## js64 Group Title sq root of x + 10 = x -2 one year ago one year ago

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1. Rosy95 Group Title

$\sqrt{x+10}=x-2$ Is this the equation? Are you looking for the value of x?

2. js64 Group Title

yes

3. hartnn Group Title

the first step is to square both sides,

4. Rosy95 Group Title

$\sqrt{x+10}=x-2$ $(\sqrt{x+10})^2=(x-2)^2$ $x+10=x^2+4$ $x+6=x^2$ You should be able to solve the rest now

5. hartnn Group Title

$(x-2)^2=x^2-4x+4$

6. hartnn Group Title

$x+10 = x^2-4x+4$

7. js64 Group Title

k

8. Rosy95 Group Title

Yes sorry misread that hartnn has the last step

9. Rosy95 Group Title

so then you get $x-6=x^2-4x$ and solve from there

10. hartnn Group Title

$x+6=x^2-4x$

11. hartnn Group Title

$x^2-5x-6=0$ can you solve this quadratic ?