## Faman39 Group Title Please help me to understand and solve these! one year ago one year ago

1. Faman39 Group Title

2. Faman39 Group Title

@mathmate can you able to help me with this?

3. mathmate Group Title

DId you work out the solutions to each of the inequalities?

4. Faman39 Group Title

I didnt understand completely those problem, thats y

5. mathmate Group Title

Solve them as equations, and since they are <, so you need any answer that is smaller the equality.

6. Faman39 Group Title

I cant really get it how to do it, but i did somehow, where i got half n half write. I need to understand whole n how to find the rite answer

7. mathmate Group Title

The questions are all inequalities. Say you solve the first one as an equality: -2(1+z)+5z+5<11 -2-2z+4z+5<11 2z<11-3=8, or z<4 So any of the answers will fit for #1. Now proceed with #2, #3, #4 and try to move a,b,c,d around so that ALL the inequalities are satisfied.

8. Faman39 Group Title

cqn you wait, cuz i m gonna show you those.

9. Faman39 Group Title

First one will fit on which one, would it be 2

10. mathmate Group Title

Because they are not equations, but inequalities, you are better of doing all 4 of them before fitting anything. For example, all the answers a,b,c,d will fit in the first. So you don't know which one to choose until you have all 4 inequalities solved.

11. mathmate Group Title

12. Faman39 Group Title

So but i want to how will i get this answer matching correct answer

13. Faman39 Group Title

Of all of them

14. mathmate Group Title

Let say if you have a set of answers 1,3,5,7 and solutions to equations which are x<2,x<6,x<8,x<4 Then your choice would be to fit 1<2, 5<6, 7<8,3<4, or else you would have one left over such as: 1<2,3<6,5<8, but 7>4 will not work. That's why you need to work out all four before you can match.

15. Faman39 Group Title

Ok so, -2 (1 + z) +4z +5 <11 -2 + -2z + 4z + 5 <11 -2 + 2z + 5<11 so does it mean 2 will match or no?

16. mathmate Group Title

You have to solve it completely, -2+2z+5<11 2z+3<11 2z<8 z<4 Now you still have to solve the other three before you can start matching.

17. Faman39 Group Title

that 2 match with this one right?

18. mathmate Group Title

All four answers will match with this one. If you want to take a chance, choose the highest number that will match. But I suggest you work out ALL 4 inequalities, then match. That will be much more sure.

19. mathmate Group Title

all four will match, because 3<4 -3<4 2<4 0<4 . That is why I suggest you work out all four inequalities before matching.

20. Faman39 Group Title

All does not matched up, thats y, i m asking, how will i figure out all this

21. mathmate Group Title

If you want, you can pick 2<4. If you choose now, the rest may or may not work.

22. mathmate Group Title

1. Solve all FOUR inequalities, so you have 4 inequalities in hand, such as z<4 z< ? z< ? z< ? 2. Match the 4 given answers so that EVERY inequality works.

23. Faman39 Group Title

Second will be -3, am i right?

24. mathmate Group Title

I'm afraid not. You have a problem with the sign.

25. mathmate Group Title

...unless you mean -z>-3

26. Faman39 Group Title

I was saying according that table which i showed

27. Faman39 Group Title

So it suppose to match up with b -3

28. Faman39 Group Title

right?

29. mathmate Group Title

Inequalities are not equations. Solutions must remain inequalities. So the second one must be given in the form z<-3, or z>3, or z<3. -3 would not be the solution to an inequality. Can you show your work?

30. Faman39 Group Title

ok

31. Faman39 Group Title

3z - 5z +10 - 8 <6

32. mathmate Group Title

3z - 5z +10 - 8 does not look right. Can you check?

33. Faman39 Group Title

2z + 10 - 8 <6 so if this be 2, then other was not 2

34. Faman39 Group Title

I cant really know how to do these all

35. Faman39 Group Title

Problems seems really confusing to me

36. mathmate Group Title

3z - 5z +10 - 8 <6 is inorrect. it should be +5z and -10. How did you get the signs reversed?

37. mathmate Group Title

Or written in full 3z+5z-10-8<6

38. Faman39 Group Title

so your saying it would match up with 3, right?

39. Faman39 Group Title

Thats how we find the 3

40. mathmate Group Title

You are going to far with matching. You need to solve ALL 4 inequalities before you can match. the answer to the second is then....?

