Faman39
  • Faman39
Please help me to understand and solve these!
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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Faman39
  • Faman39
1 Attachment
Faman39
  • Faman39
@mathmate can you able to help me with this?
mathmate
  • mathmate
DId you work out the solutions to each of the inequalities?

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Faman39
  • Faman39
I didnt understand completely those problem, thats y
mathmate
  • mathmate
Solve them as equations, and since they are <, so you need any answer that is smaller the equality.
Faman39
  • Faman39
I cant really get it how to do it, but i did somehow, where i got half n half write. I need to understand whole n how to find the rite answer
mathmate
  • mathmate
The questions are all inequalities. Say you solve the first one as an equality: -2(1+z)+5z+5<11 -2-2z+4z+5<11 2z<11-3=8, or z<4 So any of the answers will fit for #1. Now proceed with #2, #3, #4 and try to move a,b,c,d around so that ALL the inequalities are satisfied.
Faman39
  • Faman39
cqn you wait, cuz i m gonna show you those.
Faman39
  • Faman39
First one will fit on which one, would it be 2
mathmate
  • mathmate
Because they are not equations, but inequalities, you are better of doing all 4 of them before fitting anything. For example, all the answers a,b,c,d will fit in the first. So you don't know which one to choose until you have all 4 inequalities solved.
mathmate
  • mathmate
Note: inequalities have multiple answers.
Faman39
  • Faman39
So but i want to how will i get this answer matching correct answer
Faman39
  • Faman39
Of all of them
mathmate
  • mathmate
Let say if you have a set of answers 1,3,5,7 and solutions to equations which are x<2,x<6,x<8,x<4 Then your choice would be to fit 1<2, 5<6, 7<8,3<4, or else you would have one left over such as: 1<2,3<6,5<8, but 7>4 will not work. That's why you need to work out all four before you can match.
Faman39
  • Faman39
Ok so, -2 (1 + z) +4z +5 <11 -2 + -2z + 4z + 5 <11 -2 + 2z + 5<11 so does it mean 2 will match or no?
mathmate
  • mathmate
You have to solve it completely, -2+2z+5<11 2z+3<11 2z<8 z<4 Now you still have to solve the other three before you can start matching.
Faman39
  • Faman39
that 2 match with this one right?
mathmate
  • mathmate
All four answers will match with this one. If you want to take a chance, choose the highest number that will match. But I suggest you work out ALL 4 inequalities, then match. That will be much more sure.
mathmate
  • mathmate
all four will match, because 3<4 -3<4 2<4 0<4 . That is why I suggest you work out all four inequalities before matching.
Faman39
  • Faman39
All does not matched up, thats y, i m asking, how will i figure out all this
mathmate
  • mathmate
If you want, you can pick 2<4. If you choose now, the rest may or may not work.
mathmate
  • mathmate
1. Solve all FOUR inequalities, so you have 4 inequalities in hand, such as z<4 z< ? z< ? z< ? 2. Match the 4 given answers so that EVERY inequality works.
Faman39
  • Faman39
Second will be -3, am i right?
mathmate
  • mathmate
I'm afraid not. You have a problem with the sign.
mathmate
  • mathmate
...unless you mean -z>-3
Faman39
  • Faman39
I was saying according that table which i showed
Faman39
  • Faman39
So it suppose to match up with b -3
Faman39
  • Faman39
right?
mathmate
  • mathmate
Inequalities are not equations. Solutions must remain inequalities. So the second one must be given in the form z<-3, or z>3, or z<3. -3 would not be the solution to an inequality. Can you show your work?
Faman39
  • Faman39
ok
Faman39
  • Faman39
3z - 5z +10 - 8 <6
mathmate
  • mathmate
3z - 5z +10 - 8 does not look right. Can you check?
Faman39
  • Faman39
2z + 10 - 8 <6 so if this be 2, then other was not 2
Faman39
  • Faman39
I cant really know how to do these all
Faman39
  • Faman39
Problems seems really confusing to me
mathmate
  • mathmate
3z - 5z +10 - 8 <6 is inorrect. it should be +5z and -10. How did you get the signs reversed?
mathmate
  • mathmate
Or written in full 3z+5z-10-8<6
Faman39
  • Faman39
so your saying it would match up with 3, right?
Faman39
  • Faman39
Thats how we find the 3
mathmate
  • mathmate
You are going to far with matching. You need to solve ALL 4 inequalities before you can match. the answer to the second is then....?
mathmate
  • mathmate
I mean the \(solution\) to the second inequality is then....?
