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Faman39
 4 years ago
Please help me to understand and solve these!
Faman39
 4 years ago
Please help me to understand and solve these!

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Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0@mathmate can you able to help me with this?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1DId you work out the solutions to each of the inequalities?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I didnt understand completely those problem, thats y

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Solve them as equations, and since they are <, so you need any answer that is smaller the equality.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I cant really get it how to do it, but i did somehow, where i got half n half write. I need to understand whole n how to find the rite answer

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1The questions are all inequalities. Say you solve the first one as an equality: 2(1+z)+5z+5<11 22z+4z+5<11 2z<113=8, or z<4 So any of the answers will fit for #1. Now proceed with #2, #3, #4 and try to move a,b,c,d around so that ALL the inequalities are satisfied.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0cqn you wait, cuz i m gonna show you those.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0First one will fit on which one, would it be 2

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Because they are not equations, but inequalities, you are better of doing all 4 of them before fitting anything. For example, all the answers a,b,c,d will fit in the first. So you don't know which one to choose until you have all 4 inequalities solved.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Note: inequalities have multiple answers.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0So but i want to how will i get this answer matching correct answer

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Let say if you have a set of answers 1,3,5,7 and solutions to equations which are x<2,x<6,x<8,x<4 Then your choice would be to fit 1<2, 5<6, 7<8,3<4, or else you would have one left over such as: 1<2,3<6,5<8, but 7>4 will not work. That's why you need to work out all four before you can match.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Ok so, 2 (1 + z) +4z +5 <11 2 + 2z + 4z + 5 <11 2 + 2z + 5<11 so does it mean 2 will match or no?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1You have to solve it completely, 2+2z+5<11 2z+3<11 2z<8 z<4 Now you still have to solve the other three before you can start matching.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0that 2 match with this one right?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1All four answers will match with this one. If you want to take a chance, choose the highest number that will match. But I suggest you work out ALL 4 inequalities, then match. That will be much more sure.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1all four will match, because 3<4 3<4 2<4 0<4 . That is why I suggest you work out all four inequalities before matching.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0All does not matched up, thats y, i m asking, how will i figure out all this

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1If you want, you can pick 2<4. If you choose now, the rest may or may not work.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.11. Solve all FOUR inequalities, so you have 4 inequalities in hand, such as z<4 z< ? z< ? z< ? 2. Match the 4 given answers so that EVERY inequality works.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Second will be 3, am i right?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1I'm afraid not. You have a problem with the sign.

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1...unless you mean z>3

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I was saying according that table which i showed

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0So it suppose to match up with b 3

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Inequalities are not equations. Solutions must remain inequalities. So the second one must be given in the form z<3, or z>3, or z<3. 3 would not be the solution to an inequality. Can you show your work?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.13z  5z +10  8 does not look right. Can you check?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.02z + 10  8 <6 so if this be 2, then other was not 2

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I cant really know how to do these all

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Problems seems really confusing to me

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.13z  5z +10  8 <6 is inorrect. it should be +5z and 10. How did you get the signs reversed?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1Or written in full 3z+5z108<6

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so your saying it would match up with 3, right?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Thats how we find the 3

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1You are going to far with matching. You need to solve ALL 4 inequalities before you can match. the answer to the second is then....?

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1I mean the \(solution\) to the second inequality is then....?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I dont get at all how to last four, thats y i put their answer by guess, i m sure those last two were wrong but there is two matching which i gave, it was correct

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1If you don't need all four correct, that's ok. Go ahead and do it your way. I have no problem with that. Good luck with your guesses. :)

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1In mathematics, you are allowed to guess, but you also need a way to check your answer. If you cannot do both, then, sorry, guessing is not the right way.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you but all i wanted to know how to solve these, i havent done all by guess just two one which mite, but um not sure abt how to solve it to find exact answer to match. I just want to be clear abt all this

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I m not getting to find all of it exact answer

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.1I repeat: 1. Solve ALL four inequalities in the form z<4 z<3 z< ? z< / 2. THEN match the inequalities with the 4 given answers to make sure ALL inequalities are satisfied. I am still waiting for the solution to the second inequality after I have done the first one. If you have problems solving inequalities, that's where you need to work on.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.03z  10 + 5z  8 <6 3z + 5z + 10  8 <6 8z + 2<6

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I dont understand how to solve all this

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0@CalebBeavers help me please

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much for helping tolerating pain like me, i m sorry so for trouble. I really appreciate your help @mathmate, thanks alot! :)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1first of all simplify the left side. Can you simplify \[ 2(1+z) + 4z + 5\]

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.02z + 2z + 4z +5 4z +4z +5 8z +5

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ 2(1+z) = (2) \times 1 + (2) \times z = ?\]

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.02 +2z = 2 (2) X z = 2 + 2z = 4 X z I m stuck :( sorry

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1\[ 2 \times z = ?\]

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1no ... you cannot add like that.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358353383731:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1do you know how to take common?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358353592998:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.11$ + 2$ = 3$ 1$ + 2 pound = 3$  which of above is correct?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1what is the name of your currency?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1okay .. is 1 dollar + 2 pound = 3 dollar ?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yep!! 2 + (2z) here think of z as dollar and ... ther is nothing after 2 ... think of it as there is pound.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0So what i did on all that problems, so how do i match because, its seems tricky