41. mathmate Group Title

I mean the $$solution$$ to the second inequality is then....?

42. Faman39 Group Title

I dont get at all how to last four, thats y i put their answer by guess, i m sure those last two were wrong but there is two matching which i gave, it was correct

43. mathmate Group Title

If you don't need all four correct, that's ok. Go ahead and do it your way. I have no problem with that. Good luck with your guesses. :)

44. mathmate Group Title

In mathematics, you are allowed to guess, but you also need a way to check your answer. If you cannot do both, then, sorry, guessing is not the right way.

45. Faman39 Group Title

Thank you but all i wanted to know how to solve these, i havent done all by guess just two one which mite, but um not sure abt how to solve it to find exact answer to match. I just want to be clear abt all this

46. Faman39 Group Title

I m not getting to find all of it exact answer

47. mathmate Group Title

I repeat: 1. Solve ALL four inequalities in the form z<4 z<3 z< ? z< / 2. THEN match the inequalities with the 4 given answers to make sure ALL inequalities are satisfied. I am still waiting for the solution to the second inequality after I have done the first one. If you have problems solving inequalities, that's where you need to work on.

48. Faman39 Group Title

3z - 10 + 5z - 8 <6 3z + 5z + 10 - 8 <6 8z + 2<6

49. Faman39 Group Title

8z + 2 - 2 <6 8z <6

50. Faman39 Group Title

it will be a 0?

51. Faman39 Group Title

No

52. Faman39 Group Title

53. Faman39 Group Title

I dont understand how to solve all this

54. Faman39 Group Title

55. Faman39 Group Title

@phi

56. Faman39 Group Title

Thank you so much for helping tolerating pain like me, i m sorry so for trouble. I really appreciate your help @mathmate, thanks alot! :)

57. Faman39 Group Title

This one @experimentX

58. experimentX Group Title

first of all simplify the left side. Can you simplify $-2(1+z) + 4z + 5$

59. Faman39 Group Title

-2z + -2z + 4z +5 4z +4z +5 8z +5

60. Faman39 Group Title

isnt it?

61. experimentX Group Title

nope!!

62. experimentX Group Title

$-2(1+z) = (-2) \times 1 + (-2) \times z = ?$

63. Faman39 Group Title

-2 +2z = -2 (-2) X z = -2 + 2z = -4 X z I m stuck :( sorry

64. Faman39 Group Title

-2

65. experimentX Group Title

$-2 \times z = ?$

66. Faman39 Group Title

-2z

67. experimentX Group Title

-2 + (-2z)= ?

68. Faman39 Group Title

4z?

69. experimentX Group Title

no ... you cannot add like that.

70. experimentX Group Title

|dw:1358353383731:dw|

71. experimentX Group Title

do you know how to take common?

72. Faman39 Group Title

3x + 3x

73. experimentX Group Title

|dw:1358353592998:dw|

74. Faman39 Group Title

5x

75. experimentX Group Title

yes!!

76. experimentX Group Title

1$+ 2$ = 3$1$ + 2 pound = 3\$ ------------------ which of above is correct?

77. Faman39 Group Title

3?

78. Faman39 Group Title

both are same

79. experimentX Group Title

what is the name of your currency?

80. Faman39 Group Title

pound

81. experimentX Group Title

okay .. is 1 dollar + 2 pound = 3 dollar ?

82. Faman39 Group Title

no

83. experimentX Group Title

is that correct?

84. Faman39 Group Title

no

85. experimentX Group Title

why not?

86. Faman39 Group Title

Both are not similar

87. experimentX Group Title

yep!! -2 + (-2z) here think of z as dollar and ... ther is nothing after -2 ... think of it as there is pound.

88. Faman39 Group Title

So what i did on all that problems, so how do i match because, its seems tricky

89. experimentX Group Title

also I think there is no minus there. your first problem is $2(1+z) + 4z+5 = ?$ Simplify this. thikn of $$4z + 5$$ as .. 4 dollar + 5 pound

90. Faman39 Group Title

91. Faman39 Group Title

so the bracket one what we need to do

92. experimentX Group Title

at least you can make it a bit simpler.

93. Faman39 Group Title

-2 + 2z +4z +5 - 2 + 6z +5

94. Faman39 Group Title

?

95. experimentX Group Title

quite not correct. + ( - 2z) = ?

96. experimentX Group Title

no ... |dw:1358354499867:dw|

97. Faman39 Group Title

-2z

98. Faman39 Group Title

so 2 match up with this?

