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Bladerunner1122
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When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?
 one year ago
 one year ago
Bladerunner1122 Group Title
When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?
 one year ago
 one year ago

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joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
You need to do a u substitution. you have this right now:\[\int\limits_{2}^{5}h(x)dx = 11\]and the question is:\[\int\limits_{0}^{7}h(x2)dx=?\]So start with:\[\int\limits_{0}^{7}h(x2)dx\]Let u = x2, then du=dx, and your lower limit changes to:\[02=2\]while your upper limit becomes:\[72=5\]So with your substitution in place, you see that:\[\int\limits_{0}^{7}h(x2)dx=\int\limits_{2}^{5}h(u)du\]
 one year ago

Bladerunner1122 Group TitleBest ResponseYou've already chosen the best response.1
Thank you!!
 one year ago

Bladerunner1122 Group TitleBest ResponseYou've already chosen the best response.1
Wow, ok so that means the answer IS 11.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
yes, thats correct :)
 one year ago

Bladerunner1122 Group TitleBest ResponseYou've already chosen the best response.1
I'm in it for the "how to." This tells me how to solve the last fourth of my homework.
 one year ago
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