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 one year ago
Your school drama club is putting on a play and hopes to raise $600 from ticket sales. They sell adult tickets for $8 each and student tickets for $5 each. Let x represent the number of adult tickets and y represent the number of student tickets. The equation to represent the number of tickets sold to reach their goal, 8x+ 5y = 600, is graphed below. If 40 adult tickets are sold, how many student tickets must be sold to reach their goal?
 one year ago
Your school drama club is putting on a play and hopes to raise $600 from ticket sales. They sell adult tickets for $8 each and student tickets for $5 each. Let x represent the number of adult tickets and y represent the number of student tickets. The equation to represent the number of tickets sold to reach their goal, 8x+ 5y = 600, is graphed below. If 40 adult tickets are sold, how many student tickets must be sold to reach their goal?

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mayrabris2cute
 one year ago
Best ResponseYou've already chosen the best response.1OK! Hold on. I'm solving :)

mayrabris2cute
 one year ago
Best ResponseYou've already chosen the best response.156 student tickets must be sold to reach the goal

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.08x + 5y = 600 8(40) + 5y = 600 320 + 5y = 600 5y = 600  320 5y = 280 x = 56 ANSWER : 56 student must be sold to reach their goal.

mayrabris2cute
 one year ago
Best ResponseYou've already chosen the best response.1Becauseee!!! Adult: $8 * 40 = 320. So you already have 320. 600  320 = 280. Divide that by 5, and you get 56 :) I was first to answer :)

haleylooove
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you! could you help me with this one also? please! The local gym charges members a monthly fee of $50 plus an additional $2 every time you want to use the pool. Let p represent the number of times you used the pool in one month and C represent the total cost for your monthly membership. Write an equation to find the total cost of your monthly membership to the gym.

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0she is right....she was first...lol

mayrabris2cute
 one year ago
Best ResponseYou've already chosen the best response.1I'm sorry! I gtg and can't help with the other one but I'm sure @texaschic101 could totally handle it :) :)
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