anonymous
  • anonymous
If the cross-section of a wire of fixed length is doubled, how does the resistance of that wire change? (this is for studying for my semester exam. I got the question wrong on one of my chapter tests so I'm trying to find out what the correct answer was) A. Halved B. Doubled (I know it's NOT this cause that was the wrong one) C. Unchanged D. Quadrupled
Physics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Apart from using the right formula (there's one that relates the resistance of a wire to its length and cross-section), you could try an analogy. For currents and resistors, compraing the situation with water flows usually works. What would the equivalent of resistance be in a flowing river? And what would happen when the river suddenly becomes wider?
anonymous
  • anonymous
Would that make it halved?
anonymous
  • anonymous
Yes it would. A wider river/wire would allow the current to flow easier (and thus with less resistance). The formula I mentioned is \[R = \rho\frac{l}{A}\] (see e.g. http://www.physicsclassroom.com/class/circuits/u9l3b.cfm )

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yay!!! Thank you!!!
anonymous
  • anonymous
No problem!

Looking for something else?

Not the answer you are looking for? Search for more explanations.