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Faman39

  • one year ago

Please help me to understand and solve these!

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  1. Faman39
    • one year ago
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  2. Faman39
    • one year ago
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    @mathmate can you able to help me with this?

  3. mathmate
    • one year ago
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    DId you work out the solutions to each of the inequalities?

  4. Faman39
    • one year ago
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    I didnt understand completely those problem, thats y

  5. mathmate
    • one year ago
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    Solve them as equations, and since they are <, so you need any answer that is smaller the equality.

  6. Faman39
    • one year ago
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    I cant really get it how to do it, but i did somehow, where i got half n half write. I need to understand whole n how to find the rite answer

  7. mathmate
    • one year ago
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    The questions are all inequalities. Say you solve the first one as an equality: -2(1+z)+5z+5<11 -2-2z+4z+5<11 2z<11-3=8, or z<4 So any of the answers will fit for #1. Now proceed with #2, #3, #4 and try to move a,b,c,d around so that ALL the inequalities are satisfied.

  8. Faman39
    • one year ago
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    cqn you wait, cuz i m gonna show you those.

  9. Faman39
    • one year ago
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    First one will fit on which one, would it be 2

  10. mathmate
    • one year ago
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    Because they are not equations, but inequalities, you are better of doing all 4 of them before fitting anything. For example, all the answers a,b,c,d will fit in the first. So you don't know which one to choose until you have all 4 inequalities solved.

  11. mathmate
    • one year ago
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    Note: inequalities have multiple answers.

  12. Faman39
    • one year ago
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    So but i want to how will i get this answer matching correct answer

  13. Faman39
    • one year ago
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    Of all of them

  14. mathmate
    • one year ago
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    Let say if you have a set of answers 1,3,5,7 and solutions to equations which are x<2,x<6,x<8,x<4 Then your choice would be to fit 1<2, 5<6, 7<8,3<4, or else you would have one left over such as: 1<2,3<6,5<8, but 7>4 will not work. That's why you need to work out all four before you can match.

  15. Faman39
    • one year ago
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    Ok so, -2 (1 + z) +4z +5 <11 -2 + -2z + 4z + 5 <11 -2 + 2z + 5<11 so does it mean 2 will match or no?

  16. mathmate
    • one year ago
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    You have to solve it completely, -2+2z+5<11 2z+3<11 2z<8 z<4 Now you still have to solve the other three before you can start matching.

  17. Faman39
    • one year ago
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    that 2 match with this one right?

  18. mathmate
    • one year ago
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    All four answers will match with this one. If you want to take a chance, choose the highest number that will match. But I suggest you work out ALL 4 inequalities, then match. That will be much more sure.

  19. mathmate
    • one year ago
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    all four will match, because 3<4 -3<4 2<4 0<4 . That is why I suggest you work out all four inequalities before matching.

  20. Faman39
    • one year ago
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    All does not matched up, thats y, i m asking, how will i figure out all this

  21. mathmate
    • one year ago
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    If you want, you can pick 2<4. If you choose now, the rest may or may not work.

  22. mathmate
    • one year ago
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    1. Solve all FOUR inequalities, so you have 4 inequalities in hand, such as z<4 z< ? z< ? z< ? 2. Match the 4 given answers so that EVERY inequality works.

  23. Faman39
    • one year ago
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    Second will be -3, am i right?

  24. mathmate
    • one year ago
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    I'm afraid not. You have a problem with the sign.

  25. mathmate
    • one year ago
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    ...unless you mean -z>-3

  26. Faman39
    • one year ago
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    I was saying according that table which i showed

  27. Faman39
    • one year ago
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    So it suppose to match up with b -3

  28. Faman39
    • one year ago
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    right?

  29. mathmate
    • one year ago
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    Inequalities are not equations. Solutions must remain inequalities. So the second one must be given in the form z<-3, or z>3, or z<3. -3 would not be the solution to an inequality. Can you show your work?

  30. Faman39
    • one year ago
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    ok

  31. Faman39
    • one year ago
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    3z - 5z +10 - 8 <6

  32. mathmate
    • one year ago
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    3z - 5z +10 - 8 does not look right. Can you check?

