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 2 years ago
Electric field strength is defined: “force per unit positive charge on a small test charge”.
Why is it necessary for the test charge to be small?
 2 years ago
Electric field strength is defined: “force per unit positive charge on a small test charge”. Why is it necessary for the test charge to be small?

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Krishnadas
 2 years ago
Best ResponseYou've already chosen the best response.0Because if the test charge was too large,the effect by the test charge on source charge will be high.So there is a chance that the source charge will tend to move.

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.0who said the test charge is small???? +1C charge is very big charge missy!.. we consider a UNIT charge.. something that has a magnitude one in their respective units.. in SI that unit turns out to be a COULOMB.. and what krishnadas said is rubbish :P.. we need to define field at a point in some way.. so we need a reference.. its easy to remember 1C than remembering a mili coulomb or a micro coulomb.. !!..

Carl_Pham
 2 years ago
Best ResponseYou've already chosen the best response.0The test charge generates its own electric field, which adds (vectorially) to the field you're trying to measure. The force on the test charge is the result of the sum of the fields. The only way you can disentangle the result of the field you're trying to measure is to make measurements as you reduce the size of the test charge, and extrapolate the result to charge > 0. That's the process described, in a shorthand way, by saying you use a small test charge. It means you take the q>0 limit.

gleem
 2 years ago
Best ResponseYou've already chosen the best response.0Mashy is correct, the size of the test charge is irrelevant. The idea is to determine the electric field by determining the force that it exerts on the test charge as given by Coulombs's Law. Beside the field of the test charge no matter how small is infinite at that point and would essentially wipe out the field from the other charge making the measurement impossible. the electric fields do not interact. The charges interact with the others field.

gleem
 2 years ago
Best ResponseYou've already chosen the best response.0Question. From a practical point of view if the source charge is distributed and mobile say on a large conducting sphere and the test charge where large enough or close enough could cause a redistribution of the charge on the sphere thus altering the original electric field ?

Mashy
 2 years ago
Best ResponseYou've already chosen the best response.0Test charge is JUST A CONCEPT.. you don't really have to PUT a charge their.. its like WHAT IF there was a charge there.. and WHAT IF it had no effect.. on the SOURCE.. well obviously in reality the source is affected. but when i wanna describe field due to just one charge.. (source).. thats the only way to describe it..
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