Faman39
  • Faman39
I dont get at all how to last four, thats y i put their answer by guess, i m sure those last two were wrong but there is two matching which i gave, it was correct
mathmate
  • mathmate
If you don't need all four correct, that's ok. Go ahead and do it your way. I have no problem with that. Good luck with your guesses. :)
mathmate
  • mathmate
In mathematics, you are allowed to guess, but you also need a way to check your answer. If you cannot do both, then, sorry, guessing is not the right way.
Faman39
  • Faman39
Thank you but all i wanted to know how to solve these, i havent done all by guess just two one which mite, but um not sure abt how to solve it to find exact answer to match. I just want to be clear abt all this
Faman39
  • Faman39
I m not getting to find all of it exact answer
mathmate
  • mathmate
I repeat: 1. Solve ALL four inequalities in the form z<4 z<3 z< ? z< / 2. THEN match the inequalities with the 4 given answers to make sure ALL inequalities are satisfied. I am still waiting for the solution to the second inequality after I have done the first one. If you have problems solving inequalities, that's where you need to work on.
Faman39
  • Faman39
3z - 10 + 5z - 8 <6 3z + 5z + 10 - 8 <6 8z + 2<6
Faman39
  • Faman39
8z + 2 - 2 <6 8z <6
Faman39
  • Faman39
it will be a 0?
Faman39
  • Faman39
No
Faman39
  • Faman39
Please help!
Faman39
  • Faman39
I dont understand how to solve all this
Faman39
  • Faman39
@CalebBeavers help me please
Faman39
  • Faman39
@phi
Faman39
  • Faman39
Thank you so much for helping tolerating pain like me, i m sorry so for trouble. I really appreciate your help @mathmate, thanks alot! :)
Faman39
  • Faman39
This one @experimentX
experimentX
  • experimentX
first of all simplify the left side. Can you simplify \[ -2(1+z) + 4z + 5\]
Faman39
  • Faman39
-2z + -2z + 4z +5 4z +4z +5 8z +5
Faman39
  • Faman39
isnt it?
experimentX
  • experimentX
nope!!
experimentX
  • experimentX
\[ -2(1+z) = (-2) \times 1 + (-2) \times z = ?\]
Faman39
  • Faman39
-2 +2z = -2 (-2) X z = -2 + 2z = -4 X z I m stuck :( sorry
Faman39
  • Faman39
-2
experimentX
  • experimentX
\[ -2 \times z = ?\]
Faman39
  • Faman39
-2z
experimentX
  • experimentX
-2 + (-2z)= ?
Faman39
  • Faman39
4z?
experimentX
  • experimentX
no ... you cannot add like that.
experimentX
  • experimentX
|dw:1358353383731:dw|
experimentX
  • experimentX
do you know how to take common?
Faman39
  • Faman39
3x + 3x
experimentX
  • experimentX
|dw:1358353592998:dw|
Faman39
  • Faman39
5x
experimentX
  • experimentX
yes!!
experimentX
  • experimentX
1$ + 2$ = 3$ 1$ + 2 pound = 3$ ------------------ which of above is correct?
Faman39
  • Faman39
3?
Faman39
  • Faman39
both are same
experimentX
  • experimentX
what is the name of your currency?
Faman39
  • Faman39
pound
experimentX
  • experimentX
okay .. is 1 dollar + 2 pound = 3 dollar ?
Faman39
  • Faman39
no
experimentX
  • experimentX
is that correct?
Faman39
  • Faman39
no
experimentX
  • experimentX
why not?
Faman39
  • Faman39
Both are not similar
experimentX
  • experimentX
yep!! -2 + (-2z) here think of z as dollar and ... ther is nothing after -2 ... think of it as there is pound.
Faman39
  • Faman39
So what i did on all that problems, so how do i match because, its seems tricky
experimentX
  • experimentX
also I think there is no minus there. your first problem is \[ 2(1+z) + 4z+5 = ?\] Simplify this. thikn of \( 4z + 5\) as .. 4 dollar + 5 pound
Faman39
  • Faman39
it cannot be added
Faman39
  • Faman39
so the bracket one what we need to do
experimentX
  • experimentX
at least you can make it a bit simpler.
Faman39
  • Faman39
-2 + 2z +4z +5 - 2 + 6z +5
Faman39
  • Faman39
?
experimentX
  • experimentX
quite not correct. + ( - 2z) = ?
experimentX
  • experimentX
no ... |dw:1358354499867:dw|
Faman39
  • Faman39
-2z
Faman39
  • Faman39
so 2 match up with this?
