## Rachel98 2 years ago Please help. Write a rule for the nth term of the sequence. Use your rule to find a100.–8, 9, 26, 43, 60, . . .

This is an arithmetic progression with a distance of 17...So, each $a_{k}$ can be calculated by $a_{k-1}+17$ Now, $a_{n}=a_{1}+(n-1)d$ And we want the n=100 from the progression So, you'll have $a_{100}=-8+(100-1) \times 17$ $a_{100}=1675$