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\[\frac{ x-7 }{ x }+2=\frac{ x-3 }{ }\]

is there something missing on the right side? Is anything below x-3 ?

sorry x

x−7 x−3
---- +2= ----
x x

ok \[\frac{ x(x-7) }{ x^2 } = (\frac{ x(x-3) }{ x^2 })\]

but how would i multiply the equation?

x^2-3x over x?