99. Faman39 Group Title

I meant, first problem

100. experimentX Group Title

okay now simplify the first problem.

101. Faman39 Group Title

-2z + 5 < 11

102. Faman39 Group Title

-2z < 6

103. Faman39 Group Title

z < 6/-2 z < -3

104. Faman39 Group Title

it is match up with b

105. experimentX Group Title

No ... you didn't do it correctly.

106. Faman39 Group Title

divide both side

107. Faman39 Group Title

right?

108. Faman39 Group Title

i forgot, just did one side directly

109. experimentX Group Title

woops!! sorry ... your first problem. $-2(1+z) + 4z+5 = -(2(1+z)) + 4z+5 = -(2\times 1 + 2 \times z) + 4z + 5 \\ = -(2 + 2z) + 4z+5 = -2 - 2z + 4z+5 = (-2z+4z) + (-2+5) = 2z + 3$

110. experimentX Group Title

do you understand the each step?

111. Faman39 Group Title

but am i right with first one?

112. experimentX Group Title

did you get 2z+3?

113. Faman39 Group Title

no i got -3

114. experimentX Group Title

2z+3 < 11 2z+3 - 3 < 11 - 3 2z . (1/2) < 8/2 = 4 http://www.wolframalpha.com/input/?i=-2%281%2Bz%29+%2B+4z%2B5+%3C%3D+11

115. experimentX Group Title

if you had done it correctly ... you should have got $z < 4$

116. Faman39 Group Title

you are saying it match up 3

117. Faman39 Group Title

right?

118. experimentX Group Title

yes copy these each step into your notebook and see if you understand each of these steps \begin{align*} -2(1+z) + 4z+5 &= -2(1+z) + 4z+5 \\ &= -2(1+z) + 4z+5 \\ &= -(2(1+z)) + 4z+5 \\ &= -(2\times 1 + 2 \times z) + 4z + 5 \\ &= -(2 + 2z) + 4z+5 \\ &= -2 - 2z + 4z+5 \\ &= (-2z+4z) + (-2+5) \\ &= 2z + 3 \end{align*}

119. Faman39 Group Title

thank you :) it making sense now

120. Faman39 Group Title

thank you so much

121. experimentX Group Title

also if you have any misunderstanding ... don't hesitate to ask.

122. Faman39 Group Title

can you show me other 3, if your not busy or if i didnt eaten up your head, i know i m painful, i hardly understand everything in math

123. Faman39 Group Title

thats really horrible

124. experimentX Group Title

first simplify do 2nd and 4 th problem

125. experimentX Group Title

i think you are capable to do it .. also show me step!!

126. Faman39 Group Title

3z + 5z - 10 - 8 < 6?

127. experimentX Group Title

yes go on!!

128. Faman39 Group Title

8z - 10 - 8 <6 8z - 2 <6 8z <6 +2 8z < 8 z < 0

129. experimentX Group Title

http://www.wolframalpha.com/input/?i=3z+%2B+5z+-+10+-+8+%3C+6 watch your second step again.

130. Faman39 Group Title

Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 1.5? :(

131. experimentX Group Title

8z - 18 < 6 add +18 to both sides.

132. Faman39 Group Title

8z < 24 <3

133. experimentX Group Title

yes correct!! do the 4th problem similarly ... also note the mistake you made Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 (is 6-18 = 12 ??) 1.5? :( Get calculator. or watch your step agai.

134. Faman39 Group Title

In third one, how do i start?

135. experimentX Group Title

watch the example i gave you!!

136. Faman39 Group Title

I m so sorry, i m such a error maker, pls forgive me for all this trouble

137. experimentX Group Title

in which level do you study?

138. Faman39 Group Title

no actually im in online high school, where i m takin blended course

139. experimentX Group Title

really? you got terrible math!! these are very very basic simple rules

140. Faman39 Group Title

yes, im ok with other but worse in math

141. experimentX Group Title

okay try 3

142. experimentX Group Title

what did you put on 2?

143. Faman39 Group Title

Z + 5 - ( 1 + 6z) > -1

144. Faman39 Group Title

z +5 - 1 + 6z > -1

145. experimentX Group Title

there you have problem!! -(1+6z) = -1 times .. what's inside

146. experimentX Group Title

|dw:1358357567000:dw|

147. Faman39 Group Title

-1 + -6z

148. experimentX Group Title

what is + - 6z = ?

