Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?
 one year ago
 one year ago
When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?
 one year ago
 one year ago

This Question is Closed

joemath314159Best ResponseYou've already chosen the best response.1
You need to do a u substitution. you have this right now:\[\int\limits_{2}^{5}h(x)dx = 11\]and the question is:\[\int\limits_{0}^{7}h(x2)dx=?\]So start with:\[\int\limits_{0}^{7}h(x2)dx\]Let u = x2, then du=dx, and your lower limit changes to:\[02=2\]while your upper limit becomes:\[72=5\]So with your substitution in place, you see that:\[\int\limits_{0}^{7}h(x2)dx=\int\limits_{2}^{5}h(u)du\]
 one year ago

Bladerunner1122Best ResponseYou've already chosen the best response.1
Wow, ok so that means the answer IS 11.
 one year ago

joemath314159Best ResponseYou've already chosen the best response.1
yes, thats correct :)
 one year ago

Bladerunner1122Best ResponseYou've already chosen the best response.1
I'm in it for the "how to." This tells me how to solve the last fourth of my homework.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.