anonymous
  • anonymous
which is expression is equivalent to
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
if \[\sqrt{x-a}=b, x>a \]
anonymous
  • anonymous
which expression is equivalent to x? \[b^{2}-a \]
anonymous
  • anonymous
\[b-a\]

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More answers

anonymous
  • anonymous
b+a
anonymous
  • anonymous
or b^2+a
kirbykirby
  • kirbykirby
\[\sqrt{x-a}=b\]=>\[x-a=b^2\]=>\[x=b^2+a\]
kirbykirby
  • kirbykirby
When solving with radicals, square both sides because \[(\sqrt{x})^2=x\]
kirbykirby
  • kirbykirby
It will just get rid of it :)!!
anonymous
  • anonymous
so b^2+ a is the answer?
kirbykirby
  • kirbykirby
yes
anonymous
  • anonymous
how did you know x=> ?
kirbykirby
  • kirbykirby
Did you understand the first step? that x-a = b^2 ?
anonymous
  • anonymous
no i dont
anonymous
  • anonymous
|dw:1358391793350:dw|
kirbykirby
  • kirbykirby
Ok. Do you understand why \[(\sqrt{x})^2=x\]?
kirbykirby
  • kirbykirby
The "x > a" is just imposing a restriction value on your x. You don't need to use it to solve for x
anonymous
  • anonymous
where did you get the square from?
kirbykirby
  • kirbykirby
It's what you need to do in order to solve the equation. It's similar to like when you have an equation like: \[2x-4=10\]\[2x=10+4\]\[2x=14\]\[\frac{2x}{2}=\frac{14}{2}\]\[x=7\] You could argue "how did you get the divided by 2 part?" Well it's similar to your situation. You introduce this exponent to get rid of your square root, just like you introduced a divided by 2 up here^ to isolate your x
anonymous
  • anonymous
ohh ok
anonymous
  • anonymous
thanks so much :)
kirbykirby
  • kirbykirby
No problem :)
anonymous
  • anonymous
can you help me with another problem?
kirbykirby
  • kirbykirby
SUre
kirbykirby
  • kirbykirby
@ligia587
anonymous
  • anonymous
yea?
anonymous
  • anonymous
i thought you left
kirbykirby
  • kirbykirby
I can help your with your question if you need
kirbykirby
  • kirbykirby
you*

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