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nathaly95

  • 3 years ago

Factor the trinomial below. 9x2 + 6x + 1

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  1. nathaly95
    • 3 years ago
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    3?

  2. Kuoministers
    • 3 years ago
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    you need 2 numbers

  3. AravindG
    • 3 years ago
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    first of all \[\huge \color{green}{\text{WELCOME TO OPENSTUDY!}}\]

  4. nathaly95
    • 3 years ago
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    Thanks Aravind!

  5. Kuoministers
    • 3 years ago
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    \[\Huge{\color{Green}{\rightarrow \boxed{\mathbb{\text{WELCOME}{}}}{\color{green}{\color{blue}TO{\color{purple}O!}}}}} \]

  6. nathaly95
    • 3 years ago
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    Sorry and Thanks you!

  7. mathmate
    • 3 years ago
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    Looks like a perfect square of the form (a+b)^2=a^2+2ab+b^2 if you look at the question as: (3x)^2+6x+1

  8. GCR92
    • 3 years ago
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    Solve the equation using the quadratic formula, equal the whole expression to 0 and proceed, then you'll obtain 2 values of x, for example, if you get x=1 and x=2, to put it as a product you must put it with the sign changed, in this example it would be (x-1)(x-2). Sometimes you can't use the quadratic formula, I suggest you learn to factor in this order: 1-Common Factor. 2-Notable pars. 3-Ruffini Rule (you should always use this in order to factor powers above 2) 4-Quadratic formula can only be applied when you have an equation in the form Ax^2 + By + c = 0 \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

  9. nathaly95
    • 3 years ago
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    Thanks

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