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swiftskier96
Group Title
15.
You live near a bridge that goes over a river. The underside of the bridge is an arch that can be modeled with the function y = –0.000471x² + .837x where x and y are measured in feet. How high above the river is the bridge (the top of the arch)? How long is the section of bridge above the arch? (1 point)
The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 888.54 ft.
The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 1,777.07 ft.
The bridge is about 371.85 ft. above the
 one year ago
 one year ago
swiftskier96 Group Title
15. You live near a bridge that goes over a river. The underside of the bridge is an arch that can be modeled with the function y = –0.000471x² + .837x where x and y are measured in feet. How high above the river is the bridge (the top of the arch)? How long is the section of bridge above the arch? (1 point) The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 1,777.07 ft. The bridge is about 371.85 ft. above the
 one year ago
 one year ago

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swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
15. You live near a bridge that goes over a river. The underside of the bridge is an arch that can be modeled with the function y = –0.000471x² + .837x where x and y are measured in feet. How high above the river is the bridge (the top of the arch)? How long is the section of bridge above the arch? (1 point) The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 1,777.07 ft. The bridge is about 371.85 ft. above the river, and the length of the bridge above the arch is about 888.54 ft. The bridge is about 1,777.07 ft. above the river, and the length of the bridge above the arch is about 371.85 ft.
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
@Frostbite
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
Swiftskier you can do differentiation right?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
I remember learning it, but i dont remember how to do it.
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
Alright because if I understand the question right (maybe, maybe not) we can do the following: \[\frac{ dy }{ dx }=\left( 4.7*10^{4} x ^{2}+0.837x\right)^{'}=0.8379.42*10^{4}x\] We check for horizontal tangent: \[\frac{ dy }{ dx }=0\] \[0.8379.42*10^{4}x=0\] \[x=888.535\] Then you can check for y your self, think it is right? or have I misunderstood the question?
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
ment 4.71 in the first equation sorry.
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
Well it shortens it because now i know its either A or C.
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
you check for A or C by insetting the x value inside the original equation
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
Ok ill try that.
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
I get the following result, but please make a check your self. \[4.71*10^{4}*888.535^{2}+0.837*888.535=371.852\]
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
and see if you agree
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.0
Yeah i got the same. So its C then. :) Thanks for all the help!!!!!
 one year ago

Frostbite Group TitleBest ResponseYou've already chosen the best response.2
No problem :)
 one year ago
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