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 one year ago
When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?
 one year ago
When the integral from 2 to 5 has h(x)dx=11. How do you solve the integral from 0 to 7 has h(x2)dx=?

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joemath314159
 one year ago
Best ResponseYou've already chosen the best response.1You need to do a u substitution. you have this right now:\[\int\limits_{2}^{5}h(x)dx = 11\]and the question is:\[\int\limits_{0}^{7}h(x2)dx=?\]So start with:\[\int\limits_{0}^{7}h(x2)dx\]Let u = x2, then du=dx, and your lower limit changes to:\[02=2\]while your upper limit becomes:\[72=5\]So with your substitution in place, you see that:\[\int\limits_{0}^{7}h(x2)dx=\int\limits_{2}^{5}h(u)du\]

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.1Wow, ok so that means the answer IS 11.

joemath314159
 one year ago
Best ResponseYou've already chosen the best response.1yes, thats correct :)

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.1I'm in it for the "how to." This tells me how to solve the last fourth of my homework.
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