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which is expression is equivalent to

Mathematics
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if \[\sqrt{x-a}=b, x>a \]
which expression is equivalent to x? \[b^{2}-a \]
\[b-a\]

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Other answers:

b+a
or b^2+a
\[\sqrt{x-a}=b\]=>\[x-a=b^2\]=>\[x=b^2+a\]
When solving with radicals, square both sides because \[(\sqrt{x})^2=x\]
It will just get rid of it :)!!
so b^2+ a is the answer?
yes
how did you know x=> ?
Did you understand the first step? that x-a = b^2 ?
no i dont
|dw:1358391793350:dw|
Ok. Do you understand why \[(\sqrt{x})^2=x\]?
The "x > a" is just imposing a restriction value on your x. You don't need to use it to solve for x
where did you get the square from?
It's what you need to do in order to solve the equation. It's similar to like when you have an equation like: \[2x-4=10\]\[2x=10+4\]\[2x=14\]\[\frac{2x}{2}=\frac{14}{2}\]\[x=7\] You could argue "how did you get the divided by 2 part?" Well it's similar to your situation. You introduce this exponent to get rid of your square root, just like you introduced a divided by 2 up here^ to isolate your x
ohh ok
thanks so much :)
No problem :)
can you help me with another problem?
SUre
yea?
i thought you left
I can help your with your question if you need
you*

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