  33. Faman39
    • one year ago
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    2z + 10 - 8 <6 so if this be 2, then other was not 2

  34. Faman39
    • one year ago
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    I cant really know how to do these all

  35. Faman39
    • one year ago
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    Problems seems really confusing to me

  36. mathmate
    • one year ago
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    3z - 5z +10 - 8 <6 is inorrect. it should be +5z and -10. How did you get the signs reversed?

  37. mathmate
    • one year ago
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    Or written in full 3z+5z-10-8<6

  38. Faman39
    • one year ago
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    so your saying it would match up with 3, right?

  39. Faman39
    • one year ago
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    Thats how we find the 3

  40. mathmate
    • one year ago
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    You are going to far with matching. You need to solve ALL 4 inequalities before you can match. the answer to the second is then....?

  41. mathmate
    • one year ago
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    I mean the \(solution\) to the second inequality is then....?

  42. Faman39
    • one year ago
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    I dont get at all how to last four, thats y i put their answer by guess, i m sure those last two were wrong but there is two matching which i gave, it was correct

  43. mathmate
    • one year ago
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    If you don't need all four correct, that's ok. Go ahead and do it your way. I have no problem with that. Good luck with your guesses. :)

  44. mathmate
    • one year ago
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    In mathematics, you are allowed to guess, but you also need a way to check your answer. If you cannot do both, then, sorry, guessing is not the right way.

  45. Faman39
    • one year ago
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    Thank you but all i wanted to know how to solve these, i havent done all by guess just two one which mite, but um not sure abt how to solve it to find exact answer to match. I just want to be clear abt all this

  46. Faman39
    • one year ago
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    I m not getting to find all of it exact answer

  47. mathmate
    • one year ago
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    I repeat: 1. Solve ALL four inequalities in the form z<4 z<3 z< ? z< / 2. THEN match the inequalities with the 4 given answers to make sure ALL inequalities are satisfied. I am still waiting for the solution to the second inequality after I have done the first one. If you have problems solving inequalities, that's where you need to work on.

  48. Faman39
    • one year ago
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    3z - 10 + 5z - 8 <6 3z + 5z + 10 - 8 <6 8z + 2<6

  49. Faman39
    • one year ago
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    8z + 2 - 2 <6 8z <6

  50. Faman39
    • one year ago
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    it will be a 0?

  51. Faman39
    • one year ago
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    No

  52. Faman39
    • one year ago
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    Please help!

  53. Faman39
    • one year ago
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    I dont understand how to solve all this

  54. Faman39
    • one year ago
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    @CalebBeavers help me please

  55. Faman39
    • one year ago
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    @phi

  56. Faman39
    • one year ago
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    Thank you so much for helping tolerating pain like me, i m sorry so for trouble. I really appreciate your help @mathmate, thanks alot! :)

  57. Faman39
    • one year ago
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    This one @experimentX

  58. experimentX
    • one year ago
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    first of all simplify the left side. Can you simplify \[ -2(1+z) + 4z + 5\]

  59. Faman39
    • one year ago
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    -2z + -2z + 4z +5 4z +4z +5 8z +5

  60. Faman39
    • one year ago
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    isnt it?

  61. experimentX
    • one year ago
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    nope!!

  62. experimentX
    • one year ago
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    \[ -2(1+z) = (-2) \times 1 + (-2) \times z = ?\]

  63. Faman39
    • one year ago
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    -2 +2z = -2 (-2) X z = -2 + 2z = -4 X z I m stuck :( sorry

  64. Faman39
    • one year ago
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    -2

  65. experimentX
    • one year ago
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    \[ -2 \times z = ?\]

  66. Faman39
    • one year ago
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    -2z

  67. experimentX
    • one year ago
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    -2 + (-2z)= ?

  68. Faman39
    • one year ago
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    4z?

  69. experimentX
    • one year ago
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    no ... you cannot add like that.

  70. experimentX
    • one year ago
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    |dw:1358353383731:dw|

  71. experimentX
    • one year ago
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    do you know how to take common?

