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morganalana17 Group Title

green

  • one year ago
  • one year ago

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  1. blurbendy Group Title
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    I know about Pascal's triangle, but I don't know if that's what you're referring to.

    • one year ago
  2. blurbendy Group Title
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    Sure, do need an explanation of what it is, or do you have a problem you want me to look at?

    • one year ago
  3. blurbendy Group Title
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    you*

    • one year ago
  4. hba Group Title
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    http://mathworld.wolfram.com/PascalsTheorem.html

    • one year ago
  5. blurbendy Group Title
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    Sure, do you know how to expand a binomial (something)^2?

    • one year ago
  6. blurbendy Group Title
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    Okay, let's start there then. Say you have something like (x + y)^2 and we want to expand that. You can rewrite (x + y)^2 so that it's like: (x + y)(x + y) Make sense so far?

    • one year ago
  7. blurbendy Group Title
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    Good, now we're going to multiply the first x in (x + y) to BOTH the (x + y) in the other term to get: x^2 + xy |dw:1358369073609:dw|

    • one year ago
  8. blurbendy Group Title
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    Make sense?

    • one year ago
  9. precal Group Title
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    pascal's triangle is use to expand

    • one year ago
  10. precal Group Title
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    |dw:1358369183479:dw|

    • one year ago
  11. blurbendy Group Title
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    Great, then we move on and do the same thing with the first y. and get xy + y^2, so in total we have x^2 + xy + xy + y^2

    • one year ago
  12. precal Group Title
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    |dw:1358369198853:dw|do you see the pattern?

    • one year ago
  13. blurbendy Group Title
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    @precal, that's what im attempting to show. thanks for the visual though :)

    • one year ago
  14. blurbendy Group Title
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    perfect, so we have x^2 + xy + xy + y^2 which equals x^2 + 2xy + y^2, which is what precal's picture shows

    • one year ago
  15. precal Group Title
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    |dw:1358369366989:dw|

    • one year ago
  16. precal Group Title
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    |dw:1358369387693:dw|then notice what is happening to the x powers and then the y powers

    • one year ago
  17. precal Group Title
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    x powers start at 2 while y start at 0

    • one year ago
  18. precal Group Title
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    this is the pattern you will follow for you problem

    • one year ago
  19. blurbendy Group Title
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    Now, if we wanted to take that further like (x +y)^3 (like your problem) we can do two things.

    • one year ago
  20. precal Group Title
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    |dw:1358369548166:dw|you will use the 3rd row

    • one year ago
  21. precal Group Title
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    |dw:1358369588020:dw|

    • one year ago
  22. blurbendy Group Title
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    We could multiply (x + y)(x^2 + 2xy + y^2) And do the EXACT same thing like how we were multiplying the x to the second term and then the y to the second term.

    • one year ago
  23. blurbendy Group Title
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    That would give us the correct answer, OR we could use the pattern precal is showing us.

    • one year ago
  24. precal Group Title
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    |dw:1358369600649:dw|

    • one year ago
  25. precal Group Title
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    be careful with your second term because of the negative, just simplify and you are done

    • one year ago
  26. precal Group Title
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    yw

    • one year ago
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