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ErinWeeks

  • one year ago

What is the y−coordinate of the y−intercept of the line that passes through the points (−4, −4) and (4, 8)? The only question im stuck on PLEASE HELP! :)

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  1. precal
    • one year ago
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    figure out the slope then use y=mx+b and sub the slope for m and use one of the points for (x,y) to solve for b. b is our answer

  2. ErinWeeks
    • one year ago
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    Is there anyway you could start the equation of for me?

  3. precal
    • one year ago
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    |dw:1358369271960:dw|tell me what the slope is first

  4. ErinWeeks
    • one year ago
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    the slope would be M right but where am I looking for the slope for with the fraction?

  5. precal
    • one year ago
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    you need the slope to be able to use it in y=mx+b then you can use one of the points I would use (4,8) x=4 y=8 then you are solving for b. b is known as your y intercept and that is what you are looking for

  6. ErinWeeks
    • one year ago
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    So I have so far y= ? + 8 Would I plug in the 4?

  7. precal
    • one year ago
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    |dw:1358370299889:dw|you need the slope to sub the m value and solve for b

  8. ErinWeeks
    • one year ago
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    Alright so what operation would I do from here?

  9. Carolin
    • one year ago
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    next, u can just substitute the M = gradient = slope into this equations to find value b

  10. Carolin
    • one year ago
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    then, rewrite the equation form in y = mx + b

  11. ErinWeeks
    • one year ago
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    Whats the value for m?

  12. ErinWeeks
    • one year ago
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    im so confused on what to do I might just guess lbvs...

  13. Carolin
    • one year ago
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    m = 3/2

  14. Carolin
    • one year ago
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    y = mx + b 8 = (3/2)(4) + b 8 = 6 + b b = 8 -6 = 2 then, rewrite the equation: y = mx + b y = 3/2 x + 2 That the final answer

  15. ErinWeeks
    • one year ago
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    Oh you times by 4 DURR! Thank you so much I really appreciate it that makes so much more sense! Thank you again :)

  16. ErinWeeks
    • one year ago
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    so y=3/2x+2 is my answer?

  17. Carolin
    • one year ago
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    yup :)

  18. Carolin
    • one year ago
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    welcome^^

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