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Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1Use the equation below to find the value of sin x. \[\frac{ \tan x }{ \cot x }  \frac{ \sec x }{ \cos x }= \frac{ 2 }{ \csc x }\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0write everything in terms of sin and cos

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1That is what I am not understanding. I have a really hard time writting out what it is supposed to be once you start changing everything.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Hint: Write it this way. Then simply change everything to sin and cos \[\tan(x) \div \cot(x)  \sec(x) \div \cos(x) = 2 \div \csc(x)\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1So how would you change it?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{\sin(x)}{\cos(x)} \div \frac{\cos(x)}{\sin(x)}  \frac{1}{\cos(x)} \div \cos(x) = 2 \div \frac{1}{\sin(x)}\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so could the first two fracts cancel out?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2How do you divide: \[\frac{1}{4} \div \frac{7}{6}\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1Why not? BTW i missed the lessons over this stuff so i am really lost on almost all of it.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Answer the previous question. How do you divide that?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1you switch the #'s of the second fraction so it is now 6/7 and you change divide to multiply. you now have 1/4 X 6/7 which is 6/28 simplified to 3/14

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Yes, so do that same thing with the trig equation

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so it is now \[\frac{ \sin^2x }{ \cos^2x }\frac{ 1 }{ \cos x }\div \cos x=2\div \frac{ 1 }{ \sin x }\]??

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Yes, but do the rest of them. Change all of the divisions into multiplication.

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so it looks like\[\frac{ \sin^2x }{ \cos^2x }\frac{ 1 }{ cosx }\times \frac{ cosx }{ 1 }=2\times \frac{ sinx }{ 1 }\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1If so, wouldn't 1/cosx times cosx/1 cancel out?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2no, you did the cos(x)/1 incorrectly. cos(x) is already equal to cos(x)/1. You have to flip it.

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1oh duh ok so then it is \[\frac{ \sin^2 x}{ \cos^2x } \frac{ 1 }{ \cos x }\times \frac{ 1 }{ \cos x }= 2\times \frac{ sinx }{ 1 }\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so do the mult fractions combine to get 1/cos^2x

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so then what do you do?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Yes, so what do you have after that?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ \sin^2x }{ \cos^2x }\frac{ 1 }{ \cos^2x }= 2\times \frac{ sinx }{ 1 }\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Okay, do you know how to combine fractions on the left side?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1couldn't you turn 2x(sinx/1) into just 2sinx? and Im not sure what to do on the other side

Hero
 one year ago
Best ResponseYou've already chosen the best response.2On the left side, you have to combine fractions if they have the same denominator.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2For example: \[\frac{1}{4} + \frac{x}{4} = \frac{1 + x}{4}\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2The general rule for combining fractions with the same denominator is: \[\frac{a}{c} + \frac{b}{c} = \frac{a+b}{c}\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1so it is now \[\frac{ \sin^2x1 }{ \cos^2x }=2sinx\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1or is the 2sin x supposed to be sin^2x

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Now change the 1 to \(\sin^2x + \cos^2x\)

Hero
 one year ago
Best ResponseYou've already chosen the best response.2No, you have it right. 2sin(x)

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1wait, you put sin^2x + cos^2x instead of one? what is the new equation?

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Yes, you put \(\sin^2x + \cos^2x\) in place of 1 because they are equal.

Hero
 one year ago
Best ResponseYou've already chosen the best response.2What do you get afterwards?

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ \sin^2x\sin^2x+\cos^2x }{ \cos^2x }=2sinx\] then you can subtract the sin^2x to get \[\frac{ \cos^2x }{ \cos^2x }=2sinx\] then if thats the case you would just have 2sinx

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Actually, if you do it correctly you get: \[\frac{ \cos^2x }{ \cos^2x }=2\sin x\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Which simplifies to \[1 = 2 \sin x\] Remember that we are still solving for x

Hero
 one year ago
Best ResponseYou've already chosen the best response.2You were supposed to get this after substituting the 1: \[\frac{ \sin^2x(\sin^2x+\cos^2x) }{ \cos^2x }=2\sin x\] Then get : \[\frac{ \sin^2x\sin^2xcos^2x }{ \cos^2x }=2\sin x\]

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1or no sinx would be 1/2

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Ultimately you end up isolating the sin(x) on the right side: \[\frac{1}{2} = \sin x\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Now all you have to do is take the inverse sin of both sides to get \[\sin^{1}\left(\frac{1}{2}\right) = x\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2So evaluate the left side using your calc. Let me know what you get. Also make sure it is in radian mode.

Rosy95
 one year ago
Best ResponseYou've already chosen the best response.1And thank you for your help :)

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Well, in exact mode, you should have gotten \[x = \frac{\pi}{6}\]

Hero
 one year ago
Best ResponseYou've already chosen the best response.2Nevertheless:\[\frac{\pi}{6} \approx .52\]
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