Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Please help!

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
What do you need help with?
1 Attachment
how I dont understand all this be solve and what match with what

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?
Yes, cuz i have no idea.
Okay, well. Do you want me to explain it well? Or are you just looking for a solution?
Yes, please i dont understand each of this
Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\] We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]
So does it match with 3 or 2?
So, I believe you're right when you put B, because it is the "greatest" solution.
ok
Let's move on to the next one.
sure
\[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]
So this match with 3
Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.
ok take your time
\[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]
I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.
Oh, wait! I forgot to flip the sign one moment.
\[z<-3/5\] you flip the sign because you divided by a negative.
got a decimall number
\[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]
Yeah, let me relook over my math for the 3rd one.
@zepdrix all this still confusing to me
Can you help me?
Which one you stuck on? D:
all of them
I will be right back in a few minute
K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\] This is a spot where you have to be careful. Multiplying or Dividing by a negative value will FLIP the inequality sign. So we'll proceed by dividing by -7,\[\large z \lt -2\]
Take a look at those steps, see if they make sense to you. So let's think about this inequality a second. Z is LESS THAN -2. The LARGEST integer that would make this inequality true would be -3 correct? Because -3 is less than -2.
No sorry for late answer :( still didnt make sense
Which part? :o
Does first match up with 2, is that what you meant?
I didn't do the first one, I was working on the last one.
I was trying to find out where i m wrong
try an to understand how all of them match correctly
Well look at them one at a time. In each case, you're given an inequality with ONE VARIABLE. Since the inequality has only one variable, we can solve for that variable. It looks like you have the wrong answer for the 4th equation. Scroll back up, I listed detailed steps on how to solve the 4th one. See if any of the steps confuse you.
Can you tell me others also, cuz i m having confusion 3rd one
I m ridiculously crazy from many hours to understand all of it
\[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\] Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign. Dividing both sides by -5 gives us,\[\large z \lt 1\] See how the inequality sign flipped?
What is the LARGEST integer below the number 1? That is the value that will make z true in the 3rd equation.
sorry
1 is not less than 1 :D 1 is equal to 1. Think one lower than that.
0
how do you got zero
Am i wrong?
@satellite73 can you explain me all this
i cant still understand all of them
@Carl_Pham can you help me wit it
YOU just need to open the brackets and bring all constants to RHS
Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it
@satellite73 can you help me ?
@mathstudent55 can you able to help me with this?
@Faman39 well i think most of them have been solved above .tell me where exactly u have doubt
ok
actually i m confuse because, i think whenever i tried to solve n match, i cant
I dont know, why my head isnt working today, where everyone did so great
Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.
Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys

Not the answer you are looking for?

Search for more explanations.

Ask your own question