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anonymous
 4 years ago
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anonymous
 4 years ago
green

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blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0I know about Pascal's triangle, but I don't know if that's what you're referring to.

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, do need an explanation of what it is, or do you have a problem you want me to look at?

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, do you know how to expand a binomial (something)^2?

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, let's start there then. Say you have something like (x + y)^2 and we want to expand that. You can rewrite (x + y)^2 so that it's like: (x + y)(x + y) Make sense so far?

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Good, now we're going to multiply the first x in (x + y) to BOTH the (x + y) in the other term to get: x^2 + xy dw:1358369073609:dw

precal
 4 years ago
Best ResponseYou've already chosen the best response.0pascal's triangle is use to expand

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Great, then we move on and do the same thing with the first y. and get xy + y^2, so in total we have x^2 + xy + xy + y^2

precal
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358369198853:dwdo you see the pattern?

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0@precal, that's what im attempting to show. thanks for the visual though :)

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0perfect, so we have x^2 + xy + xy + y^2 which equals x^2 + 2xy + y^2, which is what precal's picture shows

precal
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358369387693:dwthen notice what is happening to the x powers and then the y powers

precal
 4 years ago
Best ResponseYou've already chosen the best response.0x powers start at 2 while y start at 0

precal
 4 years ago
Best ResponseYou've already chosen the best response.0this is the pattern you will follow for you problem

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0Now, if we wanted to take that further like (x +y)^3 (like your problem) we can do two things.

precal
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1358369548166:dwyou will use the 3rd row

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0We could multiply (x + y)(x^2 + 2xy + y^2) And do the EXACT same thing like how we were multiplying the x to the second term and then the y to the second term.

blurbendy
 4 years ago
Best ResponseYou've already chosen the best response.0That would give us the correct answer, OR we could use the pattern precal is showing us.

precal
 4 years ago
Best ResponseYou've already chosen the best response.0be careful with your second term because of the negative, just simplify and you are done
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