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js64

  • 2 years ago

sq root of x + 10 = x -2

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  1. Rosy95
    • 2 years ago
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    \[\sqrt{x+10}=x-2\] Is this the equation? Are you looking for the value of x?

  2. js64
    • 2 years ago
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    yes

  3. hartnn
    • 2 years ago
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    the first step is to square both sides,

  4. Rosy95
    • 2 years ago
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    \[\sqrt{x+10}=x-2\] \[(\sqrt{x+10})^2=(x-2)^2\] \[x+10=x^2+4\] \[x+6=x^2\] You should be able to solve the rest now

  5. hartnn
    • 2 years ago
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    \[(x-2)^2=x^2-4x+4\]

  6. hartnn
    • 2 years ago
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    \[x+10 = x^2-4x+4\]

  7. js64
    • 2 years ago
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    k

  8. Rosy95
    • 2 years ago
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    Yes sorry misread that hartnn has the last step

  9. Rosy95
    • 2 years ago
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    so then you get \[x-6=x^2-4x\] and solve from there

  10. hartnn
    • 2 years ago
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    \[x+6=x^2-4x\]

  11. hartnn
    • 2 years ago
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    \[x^2-5x-6=0\] can you solve this quadratic ?

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