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kelberryBest ResponseYou've already chosen the best response.1
What do you need help with?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
how I dont understand all this be solve and what match with what
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Yes, cuz i have no idea.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Okay, well. Do you want me to explain it well? Or are you just looking for a solution?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Yes, please i dont understand each of this
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Okay, so let's start with the first equation\[2(1+z)+4z+5<11\] We simplify the right side\[2+2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
So does it match with 3 or 2?
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
So, I believe you're right when you put B, because it is the "greatest" solution.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Let's move on to the next one.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
\[3z10+5z8<6\]\[8z18<6\]\[8z<24\]\[z<3\]
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
\[z+5(1+6z)>1\]\[z+516z>1\]\[z+46z>1\]\[5z>3\]\[z>3/5\]
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Oh, wait! I forgot to flip the sign one moment.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
\[z<3/5\] you flip the sign because you divided by a negative.
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
\[8z19+z>5\]\[7z19>5\]\[7z>14\]\[z<2\]
 one year ago

kelberryBest ResponseYou've already chosen the best response.1
Yeah, let me relook over my math for the 3rd one.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@zepdrix all this still confusing to me
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
Which one you stuck on? D:
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I will be right back in a few minute
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
K let's look at the last one a sec.\[\large8z19+z \gt 5\]We'll start by combining like terms, the 8z and z.\[\large 7z19 \gt 5\]Add 19 to both sides,\[\large 7z \gt14\] This is a spot where you have to be careful. Multiplying or Dividing by a negative value will FLIP the inequality sign. So we'll proceed by dividing by 7,\[\large z \lt 2\]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
Take a look at those steps, see if they make sense to you. So let's think about this inequality a second. Z is LESS THAN 2. The LARGEST integer that would make this inequality true would be 3 correct? Because 3 is less than 2.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
No sorry for late answer :( still didnt make sense
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Does first match up with 2, is that what you meant?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
I didn't do the first one, I was working on the last one.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I was trying to find out where i m wrong
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
try an to understand how all of them match correctly
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
Well look at them one at a time. In each case, you're given an inequality with ONE VARIABLE. Since the inequality has only one variable, we can solve for that variable. It looks like you have the wrong answer for the 4th equation. Scroll back up, I listed detailed steps on how to solve the 4th one. See if any of the steps confuse you.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Can you tell me others also, cuz i m having confusion 3rd one
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I m ridiculously crazy from many hours to understand all of it
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
\[\large z+5(1+6z) \gt1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+516z \gt 1\]Combine the z terms,\[\large 515z \gt 1\]Combine the 5 and 1,\[\large 45z \gt1\]Subtract 4 from each side,\[\large 5z \gt5\] Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign. Dividing both sides by 5 gives us,\[\large z \lt 1\] See how the inequality sign flipped?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
What is the LARGEST integer below the number 1? That is the value that will make z true in the 3rd equation.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
1 is not less than 1 :D 1 is equal to 1. Think one lower than that.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@satellite73 can you explain me all this
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
i cant still understand all of them
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@Carl_Pham can you help me wit it
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
YOU just need to open the brackets and bring all constants to RHS
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@satellite73 can you help me ?
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
@mathstudent55 can you able to help me with this?
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
@Faman39 well i think most of them have been solved above .tell me where exactly u have doubt
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
actually i m confuse because, i think whenever i tried to solve n match, i cant
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
I dont know, why my head isnt working today, where everyone did so great
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.
 one year ago

Faman39Best ResponseYou've already chosen the best response.0
Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys
 one year ago
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