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swiftskier96
Group Title
43. What is the solution of the system of equations?
2x + 2y + 3z = 6
3x + 5y + 4z = 3
2x + 3y + 4z = 10
 one year ago
 one year ago
swiftskier96 Group Title
43. What is the solution of the system of equations? 2x + 2y + 3z = 6 3x + 5y + 4z = 3 2x + 3y + 4z = 10
 one year ago
 one year ago

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swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
@phi I forgot how to do this. Can you help?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
@ghazi
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
elimination is the technique
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
are you allowed a calculator?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Yeah i have one.
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
then the best way is just "brute force" write down just the numbers keeping the same order 2 2 3 6 3 5 4 3 2 3 4 10
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
the idea is we want the first column to have zeros below the first 2 (call 2 in 1st row, 1st col the pivot) (that means we will zero out the 3 and the 2 beneath it) to zero out the 3 in the 2nd row we do this: calculate 3/pivot (in other words, 3/2= 1.5) and save this number call the number the "factor" so I can talk about it. now for each number in the 2nd row: multiply the factor times the number in the 1st row, and add it to the number in the 2nd row. write down the answer Here is what I mean for the 2nd row the factor is 3/2. multiply 3/2 * 2 (the 1st number in row 1) and add it to 3 (1st # in row 2) we get 0 now multiply 3/2 * 2 (2nd # in 1st row) and add it to 5 (2nd # in 2nd row). we get 2 multiply 3/2 * 3 (3rd # in 1st row) and add it to 4 (3rd # in 2nd row). we get 0.5 finally, multiply 3/2 *6 and add it to 3 we get 9+3= 12 these numbers are our new 2nd row. So far we have 2 2 3 6 0 2 0.5 12 2 3 4 10
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
now we do the same thing for row 3. still use 2 in the first row as the pivot, calculate the factor for the bottom row: it is 2/pivot or 1 can you figure out what the bottom row becomes?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
So i take the first number on the bottom row (2) and multiply it by the factor (2/1)?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
This is complicated. The factor is the # we want to zero out (2 in the bottom) row divided by minus the pivot. the pivot is the first # in the 1st row. It is 2. pivot is 2. the factor is 2 (bottom row)/2 or 1 the factor is 1 Now multiply the factor times each number in the pivot row (1st row) and add to the number in the bottom row. Does that make sense?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Yeah that makes more sense. Ill figure it out here. One sec...
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
In the 3rd row we'd have 2 3 4 10.
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
you multiplied the bottom row by the factor. what you want to do is multiply the pivot row by the factor then add that result to the bottom row you know you are on the right track if the first # in the answer is 0 so multiply the 1st row by 1 add these new numbers to the 3rd row. what do you get?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Ohhh ok. I got 0 1 1 4
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
yes, so now the numbers look like this 2 2 3 6 0 2 0.5 12 0 1 1 4 notice that the 1st column has zeros except to the 2. we now move to the 2nd row to its first nonzero and call that the pivot row 2 is the pivot row. its first not zero is the 2. 2 is the new pivot. we want to zero out the 1 in the 3rd row. Find the factor: #/pivot can you tell me the factor?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
So are you saying that i should take the 1 in the 3rd row and divide it by the pivot (2)?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
almost, the factor is the 1 in the 3rd row (it is the number just below the pivot) but divide by minus the pivot.
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Sorry, im confused. What does divide by minus the pivot mean? Are you saying that the pivot should be negative?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
I am saying when we want the factor (for the row we are working on) we take the number in the row (1 in this case) and divide by minus the pivot. (pivot is 2, minus the pivot is 2) the factor is going to be 1 / 2
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
Yes, the factor is 0.5 now multiply the factor times the pivot row add those numbers to the 3rd row. this will be the new 3rd row. what do you get ?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
So id do 0.5 * 0, 0.5 * 2, 0.5 * 0.5, and 0.5 * 12. That would be 0 1 0.25 6. Then i add those numbers to the 3rd row which would make the 3rd row 0 0 1.25 10
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Yesss! Lol
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
The numbers look like this 2 2 3 6 0 2 0.5 12 0 0 1.25 10 now remember we left out the variables. Let's look at just the bottom row and put back the variables: 0x + 0y + 1.25z = 10 0 times x and 0 times y are both 0 so what we really have is 1.25z= 10 can you solve for z ?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Yesh i can! 1.25z/1.25 = 10/1.25 z = 8
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
what we are doing is called "back substitution". We work backwards (or upwards) the 2nd row is 0 2 0.5 12 with variables (and leaving out the 0) 2y 0.5*z = 12 The first thing to do is replace z with its value 8 2y 0.5* 8 =12 can you solve for y ?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
0.5 * 8 = 4 So would it be 2y  4 = 12 or 2y + 4 = 12?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
if you get confused about signs, don't use subtraction. I think 32 as 3 + 2 (three plus a minus 2) so the equation 2y 0.5* 8 =12 I think of as 2y + (0.5* 8) =12
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
I really should have written as 2y + 0.5z = 12 in the first place
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Ok. So it would be 2y + 4 = 12 2y + 4  4 = 12  4 2y = 8 2y/2 = 8/2 y = 4
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
yes. Do you want to tackle the first row ?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Sure, ill try. The first row is 2 2 3 6. So it would be 2x + (2 + 3) = 6 right?
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Or is it 2x + (2*3) = 6?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
don't skip steps. Put back in the variables y and z
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
remember each row has the variables, we just left them out because we don't calculate with them until this last "back substitution"
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Oh right. So 2 2 3 6 becomes 2x + 2(4) + 3(8) = 6?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
yes, but I would write it as 2x + 2y + 3z = 6 first, then write it as 2x + 2(4) + 3(8) = 6 (until I did a few more problems).
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
Just to help remember what is going on
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Ok. So that would look like 2x + 8 + (24) = 6 2x + (16) = 6 2x + (16)  (16) = 6  (16) 2x = 10 2x/2 = 10/2 x = 5
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
Yes, so that is the answer: x=5, y=4, z=8 A bit painful, but 3 equations and 3 unknowns are painful when you do them by hand. If you have the energy,see if you can redo the first column on your own. I gave the steps, but it may have been as clear as mud the first time through.
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Ok. Will do. Thanks for all the help! That was a really hard question to go through!
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.1
The good news is this technique works for any size, 2 x 2 upto big x big (where big is as many numbers as you want to think about). These days computers solve 1,000,000 by 1,000,000 or even bigger....
 one year ago

swiftskier96 Group TitleBest ResponseYou've already chosen the best response.1
Man... That would take a really long time to solve... O_O
 one year ago
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