mlddmlnog
find all values x* described in the mean value theorem for integrals.
f(x)=s/x^2 [1,3]



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mlddmlnog
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dw:1358283986640:dw

mlddmlnog
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@zepdrix

amoodarya
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dw:1358284021076:dw

amoodarya
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dw:1358284117061:dw

mlddmlnog
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i really appreciate your help, but i'm having a little trouble reading your work.. :'(

amoodarya
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dw:1358284164559:dw

mlddmlnog
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i'still not comprehending... it's really hard to understand your work.. :"(

amoodarya
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mlddmlnog
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thank you.. but anyone else know how ot do this differently? or clearly? :D

amoodarya
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which part of that is complicated for you ?

mlddmlnog
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the formula you used, which is different from what i have on my review sheet, and i still can't read someof your work :'(

mlddmlnog
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ah.., let me try this myself :) i think i now get what you did!

amoodarya
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mlddmlnog
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ok, i dont.get.this. where did the "S" come from?

amoodarya
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s in figure is area of f(x)

mlddmlnog
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could you try doing it without the "s"?

amoodarya
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yeah without s
i.e. f(x)= 1/x^2 ?

mlddmlnog
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yes :)

amoodarya
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amoodarya
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look
if ok go on

mlddmlnog
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oh... ok. im gonna have lf again. thank you:)

mlddmlnog
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i meant try myself again.

amoodarya
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do you know the mean value of integrals theory?

mlddmlnog
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ok, so here is what i did. \[\frac{ 1 }{ 31 }\int\limits_{1}^{3}\frac{ 1 }{ x ^{x} }dx = \frac{ 1 }{ 2 }\int\limits_{1}^{3}x ^{2}dx ^{}\]
\[\frac{ 1 }{ 2 }(x ^{1})\]from 1 to 3,
\[\frac{ 1 }{ 2 }(3^{1}+1^{1}) = \frac{ 1 }{ 2 }(\frac{ 1 }{ 3 }+\frac{ 1 }{ 1 }) = \frac{ 1 }{ 2 }(\frac{ 2 }{ 3 })=\frac{ 1 }{ 3 }\]

mlddmlnog
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and i dont know what to do next. but i do know that i have found(x*) so far.