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Faman39

  • one year ago

Please help!

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  1. kelberry
    • one year ago
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    What do you need help with?

  2. Faman39
    • one year ago
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  3. Faman39
    • one year ago
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    how I dont understand all this be solve and what match with what

  4. kelberry
    • one year ago
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    I see, what you're supposed to do is simplify each equation, and then it will make more sense which are the answers. Do you need help with that?

  5. Faman39
    • one year ago
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    Yes, cuz i have no idea.

  6. kelberry
    • one year ago
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    Okay, well. Do you want me to explain it well? Or are you just looking for a solution?

  7. Faman39
    • one year ago
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    Yes, please i dont understand each of this

  8. kelberry
    • one year ago
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    Okay, so let's start with the first equation\[-2(1+z)+4z+5<11\] We simplify the right side\[-2+-2z+4z+5 <11\]\[2z+3<11\]\[2z<8\]\[z<4\]

  9. Faman39
    • one year ago
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    So does it match with 3 or 2?

  10. kelberry
    • one year ago
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    So, I believe you're right when you put B, because it is the "greatest" solution.

  11. Faman39
    • one year ago
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    ok

  12. kelberry
    • one year ago
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    Let's move on to the next one.

  13. Faman39
    • one year ago
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    sure

  14. kelberry
    • one year ago
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    \[3z-10+5z-8<6\]\[8z-18<6\]\[8z<24\]\[z<3\]

  15. Faman39
    • one year ago
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    So this match with 3

  16. kelberry
    • one year ago
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    Uhh, wait one minute, let me finish the rest of them. This is an odd question, heh.

  17. Faman39
    • one year ago
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    ok take your time

  18. kelberry
    • one year ago
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    \[z+5-(1+6z)>-1\]\[z+5-1-6z>-1\]\[z+4-6z>-1\]\[-5z>3\]\[z>-3/5\]

  19. kelberry
    • one year ago
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    I think for the 3rd equation you need to put C, because it is the "greatest" solution being that is is the furthest one away.

  20. kelberry
    • one year ago
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    Oh, wait! I forgot to flip the sign one moment.

  21. kelberry
    • one year ago
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    \[z<-3/5\] you flip the sign because you divided by a negative.

  22. Faman39
    • one year ago
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    got a decimall number

  23. kelberry
    • one year ago
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    \[-8z-19+z>-5\]\[-7z-19>-5\]\[-7z>14\]\[z<-2\]

  24. kelberry
    • one year ago
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    Yeah, let me relook over my math for the 3rd one.

  25. Faman39
    • one year ago
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    @zepdrix all this still confusing to me

  26. Faman39
    • one year ago
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    Can you help me?

  27. zepdrix
    • one year ago
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    Which one you stuck on? D:

  28. Faman39
    • one year ago
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    all of them

  29. Faman39
    • one year ago
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    I will be right back in a few minute

  30. zepdrix
    • one year ago
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    K let's look at the last one a sec.\[\large-8z-19+z \gt -5\]We'll start by combining like terms, the -8z and z.\[\large -7z-19 \gt -5\]Add 19 to both sides,\[\large -7z \gt14\] This is a spot where you have to be careful. Multiplying or Dividing by a negative value will FLIP the inequality sign. So we'll proceed by dividing by -7,\[\large z \lt -2\]

  31. zepdrix
    • one year ago
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    Take a look at those steps, see if they make sense to you. So let's think about this inequality a second. Z is LESS THAN -2. The LARGEST integer that would make this inequality true would be -3 correct? Because -3 is less than -2.

  32. Faman39
    • one year ago
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    No sorry for late answer :( still didnt make sense

  33. zepdrix
    • one year ago
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    Which part? :o

  34. Faman39
    • one year ago
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    Does first match up with 2, is that what you meant?

  35. zepdrix
    • one year ago
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    I didn't do the first one, I was working on the last one.

  36. Faman39
    • one year ago
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    I was trying to find out where i m wrong

  37. Faman39
    • one year ago
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    try an to understand how all of them match correctly

  38. zepdrix
    • one year ago
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    Well look at them one at a time. In each case, you're given an inequality with ONE VARIABLE. Since the inequality has only one variable, we can solve for that variable. It looks like you have the wrong answer for the 4th equation. Scroll back up, I listed detailed steps on how to solve the 4th one. See if any of the steps confuse you.

  39. Faman39
    • one year ago
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    Can you tell me others also, cuz i m having confusion 3rd one

  40. Faman39
    • one year ago
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    I m ridiculously crazy from many hours to understand all of it

  41. zepdrix
    • one year ago
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    \[\large z+5-(1+6z) \gt-1\]We'll start by distributing the negative to each term inside the brackets,\[\large z+5-1-6z \gt -1\]Combine the z terms,\[\large 5-1-5z \gt -1\]Combine the 5 and 1,\[\large 4-5z \gt-1\]Subtract 4 from each side,\[\large -5z \gt-5\] Again we have to be careful here. When we divide by a negative number we'll have to FLIP the direction of the inequality sign. Dividing both sides by -5 gives us,\[\large z \lt 1\] See how the inequality sign flipped?

  42. zepdrix
    • one year ago
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    What is the LARGEST integer below the number 1? That is the value that will make z true in the 3rd equation.

  43. Faman39
    • one year ago
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    sorry

  44. zepdrix
    • one year ago
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    1 is not less than 1 :D 1 is equal to 1. Think one lower than that.

  45. Faman39
    • one year ago
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    0

  46. Faman39
    • one year ago
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    how do you got zero

  47. Faman39
    • one year ago
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    Am i wrong?

  48. Faman39
    • one year ago
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    @satellite73 can you explain me all this

  49. Faman39
    • one year ago
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    i cant still understand all of them

  50. Faman39
    • one year ago
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    @Carl_Pham can you help me wit it

  51. Faman39
    • one year ago
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    @AravindG help

  52. AravindG
    • one year ago
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    YOU just need to open the brackets and bring all constants to RHS

  53. Faman39
    • one year ago
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    Can you show it how all can be n match up, i still couldnt get correct answer of all and didnt even understand any of it

  54. Faman39
    • one year ago
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    @satellite73 can you help me ?

  55. Faman39
    • one year ago
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    @mathstudent55 can you able to help me with this?

  56. AravindG
    • one year ago
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    @Faman39 well i think most of them have been solved above .tell me where exactly u have doubt

  57. Faman39
    • one year ago
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    ok

  58. Faman39
    • one year ago
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    actually i m confuse because, i think whenever i tried to solve n match, i cant

  59. Faman39
    • one year ago
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    I dont know, why my head isnt working today, where everyone did so great

  60. Faman39
    • one year ago
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    Sorry everybody, you all are totally amazing, i really appreciate all of you to come here n helping me.

  61. Faman39
    • one year ago
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    Honestly all of you are totally rocking, thank you so much guys for helping me by tolerating me, love you guys

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