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Faman39Best ResponseYou've already chosen the best response.0
@mathmate can you able to help me with this?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
DId you work out the solutions to each of the inequalities?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I didnt understand completely those problem, thats y
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Solve them as equations, and since they are <, so you need any answer that is smaller the equality.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I cant really get it how to do it, but i did somehow, where i got half n half write. I need to understand whole n how to find the rite answer
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
The questions are all inequalities. Say you solve the first one as an equality: 2(1+z)+5z+5<11 22z+4z+5<11 2z<113=8, or z<4 So any of the answers will fit for #1. Now proceed with #2, #3, #4 and try to move a,b,c,d around so that ALL the inequalities are satisfied.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
cqn you wait, cuz i m gonna show you those.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
First one will fit on which one, would it be 2
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Because they are not equations, but inequalities, you are better of doing all 4 of them before fitting anything. For example, all the answers a,b,c,d will fit in the first. So you don't know which one to choose until you have all 4 inequalities solved.
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Note: inequalities have multiple answers.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
So but i want to how will i get this answer matching correct answer
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Let say if you have a set of answers 1,3,5,7 and solutions to equations which are x<2,x<6,x<8,x<4 Then your choice would be to fit 1<2, 5<6, 7<8,3<4, or else you would have one left over such as: 1<2,3<6,5<8, but 7>4 will not work. That's why you need to work out all four before you can match.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Ok so, 2 (1 + z) +4z +5 <11 2 + 2z + 4z + 5 <11 2 + 2z + 5<11 so does it mean 2 will match or no?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
You have to solve it completely, 2+2z+5<11 2z+3<11 2z<8 z<4 Now you still have to solve the other three before you can start matching.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
that 2 match with this one right?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
All four answers will match with this one. If you want to take a chance, choose the highest number that will match. But I suggest you work out ALL 4 inequalities, then match. That will be much more sure.
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
all four will match, because 3<4 3<4 2<4 0<4 . That is why I suggest you work out all four inequalities before matching.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
All does not matched up, thats y, i m asking, how will i figure out all this
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
If you want, you can pick 2<4. If you choose now, the rest may or may not work.
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
1. Solve all FOUR inequalities, so you have 4 inequalities in hand, such as z<4 z< ? z< ? z< ? 2. Match the 4 given answers so that EVERY inequality works.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Second will be 3, am i right?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
I'm afraid not. You have a problem with the sign.
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
...unless you mean z>3
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I was saying according that table which i showed
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
So it suppose to match up with b 3
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Inequalities are not equations. Solutions must remain inequalities. So the second one must be given in the form z<3, or z>3, or z<3. 3 would not be the solution to an inequality. Can you show your work?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
3z  5z +10  8 does not look right. Can you check?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
2z + 10  8 <6 so if this be 2, then other was not 2
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I cant really know how to do these all
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Problems seems really confusing to me
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
3z  5z +10  8 <6 is inorrect. it should be +5z and 10. How did you get the signs reversed?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
Or written in full 3z+5z108<6
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so your saying it would match up with 3, right?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Thats how we find the 3
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
You are going to far with matching. You need to solve ALL 4 inequalities before you can match. the answer to the second is then....?
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
I mean the \(solution\) to the second inequality is then....?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I dont get at all how to last four, thats y i put their answer by guess, i m sure those last two were wrong but there is two matching which i gave, it was correct
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
If you don't need all four correct, that's ok. Go ahead and do it your way. I have no problem with that. Good luck with your guesses. :)
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
In mathematics, you are allowed to guess, but you also need a way to check your answer. If you cannot do both, then, sorry, guessing is not the right way.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Thank you but all i wanted to know how to solve these, i havent done all by guess just two one which mite, but um not sure abt how to solve it to find exact answer to match. I just want to be clear abt all this
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I m not getting to find all of it exact answer
 one year ago

mathmateBest ResponseYou've already chosen the best response.1
I repeat: 1. Solve ALL four inequalities in the form z<4 z<3 z< ? z< / 2. THEN match the inequalities with the 4 given answers to make sure ALL inequalities are satisfied. I am still waiting for the solution to the second inequality after I have done the first one. If you have problems solving inequalities, that's where you need to work on.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
3z  10 + 5z  8 <6 3z + 5z + 10  8 <6 8z + 2<6
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I dont understand how to solve all this
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@CalebBeavers help me please
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Thank you so much for helping tolerating pain like me, i m sorry so for trouble. I really appreciate your help @mathmate, thanks alot! :)
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
first of all simplify the left side. Can you simplify \[ 2(1+z) + 4z + 5\]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
2z + 2z + 4z +5 4z +4z +5 8z +5
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
\[ 2(1+z) = (2) \times 1 + (2) \times z = ?\]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
2 +2z = 2 (2) X z = 2 + 2z = 4 X z I m stuck :( sorry
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
\[ 2 \times z = ?\]
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
no ... you cannot add like that.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358353383731:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
do you know how to take common?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358353592998:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
1$ + 2$ = 3$ 1$ + 2 pound = 3$  which of above is correct?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
what is the name of your currency?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
okay .. is 1 dollar + 2 pound = 3 dollar ?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yep!! 2 + (2z) here think of z as dollar and ... ther is nothing after 2 ... think of it as there is pound.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
So what i did on all that problems, so how do i match because, its seems tricky
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
also I think there is no minus there. your first problem is \[ 2(1+z) + 4z+5 = ?\] Simplify this. thikn of \( 4z + 5\) as .. 4 dollar + 5 pound
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so the bracket one what we need to do
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