Faman39
  • Faman39
I meant, first problem
experimentX
  • experimentX
okay now simplify the first problem.
Faman39
  • Faman39
-2z + 5 < 11
Faman39
  • Faman39
-2z < 6
Faman39
  • Faman39
z < 6/-2 z < -3
Faman39
  • Faman39
it is match up with b
experimentX
  • experimentX
No ... you didn't do it correctly.
Faman39
  • Faman39
divide both side
Faman39
  • Faman39
right?
Faman39
  • Faman39
i forgot, just did one side directly
experimentX
  • experimentX
woops!! sorry ... your first problem. \[ -2(1+z) + 4z+5 = -(2(1+z)) + 4z+5 = -(2\times 1 + 2 \times z) + 4z + 5 \\ = -(2 + 2z) + 4z+5 = -2 - 2z + 4z+5 = (-2z+4z) + (-2+5) = 2z + 3\]
experimentX
  • experimentX
do you understand the each step?
Faman39
  • Faman39
but am i right with first one?
experimentX
  • experimentX
did you get 2z+3?
Faman39
  • Faman39
no i got -3
experimentX
  • experimentX
2z+3 < 11 2z+3 - 3 < 11 - 3 2z . (1/2) < 8/2 = 4 http://www.wolframalpha.com/input/?i=-2%281%2Bz%29+%2B+4z%2B5+%3C%3D+11
experimentX
  • experimentX
if you had done it correctly ... you should have got \[ z < 4 \]
Faman39
  • Faman39
you are saying it match up 3
Faman39
  • Faman39
right?
experimentX
  • experimentX
yes copy these each step into your notebook and see if you understand each of these steps \[ \begin{align*} -2(1+z) + 4z+5 &= -2(1+z) + 4z+5 \\ &= -2(1+z) + 4z+5 \\ &= -(2(1+z)) + 4z+5 \\ &= -(2\times 1 + 2 \times z) + 4z + 5 \\ &= -(2 + 2z) + 4z+5 \\ &= -2 - 2z + 4z+5 \\ &= (-2z+4z) + (-2+5) \\ &= 2z + 3 \end{align*} \]
Faman39
  • Faman39
thank you :) it making sense now
Faman39
  • Faman39
thank you so much
experimentX
  • experimentX
also if you have any misunderstanding ... don't hesitate to ask.
Faman39
  • Faman39
can you show me other 3, if your not busy or if i didnt eaten up your head, i know i m painful, i hardly understand everything in math
Faman39
  • Faman39
thats really horrible
experimentX
  • experimentX
first simplify do 2nd and 4 th problem
experimentX
  • experimentX
i think you are capable to do it .. also show me step!!
Faman39
  • Faman39
3z + 5z - 10 - 8 < 6?
experimentX
  • experimentX
yes go on!!
Faman39
  • Faman39
8z - 10 - 8 <6 8z - 2 <6 8z <6 +2 8z < 8 z < 0
experimentX
  • experimentX
http://www.wolframalpha.com/input/?i=3z+%2B+5z+-+10+-+8+%3C+6 watch your second step again.
Faman39
  • Faman39
Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 1.5? :(
experimentX
  • experimentX
8z - 18 < 6 add +18 to both sides.
Faman39
  • Faman39
8z < 24 <3
experimentX
  • experimentX
yes correct!! do the 4th problem similarly ... also note the mistake you made Sorry so, 8z - 18 < 6 8z < 6 - 18 8z < 12 (is 6-18 = 12 ??) 1.5? :( Get calculator. or watch your step agai.
Faman39
  • Faman39
In third one, how do i start?
experimentX
  • experimentX
watch the example i gave you!!
Faman39
  • Faman39
I m so sorry, i m such a error maker, pls forgive me for all this trouble
experimentX
  • experimentX
in which level do you study?
Faman39
  • Faman39
no actually im in online high school, where i m takin blended course
experimentX
  • experimentX
really? you got terrible math!! these are very very basic simple rules
Faman39
  • Faman39
yes, im ok with other but worse in math
experimentX
  • experimentX
okay try 3
experimentX
  • experimentX
what did you put on 2?
Faman39
  • Faman39
Z + 5 - ( 1 + 6z) > -1
Faman39
  • Faman39
z +5 - 1 + 6z > -1
experimentX
  • experimentX
there you have problem!! -(1+6z) = -1 times .. what's inside
experimentX
  • experimentX
|dw:1358357567000:dw|
Faman39
  • Faman39
-1 + -6z
experimentX
  • experimentX
what is + - 6z = ?