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1also I think there is no minus there. your first problem is \[ 2(1+z) + 4z+5 = ?\] Simplify this. thikn of \( 4z + 5\) as .. 4 dollar + 5 pound

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so the bracket one what we need to do

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1at least you can make it a bit simpler.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.02 + 2z +4z +5  2 + 6z +5

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1quite not correct. + (  2z) = ?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1no ... dw:1358354499867:dw

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so 2 match up with this?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1okay now simplify the first problem.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1No ... you didn't do it correctly.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0i forgot, just did one side directly

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1woops!! sorry ... your first problem. \[ 2(1+z) + 4z+5 = (2(1+z)) + 4z+5 = (2\times 1 + 2 \times z) + 4z + 5 \\ = (2 + 2z) + 4z+5 = 2  2z + 4z+5 = (2z+4z) + (2+5) = 2z + 3\]

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1do you understand the each step?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0but am i right with first one?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.12z+3 < 11 2z+3  3 < 11  3 2z . (1/2) < 8/2 = 4 http://www.wolframalpha.com/input/?i=2%281%2Bz%29+%2B+4z%2B5+%3C%3D+11

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1if you had done it correctly ... you should have got \[ z < 4 \]

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0you are saying it match up 3

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yes copy these each step into your notebook and see if you understand each of these steps \[ \begin{align*} 2(1+z) + 4z+5 &= 2(1+z) + 4z+5 \\ &= 2(1+z) + 4z+5 \\ &= (2(1+z)) + 4z+5 \\ &= (2\times 1 + 2 \times z) + 4z + 5 \\ &= (2 + 2z) + 4z+5 \\ &= 2  2z + 4z+5 \\ &= (2z+4z) + (2+5) \\ &= 2z + 3 \end{align*} \]

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0thank you :) it making sense now

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1also if you have any misunderstanding ... don't hesitate to ask.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0can you show me other 3, if your not busy or if i didnt eaten up your head, i know i m painful, i hardly understand everything in math

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1first simplify do 2nd and 4 th problem

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1i think you are capable to do it .. also show me step!!

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.08z  10  8 <6 8z  2 <6 8z <6 +2 8z < 8 z < 0

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=3z+%2B+5z++10++8+%3C+6 watch your second step again.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry so, 8z  18 < 6 8z < 6  18 8z < 12 1.5? :(

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.18z  18 < 6 add +18 to both sides.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yes correct!! do the 4th problem similarly ... also note the mistake you made Sorry so, 8z  18 < 6 8z < 6  18 8z < 12 (is 618 = 12 ??) 1.5? :( Get calculator. or watch your step agai.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0In third one, how do i start?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1watch the example i gave you!!

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I m so sorry, i m such a error maker, pls forgive me for all this trouble

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1in which level do you study?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0no actually im in online high school, where i m takin blended course

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1really? you got terrible math!! these are very very basic simple rules

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0yes, im ok with other but worse in math

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1what did you put on 2?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1there you have problem!! (1+6z) = 1 times .. what's inside

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358357567000:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1yes ... now simplify it

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1again, you are not getting the point. look at the big picture. look again from where you started and where you ended. and check for errors.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1it's necessary that you write the whole step on some nontebook.

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1*notebook ... if you rely on memory then you will never learn. also it's necessary that you have to look at your previous step.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0ok sure, i will keep it mind. z + 6z + 5 + 1 5z + 6 < 1

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I know, something wrong in here again

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1try pluggin that expression on Wolfram Alpha

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I dont know how to do it

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1how do you do with this \[ a + 2b  (3a+b) = a + 2b  3a b = a3a+2bb = 2a +b \]

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0add by combining like term

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1how did i get rid of (3a+b) .. just do it like there.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0 3a + b, we cant go more from this on it

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358359171654:dw

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so then your saying it will move to positive

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0But i didnt understand how did operation + to  at middle

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Hows did you change and why?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1no ... dw:1358359302646:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358359471738:dw

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0you multiplied  all on Bracket, thats y, everything 

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358359803427:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1tell me in terms of pounds and dollars .... how much should you give to me?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1isn't that equal to 3a2b? what does this mean?

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358360151961:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358360292451:dw

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1358360405299:dwdw:1358360432011:dw

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0got it now :) thank you

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0thats y it was  1, right

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1Honestly, I feel like you are trolling with me!! right ... do the third number now and show it to me.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0I m extremely sorry for taking your time n making you crazy like this

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0:( i m so sorry for everything

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0 7z  19 + 19 < 5 +19 7z + < 24 got long decimal number

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1you copied the wrong question.  7z  19 + 19 < 5 +19

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so first one was right ?

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0so 7z + 19 < 5  7z + 19  19 < 519 7z < 14 z < 2

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1well ... done!! gotta go ... i strongly suggest that you get a pencil and notebook and practice few similar problems.

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! im sorry again for trouble :(

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.1I am not in trouble ,,, you might be in math test!! so pratice well!!

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0yes, i was trying understand these so that i dont make mistake again like this

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0Last one match up with 2, right, just to be confirmed

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0i m extremely apologize for giving you trouble @experimentX. thank you so much for helping me alot! you really saved me explaining all of it. I m really very sorry horribly troubling you

Faman39
 4 years ago
Best ResponseYou've already chosen the best response.0You are really amazing, thank you so much for make me understand abt all of it without being tired. your truly great, thanks alot @experimentX
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