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Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
 one year ago
 one year ago
Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
 one year ago
 one year ago

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millitarygirl96Best ResponseYou've already chosen the best response.0
what are the possible answers?
 one year ago

JamesWolfBest ResponseYou've already chosen the best response.0
we need the "possible combinations"
 one year ago

BigD;)Best ResponseYou've already chosen the best response.1
10 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars
 one year ago

millitarygirl96Best ResponseYou've already chosen the best response.0
all you gotta do is plug the numbers into the equation which will give u the answer of C
 one year ago

millitarygirl96Best ResponseYou've already chosen the best response.0
14 dark bars and 18 milk bars that's he correct answer
 one year ago

millitarygirl96Best ResponseYou've already chosen the best response.0
6(14)+4(18) DOES NOT = 120
 one year ago

BigD;)Best ResponseYou've already chosen the best response.1
your right haha good job. sorry, and thanks
 one year ago
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