## BigD;) 2 years ago Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for \$6.00 per pound and the milk chocolate fudge bar sells for \$4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to \$120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

1. BigD;)

SOMEONE HELP

2. millitarygirl96

3. JamesWolf

we need the "possible combinations"

4. juciystar234

I agree!

5. BigD;)

10 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars

6. juciystar234

Jk :P

7. BigD;)

thank you. <3

8. millitarygirl96

all you gotta do is plug the numbers into the equation which will give u the answer of C

9. BigD;)

youre wrong actually..

10. millitarygirl96

14 dark bars and 18 milk bars that's he correct answer

11. millitarygirl96

6(14)+4(18) DOES NOT = 120

12. millitarygirl96

the*

13. BigD;)

your right haha good job. sorry, and thanks