Faman39
  • Faman39
Please help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
What do you need help with?
Faman39
  • Faman39
1 Attachment
Faman39
  • Faman39
how I dont understand all this be solve and what match with what

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More answers

anonymous
  • anonymous
I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?
Faman39
  • Faman39
Yes, cuz i have no idea.
anonymous
  • anonymous
Okay, well. Do you want me to explain it well? Or are you just looking for a solution?
Faman39
  • Faman39
Yes, please i dont understand each of this
anonymous
  • anonymous
Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\] We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]
Faman39
  • Faman39
So does it match with 3 or 2?
anonymous
  • anonymous
So, I believe you're right when you put B, because it is the "greatest" solution.
Faman39
  • Faman39
ok
anonymous
  • anonymous
Let's move on to the next one.
Faman39
  • Faman39
sure
anonymous
  • anonymous
\[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]
Faman39
  • Faman39
So this match with 3
anonymous
  • anonymous
Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.
Faman39
  • Faman39
ok take your time
anonymous
  • anonymous
\[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]
anonymous
  • anonymous
I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.
anonymous
  • anonymous
Oh, wait! I forgot to flip the sign one moment.
anonymous
  • anonymous
\[z<-3/5\] you flip the sign because you divided by a negative.
Faman39
  • Faman39
got a decimall number
anonymous
  • anonymous
\[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]
anonymous
  • anonymous
Yeah, let me relook over my math for the 3rd one.
Faman39
  • Faman39
@zepdrix all this still confusing to me
Faman39
  • Faman39
Can you help me?
zepdrix
  • zepdrix
Which one you stuck on? D:
Faman39
  • Faman39
all of them
Faman39
  • Faman39
I will be right back in a few minute
zepdrix
  • zepdrix
K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\] This is a spot where you have to be careful. Multiplying or Dividing by a negative value will FLIP the inequality sign. So we'll proceed by dividing by -7,\[\large z \lt -2\]
zepdrix
  • zepdrix
Take a look at those steps, see if they make sense to you. So let's think about this inequality a second. Z is LESS THAN -2. The LARGEST integer that would make this inequality true would be -3 correct? Because -3 is less than -2.
Faman39
  • Faman39
No sorry for late answer :( still didnt make sense
zepdrix
  • zepdrix
Which part? :o
Faman39
  • Faman39
Does first match up with 2, is that what you meant?
zepdrix
  • zepdrix
I didn't do the first one, I was working on the last one.
Faman39
  • Faman39
I was trying to find out where i m wrong
Faman39
  • Faman39
try an to understand how all of them match correctly
zepdrix
  • zepdrix
Well look at them one at a time. In each case, you're given an inequality with ONE VARIABLE. Since the inequality has only one variable, we can solve for that variable. It looks like you have the wrong answer for the 4th equation. Scroll back up, I listed detailed steps on how to solve the 4th one. See if any of the steps confuse you.
Faman39
  • Faman39
Can you tell me others also, cuz i m having confusion 3rd one
Faman39
  • Faman39
I m ridiculously crazy from many hours to understand all of it
zepdrix
  • zepdrix
\[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\] Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign. Dividing both sides by -5 gives us,\[\large z \lt 1\] See how the inequality sign flipped?
zepdrix
  • zepdrix
What is the LARGEST integer below the number 1? That is the value that will make z true in the 3rd equation.
Faman39
  • Faman39
sorry
zepdrix
  • zepdrix
1 is not less than 1 :D 1 is equal to 1. Think one lower than that.
Faman39
  • Faman39
0
Faman39
  • Faman39
how do you got zero
Faman39
  • Faman39
Am i wrong?
Faman39
  • Faman39
@satellite73 can you explain me all this
Faman39
  • Faman39
i cant still understand all of them
Faman39
  • Faman39
@Carl_Pham can you help me wit it
Faman39
  • Faman39
@AravindG help
AravindG
  • AravindG
YOU just need to open the brackets and bring all constants to RHS
Faman39
  • Faman39
Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it
Faman39
  • Faman39
@satellite73 can you help me ?
Faman39
  • Faman39
@mathstudent55 can you able to help me with this?
AravindG
  • AravindG
@Faman39 well i think most of them have been solved above .tell me where exactly u have doubt
Faman39
  • Faman39
ok
Faman39
  • Faman39
actually i m confuse because, i think whenever i tried to solve n match, i cant
Faman39
  • Faman39
I dont know, why my head isnt working today, where everyone did so great
Faman39
  • Faman39
Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.
Faman39
  • Faman39
Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys

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