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- anonymous

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

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- anonymous

- jamiebookeater

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- anonymous

SOMEONE HELP

- anonymous

what are the possible answers?

- anonymous

we need the "possible combinations"

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- anonymous

I agree!

- anonymous

10 dark bars and 15 milk bars
12 dark bars and 12 milk bars
14 dark bars and 18 milk bars
6 dark bars and 21 milk bars

- anonymous

Jk :P

- anonymous

thank you. <3

- anonymous

all you gotta do is plug the numbers into the equation which will give u the answer of C

- anonymous

youre wrong actually..

- anonymous

14 dark bars and 18 milk bars
that's he correct answer

- anonymous

6(14)+4(18) DOES NOT = 120

- anonymous

the*

- anonymous

your right haha good job. sorry, and thanks

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