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blurbendyBest ResponseYou've already chosen the best response.0
I know about Pascal's triangle, but I don't know if that's what you're referring to.
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Sure, do need an explanation of what it is, or do you have a problem you want me to look at?
 one year ago

hbaBest ResponseYou've already chosen the best response.0
http://mathworld.wolfram.com/PascalsTheorem.html
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Sure, do you know how to expand a binomial (something)^2?
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Okay, let's start there then. Say you have something like (x + y)^2 and we want to expand that. You can rewrite (x + y)^2 so that it's like: (x + y)(x + y) Make sense so far?
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Good, now we're going to multiply the first x in (x + y) to BOTH the (x + y) in the other term to get: x^2 + xy dw:1358369073609:dw
 one year ago

precalBest ResponseYou've already chosen the best response.0
pascal's triangle is use to expand
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Great, then we move on and do the same thing with the first y. and get xy + y^2, so in total we have x^2 + xy + xy + y^2
 one year ago

precalBest ResponseYou've already chosen the best response.0
dw:1358369198853:dwdo you see the pattern?
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
@precal, that's what im attempting to show. thanks for the visual though :)
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
perfect, so we have x^2 + xy + xy + y^2 which equals x^2 + 2xy + y^2, which is what precal's picture shows
 one year ago

precalBest ResponseYou've already chosen the best response.0
dw:1358369387693:dwthen notice what is happening to the x powers and then the y powers
 one year ago

precalBest ResponseYou've already chosen the best response.0
x powers start at 2 while y start at 0
 one year ago

precalBest ResponseYou've already chosen the best response.0
this is the pattern you will follow for you problem
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
Now, if we wanted to take that further like (x +y)^3 (like your problem) we can do two things.
 one year ago

precalBest ResponseYou've already chosen the best response.0
dw:1358369548166:dwyou will use the 3rd row
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
We could multiply (x + y)(x^2 + 2xy + y^2) And do the EXACT same thing like how we were multiplying the x to the second term and then the y to the second term.
 one year ago

blurbendyBest ResponseYou've already chosen the best response.0
That would give us the correct answer, OR we could use the pattern precal is showing us.
 one year ago

precalBest ResponseYou've already chosen the best response.0
be careful with your second term because of the negative, just simplify and you are done
 one year ago
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