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iluvvyyhu
Can someone explain to me how i would solve this problem thanks <3 "Estimate graphically the local maximum and local minimum of f(x)=((1/4)x^5)+(x^2)-4x"?
o-o i have a graphing calculator since the review worksheet said i needed one x.x but im not sure how to use it so ya... fail x.x
the local maximum is when the rate of change between x and y is 0|dw:1358379289305:dw|
the rate of change between x and y is found by taking the derivative
then you can find where the maximum and minimum are by solving \[\frac{ dy }{ dx } = 0\]
im sorry but im still confused x.x what would i plug into that formula? ^-^;
Do you know how to find the derivative of the formula in the question?
is this homework? what topic are you doing at the moment?
its a segment review for my exam x.x and its pre-calc
i switched schools so some of the stuff i dont know x.x
yeah your going to need to put the function into your graph and just see where the maximum and minimum are, and guess
have a look on google for an instruction book for your calc
okay:/ thanks though <3
if you cant use your calculator go here http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html
copy this formula ((x^5)/4) + (x^2) - 4x its your one but arranged in a way this calc likes it
and paste it after y1 = then press graph