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Faman39

Please help!

  • one year ago
  • one year ago

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  1. kelberry
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    What do you need help with?

    • one year ago
  2. Faman39
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    • one year ago
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  3. Faman39
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    how I dont understand all this be solve and what match with what

    • one year ago
  4. kelberry
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    I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?

    • one year ago
  5. Faman39
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    Yes, cuz i have no idea.

    • one year ago
  6. kelberry
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    Okay, well. Do you want me to explain it well? Or are you just looking for a solution?

    • one year ago
  7. Faman39
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    Yes, please i dont understand each of this

    • one year ago
  8. kelberry
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    Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\] We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]

    • one year ago
  9. Faman39
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    So does it match with 3 or 2?

    • one year ago
  10. kelberry
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    So, I believe you're right when you put B, because it is the "greatest" solution.

    • one year ago
  11. Faman39
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    ok

    • one year ago
  12. kelberry
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    Let's move on to the next one.

    • one year ago
  13. Faman39
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    sure

    • one year ago
  14. kelberry
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    \[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]

    • one year ago
  15. Faman39
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    So this match with 3

    • one year ago
  16. kelberry
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    Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.

    • one year ago
  17. Faman39
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    ok take your time

    • one year ago
  18. kelberry
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    \[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]

    • one year ago
  19. kelberry
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    I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.

    • one year ago
  20. kelberry
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    Oh, wait! I forgot to flip the sign one moment.

    • one year ago
  21. kelberry
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    \[z<-3/5\] you flip the sign because you divided by a negative.

    • one year ago
  22. Faman39
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    got a decimall number

    • one year ago
  23. kelberry
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    \[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]

    • one year ago
  24. kelberry
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    Yeah, let me relook over my math for the 3rd one.

    • one year ago
  25. Faman39
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    @zepdrix all this still confusing to me

    • one year ago
  26. Faman39
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    Can you help me?

    • one year ago
  27. zepdrix
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    Which one you stuck on? D:

    • one year ago
  28. Faman39
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    all of them

    • one year ago
  29. Faman39
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    I will be right back in a few minute

    • one year ago
  30. zepdrix
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    K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\] This is a spot where you have to be careful. Multiplying or Dividing by a negative value will FLIP the inequality sign. So we'll proceed by dividing by -7,\[\large z \lt -2\]

    • one year ago
  31. zepdrix
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    Take a look at those steps, see if they make sense to you. So let's think about this inequality a second. Z is LESS THAN -2. The LARGEST integer that would make this inequality true would be -3 correct? Because -3 is less than -2.

    • one year ago
  32. Faman39
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    No sorry for late answer :( still didnt make sense

    • one year ago
  33. zepdrix
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    Which part? :o

    • one year ago
  34. Faman39
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    Does first match up with 2, is that what you meant?

    • one year ago
  35. zepdrix
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    I didn't do the first one, I was working on the last one.

    • one year ago
  36. Faman39
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    I was trying to find out where i m wrong

    • one year ago
  37. Faman39
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    try an to understand how all of them match correctly

    • one year ago
  38. zepdrix
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    Well look at them one at a time. In each case, you're given an inequality with ONE VARIABLE. Since the inequality has only one variable, we can solve for that variable. It looks like you have the wrong answer for the 4th equation. Scroll back up, I listed detailed steps on how to solve the 4th one. See if any of the steps confuse you.

    • one year ago
  39. Faman39
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    Can you tell me others also, cuz i m having confusion 3rd one

    • one year ago
  40. Faman39
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    I m ridiculously crazy from many hours to understand all of it

    • one year ago
  41. zepdrix
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    \[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\] Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign. Dividing both sides by -5 gives us,\[\large z \lt 1\] See how the inequality sign flipped?

    • one year ago
  42. zepdrix
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    What is the LARGEST integer below the number 1? That is the value that will make z true in the 3rd equation.

    • one year ago
  43. Faman39
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    sorry

    • one year ago
  44. zepdrix
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    1 is not less than 1 :D 1 is equal to 1. Think one lower than that.

    • one year ago
  45. Faman39
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    0

    • one year ago
  46. Faman39
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    how do you got zero

    • one year ago
  47. Faman39
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    Am i wrong?

    • one year ago
  48. Faman39
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    @satellite73 can you explain me all this

    • one year ago
  49. Faman39
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    i cant still understand all of them

    • one year ago
  50. Faman39
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    @Carl_Pham can you help me wit it

    • one year ago
  51. Faman39
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    @AravindG help

    • one year ago
  52. AravindG
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    YOU just need to open the brackets and bring all constants to RHS

    • one year ago
  53. Faman39
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    Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it

    • one year ago
  54. Faman39
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    @satellite73 can you help me ?

    • one year ago
  55. Faman39
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    @mathstudent55 can you able to help me with this?

    • one year ago
  56. AravindG
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    @Faman39 well i think most of them have been solved above .tell me where exactly u have doubt

    • one year ago
  57. Faman39
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    ok

    • one year ago
  58. Faman39
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    actually i m confuse because, i think whenever i tried to solve n match, i cant

    • one year ago
  59. Faman39
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    I dont know, why my head isnt working today, where everyone did so great

    • one year ago
  60. Faman39
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    Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.

    • one year ago
  61. Faman39
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    Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys

    • one year ago
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