Faman39
  • Faman39
- 6z
experimentX
  • experimentX
yes ... now simplify it
Faman39
  • Faman39
7z
experimentX
  • experimentX
again, you are not getting the point. look at the big picture. look again from where you started and where you ended. and check for errors.
Faman39
  • Faman39
ok sorry
Faman39
  • Faman39
z + 5 - -1 + -6z <1
experimentX
  • experimentX
it's necessary that you write the whole step on some nontebook.
experimentX
  • experimentX
*notebook ... if you rely on memory then you will never learn. also it's necessary that you have to look at your previous step.
Faman39
  • Faman39
ok sure, i will keep it mind. z + -6z + 5- + -1 5z + 6 < 1
Faman39
  • Faman39
I know, something wrong in here again
Faman39
  • Faman39
5z < 1 - 6 5z < 5 1
Faman39
  • Faman39
<1
Faman39
  • Faman39
am i wrong?
experimentX
  • experimentX
try pluggin that expression on Wolfram Alpha
Faman39
  • Faman39
I dont know how to do it
Faman39
  • Faman39
:(
Faman39
  • Faman39
your saying negative
experimentX
  • experimentX
how do you do with this \[ a + 2b - (3a+b) = a + 2b - 3a -b = a-3a+2b-b = -2a +b \]
Faman39
  • Faman39
add by combining like term
experimentX
  • experimentX
how did i get rid of -(3a+b) .. just do it like there.
Faman39
  • Faman39
- 3a + b, we cant go more from this on it
experimentX
  • experimentX
- 3a - b
experimentX
  • experimentX
|dw:1358359171654:dw|
Faman39
  • Faman39
so then your saying it will move to positive
Faman39
  • Faman39
But i didnt understand how did operation + to - at middle
Faman39
  • Faman39
Hows did you change and why?
experimentX
  • experimentX
no ... |dw:1358359302646:dw|
Faman39
  • Faman39
ok
experimentX
  • experimentX
|dw:1358359471738:dw|
Faman39
  • Faman39
not equal
Faman39
  • Faman39
yes
Faman39
  • Faman39
you multiplied - all on Bracket, thats y, everything -
experimentX
  • experimentX
|dw:1358359803427:dw|
Faman39
  • Faman39
- 3a + -2b
experimentX
  • experimentX
tell me in terms of pounds and dollars .... how much should you give to me?
Faman39
  • Faman39
3 dollar, 2 pounds
experimentX
  • experimentX
isn't that equal to -3a-2b? what does this mean?
experimentX
  • experimentX
|dw:1358360151961:dw|
experimentX
  • experimentX
|dw:1358360292451:dw|
experimentX
  • experimentX
|dw:1358360405299:dw||dw:1358360432011:dw|
Faman39
  • Faman39
got it now :) thank you
Faman39
  • Faman39
thats y it was - 1, right
experimentX
  • experimentX
Honestly, I feel like you are trolling with me!! right ... do the third number now and show it to me.
Faman39
  • Faman39
I m extremely sorry for taking your time n making you crazy like this
Faman39
  • Faman39
:( i m so sorry for everything
Faman39
  • Faman39
- 7z - 19 + 19 < 5 +19 -7z + < 24 got long decimal number
experimentX
  • experimentX
you copied the wrong question. - 7z - 19 + 19 < -5 +19
Faman39
  • Faman39
so first one was right ?
Faman39
  • Faman39
which i showed you b4
experimentX
  • experimentX
no you had +7z ...
Faman39
  • Faman39
-8z - 19 + z > - 5
Faman39
  • Faman39
so -7z + 19 < 5 - 7z + 19 - 19 < 5-19 -7z < 14 z < -2
experimentX
  • experimentX
well ... done!! gotta go ... i strongly suggest that you get a pencil and notebook and practice few similar problems.
Faman39
  • Faman39
Thank you so much! im sorry again for trouble :(
experimentX
  • experimentX
I am not in trouble ,,, you might be in math test!! so pratice well!!
Faman39
  • Faman39
yes, i was trying understand these so that i dont make mistake again like this
Faman39
  • Faman39
Last one match up with 2, right, just to be confirmed
Faman39
  • Faman39
i m extremely apologize for giving you trouble @experimentX. thank you so much for helping me alot! you really saved me explaining all of it. I m really very sorry horribly troubling you
Faman39
  • Faman39
You are really amazing, thank you so much for make me understand abt all of it without being tired. your truly great, thanks alot @experimentX

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