Please help on PreCal

- anonymous

Please help on PreCal

- katieb

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- cgreenwade2000

Ok go

- anonymous

Find an expression equivalent to... |dw:1358280084977:dw|

- cgreenwade2000

any expression? or is this something needing to involve a certain method?
There's a number of ways to find an equivalent.

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## More answers

- anonymous

I am not sure. The answer choice are...
A. sec^2 theta
B. cot theta
C. tan^2 theta
D. cos^2 theta

- cgreenwade2000

|dw:1358280261643:dw|

- cgreenwade2000

|dw:1358280353086:dw|

- cgreenwade2000

Oh, my pictures got cut off, but the math is easy to see if you know definitions of trig functions and basic algebra skills.

- anonymous

Yes I can see. Thanks for writing out the equations. So the answer would be A. sec^2 theta?

- cgreenwade2000

|dw:1358280516292:dw|

- anonymous

So can you help with another one?

- cgreenwade2000

YEs. Post a new question

- anonymous

Simplify|dw:1358281039137:dw|

- cgreenwade2000

Tan^2theta + 1 = sec^2theta
This is very useful to remember.

- anonymous

And can you check a question? The question is Which expression is equivalent to cos(pi-theta)? I got -cos theta. Is that right?

- cgreenwade2000

I'll answer that one quickly before I finish your first problem.

- cgreenwade2000

|dw:1358281166638:dw|

- cgreenwade2000

Another good rule to remember. So, yes your answer is correct.

- anonymous

Thanks and for my second question, I am still confused. Can you explain more? It was the simplify one

- cgreenwade2000

|dw:1358281344118:dw|

- cgreenwade2000

|dw:1358281440642:dw|

- anonymous

Oh ok. So since cos^2 theta can be crossed out, you move the 1st numerator over the 2nd denominator. That makes more sense. Thanks!

- cgreenwade2000

Well, it's not being crossed out. It's cos^2 theta divided by itself which is one. And then as fractions go, numerator times numerator and denominator times denominator.

- anonymous

Oh ok, Do you know how to do this one....
Solve \[4\sin ^{2}x+4\sqrt{2}cosx-6=0\]

- cgreenwade2000

Post this one as a new question up top and close this question.

- anonymous

ok

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