- Faman39

Please help!

- schrodinger

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- anonymous

What do you need help with?

- Faman39

##### 1 Attachment

- Faman39

how I dont understand all this be solve and what match with what

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## More answers

- anonymous

I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?

- Faman39

Yes, cuz i have no idea.

- anonymous

Okay, well. Do you want me to explain it well? Or are you just looking for a solution?

- Faman39

Yes, please i dont understand each of this

- anonymous

Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\]
We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]

- Faman39

So does it match with 3 or 2?

- anonymous

So, I believe you're right when you put B, because it is the "greatest" solution.

- Faman39

ok

- anonymous

Let's move on to the next one.

- Faman39

sure

- anonymous

\[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]

- Faman39

So this match with 3

- anonymous

Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.

- Faman39

ok take your time

- anonymous

\[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]

- anonymous

I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.

- anonymous

Oh, wait! I forgot to flip the sign one moment.

- anonymous

\[z<-3/5\] you flip the sign because you divided by a negative.

- Faman39

got a decimall number

- anonymous

\[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]

- anonymous

Yeah, let me relook over my math for the 3rd one.

- Faman39

@zepdrix all this still confusing to me

- Faman39

Can you help me?

- zepdrix

Which one you stuck on? D:

- Faman39

all of them

- Faman39

I will be right back in a few minute

- zepdrix

K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\]
This is a spot where you have to be careful.
Multiplying or Dividing by a negative value will FLIP the inequality sign.
So we'll proceed by dividing by -7,\[\large z \lt -2\]

- zepdrix

Take a look at those steps, see if they make sense to you.
So let's think about this inequality a second.
Z is LESS THAN -2.
The LARGEST integer that would make this inequality true would be -3 correct?
Because -3 is less than -2.

- Faman39

No sorry for late answer :( still didnt make sense

- zepdrix

Which part? :o

- Faman39

Does first match up with 2, is that what you meant?

- zepdrix

I didn't do the first one, I was working on the last one.

- Faman39

I was trying to find out where i m wrong

- Faman39

try an to understand how all of them match correctly

- zepdrix

Well look at them one at a time.
In each case, you're given an inequality with ONE VARIABLE.
Since the inequality has only one variable, we can solve for that variable.
It looks like you have the wrong answer for the 4th equation.
Scroll back up, I listed detailed steps on how to solve the 4th one.
See if any of the steps confuse you.

- Faman39

Can you tell me others also, cuz i m having confusion 3rd one

- Faman39

I m ridiculously crazy from many hours to understand all of it

- zepdrix

\[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\]
Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign.
Dividing both sides by -5 gives us,\[\large z \lt 1\]
See how the inequality sign flipped?

- zepdrix

What is the LARGEST integer below the number 1?
That is the value that will make z true in the 3rd equation.

- Faman39

sorry

- zepdrix

1 is not less than 1 :D 1 is equal to 1. Think one lower than that.

- Faman39

0

- Faman39

how do you got zero

- Faman39

Am i wrong?

- Faman39

@satellite73 can you explain me all this

- Faman39

i cant still understand all of them

- Faman39

@Carl_Pham can you help me wit it

- Faman39

@AravindG help

- AravindG

YOU just need to open the brackets and bring all constants to RHS

- Faman39

Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it

- Faman39

@satellite73 can you help me ?

- Faman39

@mathstudent55 can you able to help me with this?

- AravindG

@Faman39 well i think most of them have been solved above .tell me where exactly u have doubt

- Faman39

ok

- Faman39

actually i m confuse because, i think whenever i tried to solve n match, i cant

- Faman39

I dont know, why my head isnt working today, where everyone did so great

- Faman39

Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.

- Faman39

Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys

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