Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Spartan_Of_Ares

  • one year ago

can i get help with some algebra 1?

  • This Question is Open
  1. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{ x-7 }{ x }+2=\frac{ x-3 }{ }\]

  2. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is there something missing on the right side? Is anything below x-3 ?

  3. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry x

  4. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x−7 x−3 ---- +2= ---- x x

  5. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    my first thought is to multiply both sides by x like this \[ x \cdot \left(\frac{(x-7)}{x} +2\right)= x \cdot \frac{(x-3)}{x} \]

  6. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok \[\frac{ x(x-7) }{ x^2 } = (\frac{ x(x-3) }{ x^2 })\]

  7. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    interesting... time to learn a few algebra rules. First, \[ c\cdot \frac{a}{b} \text{ is the same as } \frac{c}{1}\cdot \frac{a}{b}\] you multiply top times top and bottom times bottom so for the right hand side \[ x \cdot \frac{(x-3)}{x} \] you could write it as \[ \frac{x(x-3)}{x}\] but the x on top and the x on the bottom make \[ \frac{x}{x} = 1\] anything divided by itself is 1

  8. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but how would i multiply the equation?

  9. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    start with \[ x \cdot \left(\frac{(x-7)}{x} +2\right)= x \cdot \frac{(x-3)}{x} \] what do you get for the right-hand side of the = ? We'll get to the left after we get the right side done

  10. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x^2-3x over x?

  11. Spartan_Of_Ares
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @phi

  12. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, but you should always look for the same thing in the top and bottom, because they divide out. so rather than doing x(x-3)/x --> (x^2 -3x)/x (which is correct) you should say: \[ \frac{\cancel{x}(x-3)}{\cancel{x}} = (x-3) \]

  13. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[ x \cdot \left(\frac{(x-7)}{x} +2\right)= x -3 \] on the left side, "distribute the x". that means multiply all the terms inside the parens by x (don't forget the 2) and notice that you will get x/x so you can cancel them.

  14. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.