  72. Faman39
    • one year ago
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    3x + 3x

  73. experimentX
    • one year ago
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    |dw:1358353592998:dw|

  74. Faman39
    • one year ago
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    5x

  75. experimentX
    • one year ago
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    yes!!

  76. experimentX
    • one year ago
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    1$ + 2$ = 3$ 1$ + 2 pound = 3$ ------------------ which of above is correct?

  77. Faman39
    • one year ago
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    3?

  78. Faman39
    • one year ago
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    both are same

  79. experimentX
    • one year ago
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    what is the name of your currency?

  80. Faman39
    • one year ago
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    pound

  81. experimentX
    • one year ago
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    okay .. is 1 dollar + 2 pound = 3 dollar ?

  82. Faman39
    • one year ago
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    no

  83. experimentX
    • one year ago
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    is that correct?

  84. Faman39
    • one year ago
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    no

  85. experimentX
    • one year ago
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    why not?

  86. Faman39
    • one year ago
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    Both are not similar

  87. experimentX
    • one year ago
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    yep!! -2 + (-2z) here think of z as dollar and ... ther is nothing after -2 ... think of it as there is pound.

  88. Faman39
    • one year ago
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    So what i did on all that problems, so how do i match because, its seems tricky

  89. experimentX
    • one year ago
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    also I think there is no minus there. your first problem is \[ 2(1+z) + 4z+5 = ?\] Simplify this. thikn of \( 4z + 5\) as .. 4 dollar + 5 pound

  90. Faman39
    • one year ago
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    it cannot be added

  91. Faman39
    • one year ago
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    so the bracket one what we need to do

  92. experimentX
    • one year ago
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    at least you can make it a bit simpler.

  93. Faman39
    • one year ago
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    -2 + 2z +4z +5 - 2 + 6z +5

  94. Faman39
    • one year ago
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    ?

  95. experimentX
    • one year ago
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    quite not correct. + ( - 2z) = ?

  96. experimentX
    • one year ago
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    no ... |dw:1358354499867:dw|

  97. Faman39
    • one year ago
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    -2z

  98. Faman39
    • one year ago
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    so 2 match up with this?

  99. Faman39
    • one year ago
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    I meant, first problem

  100. experimentX
    • one year ago
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    okay now simplify the first problem.

  101. Faman39
    • one year ago
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    -2z + 5 < 11

  102. Faman39
    • one year ago
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    -2z < 6

  103. Faman39
    • one year ago
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    z < 6/-2 z < -3

  104. Faman39
    • one year ago
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    it is match up with b

  105. experimentX
    • one year ago
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    No ... you didn't do it correctly.

  106. Faman39
    • one year ago
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    divide both side

  107. Faman39
    • one year ago
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    right?

  108. Faman39
    • one year ago
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    i forgot, just did one side directly

  109. experimentX
    • one year ago
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    woops!! sorry ... your first problem. \[ -2(1+z) + 4z+5 = -(2(1+z)) + 4z+5 = -(2\times 1 + 2 \times z) + 4z + 5 \\ = -(2 + 2z) + 4z+5 = -2 - 2z + 4z+5 = (-2z+4z) + (-2+5) = 2z + 3\]

  110. experimentX
    • one year ago
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    do you understand the each step?

  111. Faman39
    • one year ago
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    but am i right with first one?

  112. experimentX
    • one year ago
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    did you get 2z+3?

  113. Faman39
    • one year ago
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    no i got -3

  114. experimentX
    • one year ago
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    2z+3 < 11 2z+3 - 3 < 11 - 3 2z . (1/2) < 8/2 = 4 http://www.wolframalpha.com/input/?i=-2%281%2Bz%29+%2B+4z%2B5+%3C%3D+11

  115. experimentX
    • one year ago
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    if you had done it correctly ... you should have got \[ z < 4 \]

  116. Faman39
    • one year ago
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    you are saying it match up 3

  117. Faman39
    • one year ago
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    right?

  118. experimentX
    • one year ago
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    yes copy these each step into your notebook and see if you understand each of these steps \[ \begin{align*} -2(1+z) + 4z+5 &= -2(1+z) + 4z+5 \\ &= -2(1+z) + 4z+5 \\ &= -(2(1+z)) + 4z+5 \\ &= -(2\times 1 + 2 \times z) + 4z + 5 \\ &= -(2 + 2z) + 4z+5 \\ &= -2 - 2z + 4z+5 \\ &= (-2z+4z) + (-2+5) \\ &= 2z + 3 \end{align*} \]

  119. Faman39
    • one year ago
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    thank you :) it making sense now

  120. Faman39
    • one year ago
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    thank you so much

  121. experimentX
    • one year ago
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    also if you have any misunderstanding ... don't hesitate to ask.