149. Faman39 Group Title

- 6z

150. experimentX Group Title

yes ... now simplify it

151. Faman39 Group Title

7z

152. experimentX Group Title

again, you are not getting the point. look at the big picture. look again from where you started and where you ended. and check for errors.

153. Faman39 Group Title

ok sorry

154. Faman39 Group Title

z + 5 - -1 + -6z <1

155. experimentX Group Title

it's necessary that you write the whole step on some nontebook.

156. experimentX Group Title

*notebook ... if you rely on memory then you will never learn. also it's necessary that you have to look at your previous step.

157. Faman39 Group Title

ok sure, i will keep it mind. z + -6z + 5- + -1 5z + 6 < 1

158. Faman39 Group Title

I know, something wrong in here again

159. Faman39 Group Title

5z < 1 - 6 5z < 5 1

160. Faman39 Group Title

<1

161. Faman39 Group Title

am i wrong?

162. experimentX Group Title

try pluggin that expression on Wolfram Alpha

163. Faman39 Group Title

I dont know how to do it

164. Faman39 Group Title

:(

165. Faman39 Group Title

166. experimentX Group Title

how do you do with this $a + 2b - (3a+b) = a + 2b - 3a -b = a-3a+2b-b = -2a +b$

167. Faman39 Group Title

168. experimentX Group Title

how did i get rid of -(3a+b) .. just do it like there.

169. Faman39 Group Title

- 3a + b, we cant go more from this on it

170. experimentX Group Title

- 3a - b

171. experimentX Group Title

|dw:1358359171654:dw|

172. Faman39 Group Title

so then your saying it will move to positive

173. Faman39 Group Title

But i didnt understand how did operation + to - at middle

174. Faman39 Group Title

Hows did you change and why?

175. experimentX Group Title

no ... |dw:1358359302646:dw|

176. Faman39 Group Title

ok

177. experimentX Group Title

|dw:1358359471738:dw|

178. Faman39 Group Title

not equal

179. Faman39 Group Title

yes

180. Faman39 Group Title

you multiplied - all on Bracket, thats y, everything -

181. experimentX Group Title

|dw:1358359803427:dw|

182. Faman39 Group Title

- 3a + -2b

183. experimentX Group Title

tell me in terms of pounds and dollars .... how much should you give to me?

184. Faman39 Group Title

3 dollar, 2 pounds

185. experimentX Group Title

isn't that equal to -3a-2b? what does this mean?

186. experimentX Group Title

|dw:1358360151961:dw|

187. experimentX Group Title

|dw:1358360292451:dw|

188. experimentX Group Title

|dw:1358360405299:dw||dw:1358360432011:dw|

189. Faman39 Group Title

got it now :) thank you

190. Faman39 Group Title

thats y it was - 1, right

191. experimentX Group Title

Honestly, I feel like you are trolling with me!! right ... do the third number now and show it to me.

192. Faman39 Group Title

I m extremely sorry for taking your time n making you crazy like this

193. Faman39 Group Title

:( i m so sorry for everything

194. Faman39 Group Title

- 7z - 19 + 19 < 5 +19 -7z + < 24 got long decimal number

195. experimentX Group Title

you copied the wrong question. - 7z - 19 + 19 < -5 +19

196. Faman39 Group Title

so first one was right ?

197. Faman39 Group Title

which i showed you b4

198. experimentX Group Title

199. Faman39 Group Title

-8z - 19 + z > - 5

200. Faman39 Group Title

so -7z + 19 < 5 - 7z + 19 - 19 < 5-19 -7z < 14 z < -2

201. experimentX Group Title

well ... done!! gotta go ... i strongly suggest that you get a pencil and notebook and practice few similar problems.

202. Faman39 Group Title

Thank you so much! im sorry again for trouble :(

203. experimentX Group Title

I am not in trouble ,,, you might be in math test!! so pratice well!!

204. Faman39 Group Title

yes, i was trying understand these so that i dont make mistake again like this

205. Faman39 Group Title

Last one match up with 2, right, just to be confirmed

206. Faman39 Group Title

i m extremely apologize for giving you trouble @experimentX. thank you so much for helping me alot! you really saved me explaining all of it. I m really very sorry horribly troubling you

207. Faman39 Group Title

You are really amazing, thank you so much for make me understand abt all of it without being tired. your truly great, thanks alot @experimentX