## anonymous 3 years ago Can someone explain to me how i would solve this problem thanks <3 "Estimate graphically the local maximum and local minimum of f(x)=((1/4)x^5)+(x^2)-4x"?

1. anonymous

o-o i have a graphing calculator since the review worksheet said i needed one x.x but im not sure how to use it so ya... fail x.x

2. anonymous

the local maximum is when the rate of change between x and y is 0|dw:1358379289305:dw|

3. anonymous

the rate of change between x and y is found by taking the derivative

4. anonymous

then you can find where the maximum and minimum are by solving $\frac{ dy }{ dx } = 0$

5. anonymous

im sorry but im still confused x.x what would i plug into that formula? ^-^;

6. anonymous

Do you know how to find the derivative of the formula in the question?

7. anonymous

no :(

8. anonymous

is this homework? what topic are you doing at the moment?

9. anonymous

its a segment review for my exam x.x and its pre-calc

10. anonymous

i switched schools so some of the stuff i dont know x.x

11. anonymous

yeah your going to need to put the function into your graph and just see where the maximum and minimum are, and guess

12. anonymous

have a look on google for an instruction book for your calc

13. anonymous

okay:/ thanks though <3

14. anonymous

if you cant use your calculator go here http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

15. anonymous

copy this formula ((x^5)/4) + (x^2) - 4x its your one but arranged in a way this calc likes it

16. anonymous

and paste it after y1 = then press graph

17. anonymous

thanks!(:

18. anonymous

:)