## iluvvyyhu 2 years ago Can someone explain to me how i would solve this problem thanks <3 "Estimate graphically the local maximum and local minimum of f(x)=((1/4)x^5)+(x^2)-4x"?

1. iluvvyyhu

o-o i have a graphing calculator since the review worksheet said i needed one x.x but im not sure how to use it so ya... fail x.x

2. JamesWolf

the local maximum is when the rate of change between x and y is 0|dw:1358379289305:dw|

3. JamesWolf

the rate of change between x and y is found by taking the derivative

4. JamesWolf

then you can find where the maximum and minimum are by solving $\frac{ dy }{ dx } = 0$

5. iluvvyyhu

im sorry but im still confused x.x what would i plug into that formula? ^-^;

6. JamesWolf

Do you know how to find the derivative of the formula in the question?

7. iluvvyyhu

no :(

8. JamesWolf

is this homework? what topic are you doing at the moment?

9. iluvvyyhu

its a segment review for my exam x.x and its pre-calc

10. iluvvyyhu

i switched schools so some of the stuff i dont know x.x

11. JamesWolf

yeah your going to need to put the function into your graph and just see where the maximum and minimum are, and guess

12. JamesWolf

have a look on google for an instruction book for your calc

13. iluvvyyhu

okay:/ thanks though <3

14. JamesWolf

if you cant use your calculator go here http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

15. JamesWolf

copy this formula ((x^5)/4) + (x^2) - 4x its your one but arranged in a way this calc likes it

16. JamesWolf

and paste it after y1 = then press graph

17. iluvvyyhu

thanks!(:

18. JamesWolf

:)