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Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?
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SOMEONE HELP
millitarygirl96
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what are the possible answers?
JamesWolf
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we need the "possible combinations"
juciystar234
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I agree!
BigD;)
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10 dark bars and 15 milk bars
12 dark bars and 12 milk bars
14 dark bars and 18 milk bars
6 dark bars and 21 milk bars
juciystar234
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Jk :P
BigD;)
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thank you. <3
millitarygirl96
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all you gotta do is plug the numbers into the equation which will give u the answer of C
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youre wrong actually..
millitarygirl96
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14 dark bars and 18 milk bars
that's he correct answer
millitarygirl96
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6(14)+4(18) DOES NOT = 120
millitarygirl96
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the*
BigD;)
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your right haha good job. sorry, and thanks