  122. Faman39
    • one year ago
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    can you show me other 3, if your not busy or if i didnt eaten up your head, i know i m painful, i hardly understand everything in math

  123. Faman39
    • one year ago
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    thats really horrible

  124. experimentX
    • one year ago
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    first simplify do 2nd and 4 th problem

  125. experimentX
    • one year ago
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    i think you are capable to do it .. also show me step!!

  126. Faman39
    • one year ago
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    3z + 5z - 10 - 8 < 6?

  127. experimentX
    • one year ago
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    yes go on!!

  128. Faman39
    • one year ago
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    8z - 10 - 8 <6 8z - 2 <6 8z <6 +2 8z < 8 z < 0

  129. experimentX
    • one year ago
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    http://www.wolframalpha.com/input/?i=3z+%2B+5z+-+10+-+8+%3C+6 watch your second step again.

  130. Faman39
    • one year ago
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    Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 1.5? :(

  131. experimentX
    • one year ago
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    8z - 18 < 6 add +18 to both sides.

  132. Faman39
    • one year ago
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    8z < 24 <3

  133. experimentX
    • one year ago
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    yes correct!! do the 4th problem similarly ... also note the mistake you made Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 (is 6-18 = 12 ??) 1.5? :( Get calculator. or watch your step agai.

  134. Faman39
    • one year ago
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    In third one, how do i start?

  135. experimentX
    • one year ago
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    watch the example i gave you!!

  136. Faman39
    • one year ago
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    I m so sorry, i m such a error maker, pls forgive me for all this trouble

  137. experimentX
    • one year ago
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    in which level do you study?

  138. Faman39
    • one year ago
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    no actually im in online high school, where i m takin blended course

  139. experimentX
    • one year ago
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    really? you got terrible math!! these are very very basic simple rules

  140. Faman39
    • one year ago
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    yes, im ok with other but worse in math

  141. experimentX
    • one year ago
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    okay try 3

  142. experimentX
    • one year ago
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    what did you put on 2?

  143. Faman39
    • one year ago
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    Z + 5 - ( 1 + 6z) > -1

  144. Faman39
    • one year ago
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    z +5 - 1 + 6z > -1

  145. experimentX
    • one year ago
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    there you have problem!! -(1+6z) = -1 times .. what's inside

  146. experimentX
    • one year ago
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    |dw:1358357567000:dw|

  147. Faman39
    • one year ago
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    -1 + -6z

  148. experimentX
    • one year ago
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    what is + - 6z = ?

  149. Faman39
    • one year ago
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    - 6z

  150. experimentX
    • one year ago
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    yes ... now simplify it

  151. Faman39
    • one year ago
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    7z

  152. experimentX
    • one year ago
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    again, you are not getting the point. look at the big picture. look again from where you started and where you ended. and check for errors.

  153. Faman39
    • one year ago
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    ok sorry

  154. Faman39
    • one year ago
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    z + 5 - -1 + -6z <1

  155. experimentX
    • one year ago
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    it's necessary that you write the whole step on some nontebook.

  156. experimentX
    • one year ago
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    *notebook ... if you rely on memory then you will never learn. also it's necessary that you have to look at your previous step.

