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you sort of need the graphs?
I know.. i have one
Can you post a picture of the graph then I can try to help?
yes. one sec! :)
Just take some points on the graph and substitute them in the equation. Whatever equations satisfy the point are your equations
satisfy the point in the sense which give 0 on substitution of x and y co-ordinates in the place of x and y
oh wait! its right there
they both intersect at (2,3) so if we substitute these equations in the above equations none satisfy so none of the equations match the graph
hmm.... thats not one of the answers?
Well, I'm confused then..
The point of intersection is (3,2) not (2,3)
yeah sorry I'm wrong
in that case the last set is your answer try substituting 2 and 3 in the place of x and y
So, would this be the answer? x – 3y = –9 2x – 3y = 0
no x+3y=9 (3+3*2=9) and 2x-3y=o (2*3-3*2=0)
ahh. i was going to chose that one