anonymous
  • anonymous
Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
SOMEONE HELP
anonymous
  • anonymous
what are the possible answers?
anonymous
  • anonymous
we need the "possible combinations"

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anonymous
  • anonymous
I agree!
anonymous
  • anonymous
10 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars
anonymous
  • anonymous
Jk :P
anonymous
  • anonymous
thank you. <3
anonymous
  • anonymous
all you gotta do is plug the numbers into the equation which will give u the answer of C
anonymous
  • anonymous
youre wrong actually..
anonymous
  • anonymous
14 dark bars and 18 milk bars that's he correct answer
anonymous
  • anonymous
6(14)+4(18) DOES NOT = 120
anonymous
  • anonymous
the*
anonymous
  • anonymous
your right haha good job. sorry, and thanks

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