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BigD;)
 3 years ago
Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
BigD;)
 3 years ago
Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

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millitarygirl96
 3 years ago
Best ResponseYou've already chosen the best response.0what are the possible answers?

JamesWolf
 3 years ago
Best ResponseYou've already chosen the best response.0we need the "possible combinations"

BigD;)
 3 years ago
Best ResponseYou've already chosen the best response.110 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars

millitarygirl96
 3 years ago
Best ResponseYou've already chosen the best response.0all you gotta do is plug the numbers into the equation which will give u the answer of C

millitarygirl96
 3 years ago
Best ResponseYou've already chosen the best response.014 dark bars and 18 milk bars that's he correct answer

millitarygirl96
 3 years ago
Best ResponseYou've already chosen the best response.06(14)+4(18) DOES NOT = 120

BigD;)
 3 years ago
Best ResponseYou've already chosen the best response.1your right haha good job. sorry, and thanks
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