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BigD;)

  • 3 years ago

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

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  1. BigD;)
    • 3 years ago
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    SOMEONE HELP

  2. millitarygirl96
    • 3 years ago
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    what are the possible answers?

  3. JamesWolf
    • 3 years ago
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    we need the "possible combinations"

  4. juciystar234
    • 3 years ago
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    I agree!

  5. BigD;)
    • 3 years ago
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    10 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars

  6. juciystar234
    • 3 years ago
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    Jk :P

  7. BigD;)
    • 3 years ago
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    thank you. <3

  8. millitarygirl96
    • 3 years ago
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    all you gotta do is plug the numbers into the equation which will give u the answer of C

  9. BigD;)
    • 3 years ago
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    youre wrong actually..

  10. millitarygirl96
    • 3 years ago
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    14 dark bars and 18 milk bars that's he correct answer

  11. millitarygirl96
    • 3 years ago
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    6(14)+4(18) DOES NOT = 120

  12. millitarygirl96
    • 3 years ago
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    the*

  13. BigD;)
    • 3 years ago
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    your right haha good job. sorry, and thanks

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