at least you can make it a bit simpler.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
2 + 2z +4z +5  2 + 6z +5
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
quite not correct. + (  2z) = ?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
no ... dw:1358354499867:dw
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so 2 match up with this?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I meant, first problem
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
okay now simplify the first problem.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
No ... you didn't do it correctly.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
i forgot, just did one side directly
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
woops!! sorry ... your first problem. \[ 2(1+z) + 4z+5 = (2(1+z)) + 4z+5 = (2\times 1 + 2 \times z) + 4z + 5 \\ = (2 + 2z) + 4z+5 = 2  2z + 4z+5 = (2z+4z) + (2+5) = 2z + 3\]
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
do you understand the each step?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
but am i right with first one?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
2z+3 < 11 2z+3  3 < 11  3 2z . (1/2) < 8/2 = 4 http://www.wolframalpha.com/input/?i=2%281%2Bz%29+%2B+4z%2B5+%3C%3D+11
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
if you had done it correctly ... you should have got \[ z < 4 \]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
you are saying it match up 3
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yes copy these each step into your notebook and see if you understand each of these steps \[ \begin{align*} 2(1+z) + 4z+5 &= 2(1+z) + 4z+5 \\ &= 2(1+z) + 4z+5 \\ &= (2(1+z)) + 4z+5 \\ &= (2\times 1 + 2 \times z) + 4z + 5 \\ &= (2 + 2z) + 4z+5 \\ &= 2  2z + 4z+5 \\ &= (2z+4z) + (2+5) \\ &= 2z + 3 \end{align*} \]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
thank you :) it making sense now
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
also if you have any misunderstanding ... don't hesitate to ask.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
can you show me other 3, if your not busy or if i didnt eaten up your head, i know i m painful, i hardly understand everything in math
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
first simplify do 2nd and 4 th problem
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
i think you are capable to do it .. also show me step!!
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
8z  10  8 <6 8z  2 <6 8z <6 +2 8z < 8 z < 0
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=3z+%2B+5z++10++8+%3C+6 watch your second step again.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Sorry so, 8z  18 < 6 8z < 6  18 8z < 12 1.5? :(
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
8z  18 < 6 add +18 to both sides.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yes correct!! do the 4th problem similarly ... also note the mistake you made Sorry so, 8z  18 < 6 8z < 6  18 8z < 12 (is 618 = 12 ??) 1.5? :( Get calculator. or watch your step agai.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
In third one, how do i start?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
watch the example i gave you!!
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I m so sorry, i m such a error maker, pls forgive me for all this trouble
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
in which level do you study?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
no actually im in online high school, where i m takin blended course
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
really? you got terrible math!! these are very very basic simple rules
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
yes, im ok with other but worse in math
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
what did you put on 2?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Z + 5  ( 1 + 6z) > 1
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
there you have problem!! (1+6z) = 1 times .. what's inside
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358357567000:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
what is +  6z = ?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
yes ... now simplify it
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
again, you are not getting the point. look at the big picture. look again from where you started and where you ended. and check for errors.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
it's necessary that you write the whole step on some nontebook.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
*notebook ... if you rely on memory then you will never learn. also it's necessary that you have to look at your previous step.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
ok sure, i will keep it mind. z + 6z + 5 + 1 5z + 6 < 1
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I know, something wrong in here again
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
try pluggin that expression on Wolfram Alpha
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I dont know how to do it
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
how do you do with this \[ a + 2b  (3a+b) = a + 2b  3a b = a3a+2bb = 2a +b \]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
add by combining like term
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
how did i get rid of (3a+b) .. just do it like there.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
 3a + b, we cant go more from this on it
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358359171654:dw
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so then your saying it will move to positive
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
But i didnt understand how did operation + to  at middle
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Hows did you change and why?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
no ... dw:1358359302646:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358359471738:dw
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
you multiplied  all on Bracket, thats y, everything 
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358359803427:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
tell me in terms of pounds and dollars .... how much should you give to me?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
isn't that equal to 3a2b? what does this mean?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358360151961:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358360292451:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1358360405299:dwdw:1358360432011:dw
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
got it now :) thank you
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
thats y it was  1, right
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
Honestly, I feel like you are trolling with me!! right ... do the third number now and show it to me.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I m extremely sorry for taking your time n making you crazy like this
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
:( i m so sorry for everything
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
 7z  19 + 19 < 5 +19 7z + < 24 got long decimal number
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
you copied the wrong question.  7z  19 + 19 < 5 +19
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so first one was right ?
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
no you had +7z ...
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
so 7z + 19 < 5  7z + 19  19 < 519 7z < 14 z < 2
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
well ... done!! gotta go ... i strongly suggest that you get a pencil and notebook and practice few similar problems.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Thank you so much! im sorry again for trouble :(
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
I am not in trouble ,,, you might be in math test!! so pratice well!!
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
yes, i was trying understand these so that i dont make mistake again like this
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Last one match up with 2, right, just to be confirmed
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
i m extremely apologize for giving you trouble @experimentX. thank you so much for helping me alot! you really saved me explaining all of it. I m really very sorry horribly troubling you
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
You are really amazing, thank you so much for make me understand abt all of it without being tired. your truly great, thanks alot @experimentX
 one year ago
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