  157. Faman39
    • one year ago
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    ok sure, i will keep it mind. z + -6z + 5- + -1 5z + 6 < 1

  158. Faman39
    • one year ago
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    I know, something wrong in here again

  159. Faman39
    • one year ago
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    5z < 1 - 6 5z < 5 1

  160. Faman39
    • one year ago
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    <1

  161. Faman39
    • one year ago
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    am i wrong?

  162. experimentX
    • one year ago
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    try pluggin that expression on Wolfram Alpha

  163. Faman39
    • one year ago
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    I dont know how to do it

  164. Faman39
    • one year ago
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    :(

  165. Faman39
    • one year ago
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    your saying negative

  166. experimentX
    • one year ago
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    how do you do with this \[ a + 2b - (3a+b) = a + 2b - 3a -b = a-3a+2b-b = -2a +b \]

  167. Faman39
    • one year ago
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    add by combining like term

  168. experimentX
    • one year ago
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    how did i get rid of -(3a+b) .. just do it like there.

  169. Faman39
    • one year ago
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    - 3a + b, we cant go more from this on it

  170. experimentX
    • one year ago
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    - 3a - b

  171. experimentX
    • one year ago
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    |dw:1358359171654:dw|

  172. Faman39
    • one year ago
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    so then your saying it will move to positive

  173. Faman39
    • one year ago
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    But i didnt understand how did operation + to - at middle

  174. Faman39
    • one year ago
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    Hows did you change and why?

  175. experimentX
    • one year ago
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    no ... |dw:1358359302646:dw|

  176. Faman39
    • one year ago
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    ok

  177. experimentX
    • one year ago
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    |dw:1358359471738:dw|

  178. Faman39
    • one year ago
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    not equal

  179. Faman39
    • one year ago
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    yes

  180. Faman39
    • one year ago
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    you multiplied - all on Bracket, thats y, everything -

  181. experimentX
    • one year ago
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    |dw:1358359803427:dw|

  182. Faman39
    • one year ago
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    - 3a + -2b

  183. experimentX
    • one year ago
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    tell me in terms of pounds and dollars .... how much should you give to me?

  184. Faman39
    • one year ago
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    3 dollar, 2 pounds

  185. experimentX
    • one year ago
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    isn't that equal to -3a-2b? what does this mean?

  186. experimentX
    • one year ago
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    |dw:1358360151961:dw|

  187. experimentX
    • one year ago
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    |dw:1358360292451:dw|

  188. experimentX
    • one year ago
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    Medals 1

    |dw:1358360405299:dw||dw:1358360432011:dw|

  189. Faman39
    • one year ago
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    got it now :) thank you

  190. Faman39
    • one year ago
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    thats y it was - 1, right

  191. experimentX
    • one year ago
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    Honestly, I feel like you are trolling with me!! right ... do the third number now and show it to me.

  192. Faman39
    • one year ago
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    I m extremely sorry for taking your time n making you crazy like this

  193. Faman39
    • one year ago
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    :( i m so sorry for everything

  194. Faman39
    • one year ago
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    - 7z - 19 + 19 < 5 +19 -7z + < 24 got long decimal number

  195. experimentX
    • one year ago
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    you copied the wrong question. - 7z - 19 + 19 < -5 +19

  196. Faman39
    • one year ago
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    so first one was right ?

  197. Faman39
    • one year ago
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    which i showed you b4

  198. experimentX
    • one year ago
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    no you had +7z ...

  199. Faman39
    • one year ago
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    -8z - 19 + z > - 5

  200. Faman39
    • one year ago
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    so -7z + 19 < 5 - 7z + 19 - 19 < 5-19 -7z < 14 z < -2

  201. experimentX
    • one year ago
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    well ... done!! gotta go ... i strongly suggest that you get a pencil and notebook and practice few similar problems.

  202. Faman39
    • one year ago
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    Thank you so much! im sorry again for trouble :(

  203. experimentX
    • one year ago
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    I am not in trouble ,,, you might be in math test!! so pratice well!!

  204. Faman39
    • one year ago
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    yes, i was trying understand these so that i dont make mistake again like this

  205. Faman39
    • one year ago
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    Last one match up with 2, right, just to be confirmed

  206. Faman39
    • one year ago
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    i m extremely apologize for giving you trouble @experimentX. thank you so much for helping me alot! you really saved me explaining all of it. I m really very sorry horribly troubling you

  207. Faman39
    • one year ago
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    You are really amazing, thank you so much for make me understand abt all of it without being tired. your truly great, thanks alot @experimentX

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