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ValentinaT

  • 3 years ago

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  1. ValentinaT
    • 3 years ago
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  2. JamesWolf
    • 3 years ago
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    so for the first triangle perimeter, p1, is ; p1 = 2y + x = 14 for the second triangle perimeter, p2, is; p2 = (5/4)y + (5/4) y + 3x = 21 p2 = (5/2)y + 3x so you need to solve the simultaneous equations 2y + x = 14 (5/2)y + 3x

  3. JamesWolf
    • 3 years ago
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    the bottom one should be (5/2)y + 3x = 21

  4. ValentinaT
    • 3 years ago
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    Okay, how would I solve those?

  5. JamesWolf
    • 3 years ago
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    you need to get just one variable in an equation first. So i would eliminate the x's by multiplying the top equation by 3. Now both equations have "3x" and you can subtract the top equation from the bottom to get a formula with just y's.

  6. ValentinaT
    • 3 years ago
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    Okay.

  7. JamesWolf
    • 3 years ago
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    then you can solve that to find the value of y, plug it back in the original equation and you can find out x

  8. ValentinaT
    • 3 years ago
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    Thanks.

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