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quarkine

When we bring charge from infinity to free space,the work done is said to be zero.but by bringing the charge we are actually creating the electric field in the free space.so if we integrate the energy density wrt volume,surely the answer should come non-zero...so some energy got stored in space due to our bringing of charge..so shouldn't it require work to be done to create the E field i.e to bring the single charge??

  • one year ago
  • one year ago

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  1. Mashy
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    I don't understand your integrating stuff.. but.. there is no work done cause.. there is no other charge .. hence there is not other field.. and hence there is not resistance to this charge that you are bringing into this finite world.. !!.. and hence we say we didn't need to do any work.. !

    • one year ago
  2. Mashy
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    and strictly speaking.. you are not CREATING field as such.. its already there.. associated with the charge.. its an intrinsic property of the charge..

    • one year ago
  3. Mashy
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    why ain't anyone replying? :D was my reply so awesome? :D that it rendered you guys speechless? :D

    • one year ago
  4. quarkine
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    well i guess everyone will at first think of this answer only...it most probably is right...still something fishy is going on with the field storing the energy thing.any other opinion about this,anyone???

    • one year ago
  5. rajathsbhat
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    @Mashy is right. And i don't understand why you think some energy is stored in space just because the charge is moved through it. As far as I'm concerned, moving a charge from point A to point B infinitesimally slowly is equivalent to not moving the charge at all.

    • one year ago
  6. Carl_Pham
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    You're not creating the field, it's already there. All you're doing is changing its strength in two different places (infinity and right here). Whatever work you do increasing the strength of the field here is exactly matched by the work released when the field decreases at infinity, because the interactions of the charge are identical in both places. Infinity isn't any stranger place than 5 m away, in this case, and you don't think you would do work moving the charge 5 m to the left in empty space, do you?

    • one year ago
  7. Carl_Pham
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    You certainly must do work to *create* the field in the first place, and if you are talking about *creating* a charge out of nowhere, then that will indeed require energy. If you are asking about the additional energy required to create an electric charge, beyond that required just to create an uncharged particle of the same mass, that is a subtle question, and I'm not 100% sure of the answer, if an answer is even possible.

    • one year ago
  8. salini
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    this is a nice question.......we say there is no work done because we bring the charge under the absence of any external electric field but your point is that when u move a charge in space it creates an electric field of itself....well yes it does but doesnt get affected by it as work done is E.ds=Edscos@ when theta is 90 no work is done so considering a point charge to emit electric field in a radial field to its direction of motion @=90 and work done is 0 |dw:1372474806287:dw|

    • 9 months ago
  9. Mashy
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    But Salini, that only holds good when you are doing the work IN AN EXTERNAL FIELD, here, the object (charge itself) has electric field, and we are talking about that field. So I agree with Carl that when you do positive work in CREATING electric field here, you also sort of do negative work in REMOVING the electric field at infinity.. and so the net work you do is zero!

    • 9 months ago
  10. quarkine
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    well been away for a long time... i thought about it and figured that the work done is zero.but the reason i was looking for is that when we bring a charge somewhere electric field is created-so we may believe that we have done some work. But in reality,before bring the charge there,it was somewhere else.we just shifted the electric field associated around the charge from that region to a new region of space.

    • 8 months ago
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