000
    • 3 years ago
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    |dw:1358280261643:dw|

  6. cgreenwade2000
    • 3 years ago
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    |dw:1358280353086:dw|

  7. cgreenwade2000
    • 3 years ago
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    Oh, my pictures got cut off, but the math is easy to see if you know definitions of trig functions and basic algebra skills.

  8. Rosy95
    • 3 years ago
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    Yes I can see. Thanks for writing out the equations. So the answer would be A. sec^2 theta?

  9. cgreenwade2000
    • 3 years ago
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    |dw:1358280516292:dw|

  10. Rosy95
    • 3 years ago
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    So can you help with another one?

  11. cgreenwade2000
    • 3 years ago
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    YEs. Post a new question

  12. Rosy95
    • 3 years ago
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    Simplify|dw:1358281039137:dw|

  13. cgreenwade2000
    • 3 years ago
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    Tan^2theta + 1 = sec^2theta This is very useful to remember.

  14. Rosy95
    • 3 years ago
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    And can you check a question? The question is Which expression is equivalent to cos(pi-theta)? I got -cos theta. Is that right?

  15. cgreenwade2000
    • 3 years ago
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    I'll answer that one quickly before I finish your first problem.

  16. cgreenwade2000
    • 3 years ago
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    |dw:1358281166638:dw|

  17. cgreenwade2000
    • 3 years ago
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    Another good rule to remember. So, yes your answer is correct.

  18. Rosy95
    • 3 years ago
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    Thanks and for my second question, I am still confused. Can you explain more? It was the simplify one

  19. cgreenwade2000
    • 3 years ago
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    |dw:1358281344118:dw|

  20. cgreenwade2000
    • 3 years ago
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    |dw:1358281440642:dw|

  21. Rosy95
    • 3 years ago
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    Oh ok. So since cos^2 theta can be crossed out, you move the 1st numerator over the 2nd denominator. That makes more sense. Thanks!

  22. cgreenwade2000
    • 3 years ago
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    Well, it's not being crossed out. It's cos^2 theta divided by itself which is one. And then as fractions go, numerator times numerator and denominator times denominator.

  23. Rosy95
    • 3 years ago
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    Oh ok, Do you know how to do this one.... Solve \[4\sin ^{2}x+4\sqrt{2}cosx-6=0\]

  24. cgreenwade2000
    • 3 years ago
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    Post this one as a new question up top and close this question.

  25. Rosy95
    • 3 years ago
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    ok

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