A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Solve csc x + 2 = 0 for 0 < x < 2pi. I think it is 7pi/6 and 11pi/6

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so you have csc(x) = 2 so sin(x) = 1/2 this is 3rd and 4th quadrants so pi + pi/6 = 7pi/6 (3rd quadrant) 2pi  pi/6 = 11pi/6 (4th Quadrant) so you solution looks great... well done

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0Thanks. Can you help with this one though, I am confused. Solve 2 sin x + sqrt(3) < 0 for 0 x < 2.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1ok... so you will start with \[2\sin(x) < \sqrt{3} \] so \[\sin(x) <  \frac{\sqrt{3}}{2}\] so aren't there 2 inequaitites to this in the 3rd quadrant \[\pi < x < \frac{4\pi}{3}\] and the 4th quadrant \[\frac{5\pi}{3} < x < 2\pi\] tough question, I not really confident on the solutions...

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.0The answer choices are \[\frac{ 4\pi }{3 } < x < \frac{ 5\pi }{ 3 }\] \[\frac{ 2\pi }{3 } < x < \frac{ 4\pi }{ 3 }\] \[\frac{ 7\pi }{6 } < x < \frac{ 11\pi }{ 6 }\] \[\frac{ 5\pi }{6 } < x < \frac{ 7\pi }{ 6 }\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1that would be my best guess... but its only a guess...
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.