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anonymous
 3 years ago
can i get help with some algebra 1?
anonymous
 3 years ago
can i get help with some algebra 1?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x7 }{ x }+2=\frac{ x3 }{ }\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.0is there something missing on the right side? Is anything below x3 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x−7 x−3  +2=  x x

phi
 3 years ago
Best ResponseYou've already chosen the best response.0my first thought is to multiply both sides by x like this \[ x \cdot \left(\frac{(x7)}{x} +2\right)= x \cdot \frac{(x3)}{x} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok \[\frac{ x(x7) }{ x^2 } = (\frac{ x(x3) }{ x^2 })\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.0interesting... time to learn a few algebra rules. First, \[ c\cdot \frac{a}{b} \text{ is the same as } \frac{c}{1}\cdot \frac{a}{b}\] you multiply top times top and bottom times bottom so for the right hand side \[ x \cdot \frac{(x3)}{x} \] you could write it as \[ \frac{x(x3)}{x}\] but the x on top and the x on the bottom make \[ \frac{x}{x} = 1\] anything divided by itself is 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but how would i multiply the equation?

phi
 3 years ago
Best ResponseYou've already chosen the best response.0start with \[ x \cdot \left(\frac{(x7)}{x} +2\right)= x \cdot \frac{(x3)}{x} \] what do you get for the righthand side of the = ? We'll get to the left after we get the right side done

phi
 3 years ago
Best ResponseYou've already chosen the best response.0yes, but you should always look for the same thing in the top and bottom, because they divide out. so rather than doing x(x3)/x > (x^2 3x)/x (which is correct) you should say: \[ \frac{\cancel{x}(x3)}{\cancel{x}} = (x3) \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.0\[ x \cdot \left(\frac{(x7)}{x} +2\right)= x 3 \] on the left side, "distribute the x". that means multiply all the terms inside the parens by x (don't forget the 2) and notice that you will get x/x so you can cancel them.
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