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Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Solve\[4\sin^2x+4\sqrt{2} cosx6=0\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0the question is not here ! or i do not see it

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0I just posted it before you wrote your comment

hba
 one year ago
Best ResponseYou've already chosen the best response.0@amoodarya Refresh your page

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1Substitute in for the value of sin^2(x) You know what it is?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Substitute it where? I am still confused.

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1sin^2(x) can be put in terms of cos^2(x)

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1sin^2(x) = 1cos^2 (x) Another really important one to remember. (I hope you're writing these important ones down, especially if you plan on going further in calculus)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then put cos x =y and you get a Quadratic in 'y', which can be solved easily.

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1I wasn't going to suggest that.......but it makes it a lot easier. Go that route.

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1Don't forget to distribute when you substitute for sin^2(x)

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0wait so is the new equation\[4( \frac{ 1 }{\cos^2x }) + 4 \sqrt{2}cosx6=0\]

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.14(1cos^2x).......

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1actually, \[\huge \color{red}{\sin^2x+\cos^2x=1 \\ \implies \sin^2x =1\cos^2x}\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0no dw:1358282546908:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge \color{red}{\sin^2x+\cos^2x=1 \\ \implies \sin^2x =1\cos^2x \\ \implies 4\sin^2x=44\cos^2x}\]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358282634437:dw

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Can you rewrite that? It is hard to read

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\[4\sin^2x+4\sqrt{2} cosx6=0 \\ 44\cos^2x+4\sqrt{2} cosx6=0\\4\cos^2x4\sqrt{2} cosx+2=0 \\put \cos x=y \\ \implies 4y^24\sqrt2y+2=0\] can you solve this quadratic ?

cgreenwade2000
 one year ago
Best ResponseYou've already chosen the best response.1That should be a 2 @hartnn

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0ok so the answer is \[\frac{ \pi }{4 }+2\pi k, \frac{ 7\pi }{4 }+2\pi k\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1how did u get that ? what values of y u got ?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358282921662:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1@Rosy95 did you actually solve it ?

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0dw:1358283161601:dw

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Im' sorry, I forgot to include the rest of the question...it is solve (that long equation) for all real values of x.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1@Rosy95 what answer you wrote is correct. did you solve it by yourself ? and any doubts anywhere ?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0I solved it by myself but i looked at the answer choices when I got half of it.
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